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How many grams of rm NH 3 can be produced from 2.90 mol of rm N 2?
To calculate the amount of NH3 that can be produced, we need to use the balanced chemical equation for the reaction between N2 and H2 to form NH3. The balanced equation is: N2 + 3H2 -> 2NH3. From the equation, we can see that 1 mole of N2 produces 2 moles of NH3. Therefore, if 2.90 mol of N2 is used, it will produce 2.90 mol * (2 mol NH3/1 mol N2) = 5.80 mol of NH3. To convert this to grams, we need to multiply the number of moles of NH3 by its molar mass, which is 17 g/mol. Therefore, the amount of NH3 produced from 2.90 mol of N2 is 5.80 mol * 17 g/mol = 98.6 g of NH3.
How many atoms are there in 0.850 mol of ammonia?
There are 6.02 x 1023 NH3 molecules in 1 mole of NH3.Therefore 0.850mol of ammonia would have 0.85 x 6.02 x 1023 molecules of NH3.In each NH3 molecule there are 4 atoms (one N and three H atoms).Therefore the number of atoms in 0.850mol of NH3 is4 x 0.85 x 6.02 x 1023 = 2.05 x 1024
How many Molecules are contained in 0.900 mol O2?
There are (5.41 \times 10^{23}) molecules of (O_2) in 0.900 moles.
How many molecules are there in 1.00 mol of H2O2?
There are 6.022x10^23 molecules in 1.00 mol of anything.
How many molecules of ammonia are contained in 10 moles of ammonia NH3?
1 mol of any substance contains 6.02 x 1023 constituent particles. This is the avogadro constant. So in 10 moles of NH3, there would be 10 x 6.02 x 1023 = 6.02 x 1024 NH3 molecules.
How many molecules are in 75g of N2O3?
1 mole N2O3 = 76.0116g N2O3 (atomic weights x subscripts) 1 mole N2O3 = 6.022 x 1023 molecules N2O3 75g N2O3 x (1mol N2O3/76.0116g N2O3) = 0.99mol N2O3 0.99mol N2O3 x (6.022 x 1023 molecules N2O3/1mol N2O3) = 6.0 x 1023 molecules N2O3
What is the bond energy of nh3?
The bond energy of NH3, which is the energy required to break one mole of NH3 molecules into its individual atoms, is approximately 391 kJ/mol.
How many moles of NH3 are produced when 1.2 mol of H2 reacts?
The balanced chemical equation for the reaction between H2 and NH3 is: 3H2 + N2 → 2NH3 From the equation, we can see that 3 moles of H2 produce 2 moles of NH3. Therefore, when 1.2 moles of H2 react, we can calculate the moles of NH3 produced as: 1.2 mol H2 * (2 mol NH3 / 3 mol H2) = 0.8 mol NH3.
How many molecules are in 0.0650 mol NH3?
The number of molecules is 0,391439155705.10e23.
How many grams of NH3 can be produced from 4.46 mol of N2 and excess H2.?
The molecular weight of NH3 is 17.03-grams per mole and 14.01 for N2. The reaction is N2 + 3H2 = NH3. Therefore for every 1-mole of N2 as a reactant 1-mole of NH3 is produced. .2941-moles of NH3 is produced with a mass of 5.01-grams.
How many grams of NH3 can be produced from 3.38 mol of N2 and excess H2.?
The balanced chemical equation for the reaction is: N2 + 3H2 -> 2NH3 From the equation, it can be seen that 1 mol of N2 produces 2 mol of NH3. Therefore, 3.38 mol of N2 will produce 2 x 3.38 = 6.76 mol of NH3. To convert this to grams, you need to multiply the molar mass of NH3 (17.03 g/mol) by the number of moles of NH3 produced. Thus, 6.76 mol of NH3 will produce 6.76 x 17.03 = 115.18 g of NH3.
How many grams of NH3 can be produced from 2.23 mol of N2 and excess H2.?
By balancing the chemical equation for the reaction N2 + 3H2 -> 2NH3, we can see that 1 mol of N2 produces 2 mol of NH3. Therefore, 2.23 mol of N2 will produce 2.23 x 2 = 4.46 mol of NH3. Since the molar mass of NH3 is approximately 17 g/mol, 4.46 mol of NH3 is equivalent to 4.46 x 17 = 75.82 grams of NH3.
How many grams of NH3 can be produced from 4.33 mol of N2 and excess H2. Express your answer numerically in grams.?
4.33 mol of N2 will produce twice as many moles of NH3 since the balanced chemical equation is N2 + 3H2 -> 2NH3. Therefore, 4.33 mol of N2 will produce 8.66 mol of NH3. To convert this to grams, use the molar mass of NH3 (17.03 g/mol) to find that 8.66 mol is equal to 147.43 grams of NH3.
Number of N atoms in 0.410 mol NH3?
I actually have this problem in my chemistry book too. This is what is given in the "Solutions to Red Exercises" book that went along with the text: Analyze. Given: mol NH3, Find: N atoms Plan. mol NH3---> mol N atoms---> N atoms Solve. 0.410 mol NH3 * 1 mol N atoms/ 1 mol NH3 * 6.022*10^23 atoms/1mol = 2.47*10^23 N atoms Check. (0.4)(6*10^23)=2.4*10^23. I hope this helps.
What is the mass of 1.75 1024 molecules of NH3?
To find the mass of 1.75 x 10^24 molecules of NH3, you would first calculate the molar mass of NH3 (17.03 g/mol). Then, you would convert the number of molecules to moles by dividing by Avogadro's number (6.022 x 10^23 molecules/mol). Finally, multiply the number of moles by the molar mass to find the mass.
How many grams of NH3 can be produced from 2.22 mol of N2 and excess H2.?
To determine the mass of NH3 produced from 2.22 mol of N2, we use the balanced equation for the synthesis of ammonia: N2 + 3H2 → 2NH3. From the equation, 1 mole of N2 produces 2 moles of NH3. Therefore, 2.22 mol of N2 will yield 2 × 2.22 = 4.44 mol of NH3. The molar mass of NH3 is approximately 17.03 g/mol, so the mass produced is 4.44 mol × 17.03 g/mol = 75.7 grams of NH3.
How many grams of NH3 will have the same number of molecules at 15.0 g of C6H6?
You first need to find the mass weight of NH3. wt. of N + (wt. of H)= 14.0067 + 3(1.0067)= 17.03052 Now that you have the mass weight, you divide 15 into 17.03052... 15.0/17.03052 = 0.8807 moles in 15. g of NH3
