1 mol of any substance contains 6.02 x 1023 constituent particles. This is the avogadro constant. So in 10 moles of NH3, there would be 10 x 6.02 x 1023 = 6.02 x 1024 NH3 molecules.
There are (5.41 \times 10^{23}) molecules of (O_2) in 0.900 moles.
By balancing the chemical equation for the formation of ammonia (NH3) from nitrogen gas (N2) and hydrogen gas (H2), we have: N2 + 3H2 → 2NH3 This means that for every 1 molecule of N2 and 3 molecules of H2, we get 2 molecules of NH3. Therefore, from 2 molecules of N2 and 6 molecules of H2, we can form 4 molecules of NH3.
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
The reaction of nitrogen with hydrogen to form ammonia is: N2 +3H2 = 2NH3 Therefore to make 10 moles of ammonia you need 5 moles N2 and 15 moles H2
There are approximately 0.023 moles of ammonia in 1 g of ammonia (NH3).
0,522 moles of ammonia contain 3,143.10e23 molecules of NH3.
There are (5.41 \times 10^{23}) molecules of (O_2) in 0.900 moles.
To find the number of molecules in 0.75 g of ammonia, we need to first calculate the number of moles using the molar mass of ammonia (17 g/mol). Then we can use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. In this case, the number of molecules in 0.75 g of ammonia would be approximately 1.26 x 10^22 molecules.
Since ammonia has a chemical formula of NH3, it contains one mole of nitrogen and three moles of hydrogen per mole of ammonia. Therefore, 3 moles of ammonia contain 3 moles of nitrogen and 9 moles of hydrogen atoms.
this is a easy one. There are only 0.04166 moles.
To produce 525 grams of ammonia (NH3), you would need 25 moles of ammonia. Since the balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is 3H2 + N2 -> 2NH3, you would need 75 moles of hydrogen molecules (H2) to produce 525 grams of ammonia. This is equivalent to 4,500 molecules of hydrogen.
To find the number of moles in 170000 grams of ammonia, you need to divide the given mass by the molar mass of ammonia. The molar mass of ammonia (NH3) is about 17 grams/mol. Therefore, 170000g ÷ 17g/mol ≈ 10000 moles of ammonia.
7.95 X 1022 molecules NH3 (1 mole NH3/6.022 X 1023) = 0.132 moles ammonia =================
By balancing the chemical equation for the formation of ammonia (NH3) from nitrogen gas (N2) and hydrogen gas (H2), we have: N2 + 3H2 → 2NH3 This means that for every 1 molecule of N2 and 3 molecules of H2, we get 2 molecules of NH3. Therefore, from 2 molecules of N2 and 6 molecules of H2, we can form 4 molecules of NH3.
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
The number of molecules is 7,52767607125.10e23.
To convert from molecules to moles, divide the number of molecules by Avogadro's number (6.022 x 10^23). So, for 5.01020 molecules of carbon, the number of moles of carbon would be approximately 8.33 x 10^-3 moles.