This is a chemical calculation. there are 0.04166 moles in it.
There are 200 grams of ammonia in 200 grams of ammonia.
Ammonia = NH3 and has a molar mass of 17.031 g/molmoles NH3 = 63.9 g x 1 mol/17.031 g = 3.752 molesmolecules NH3 = 3.752 moles x 6.02x10^23 molecules/mole = 2.259x10^24 moleculesEach molecule of NH3 has 4 atoms (1 N + 3 H), thus....number of atoms = 4 atoms/molecule x 2.259x10^24 molecules = 9.04x10^24 atoms (to 3 sig figs)
To find the mass in grams of 1.20x10^25 molecules of ammonia (NH3), you first calculate the molar mass of NH3 (17.031 g/mol). Then, divide the given number of molecules by Avogadro's number (6.022x10^23 molecules/mol) to find the number of moles, and finally, multiply the number of moles by the molar mass to get the mass in grams, which will be approximately 4.08x10^2 grams.
To find the number of moles in 0.75 g of ammonia (NH3), you first need to calculate the molar mass of ammonia (NH3) which is approximately 17 g/mol. Then divide the given mass (0.75 g) by the molar mass to get the number of moles. In this case, 0.75 g of ammonia is equivalent to about 0.044 moles.
Ammonia sulfide is (NH4)2SO4. And the molar mass is 116 g mol-1.
The mass of 3 mol of ammonia is 51,093 g; the number of ammonia molecules in 3 moles is18,066422571.10e23.
This value is 21,85 g.
The mass of 5 mol of ammonia is 85,155 g; the number of ammonia molecules in 5 moles is3,011 070 428 5.10e24.
Assuming that this ammonia gas is at STP, you can use Avogadro's number to gind the number of moles of gas:(387 x 1021 molecules) x (1 mol / 6.02x1023particles) x (17.03 g / 1 mol) =110 g NH3
Gram mole is the mass of a substance which equal to molecular mass in amu. For ammonia we have one nitrogen atom and three atoms of hydrogen. So the molecular mass in amu will be 14+3 = 17 Now 17 g of ammonia would have 6.023 x 1023 molecules. ie avagadro number of molecules. Hence every 1 g will have (6.023/17) x 1023 So for 32 g it would have (32/17) x 6.023 x 1023 molecules.
6.022 x 1023 molecules. One mole of any substance has the same i.e. 6.022 x 1023 of its constituents particles.
There are 200 grams of ammonia in 200 grams of ammonia.
chicken
1 g of ammonia (NH3) is equal to 0,059 mol.
Ammonia = NH3 and has a molar mass of 17.031 g/molmoles NH3 = 63.9 g x 1 mol/17.031 g = 3.752 molesmolecules NH3 = 3.752 moles x 6.02x10^23 molecules/mole = 2.259x10^24 moleculesEach molecule of NH3 has 4 atoms (1 N + 3 H), thus....number of atoms = 4 atoms/molecule x 2.259x10^24 molecules = 9.04x10^24 atoms (to 3 sig figs)
75 mg = .075 g.
There are approximately 0.023 moles of ammonia in 1 g of ammonia (NH3).