Gram mole is the mass of a substance which equal to molecular mass in amu. For ammonia we have one nitrogen atom and three atoms of hydrogen. So the molecular mass in amu will be 14+3 = 17
Now 17 g of ammonia would have 6.023 x 1023 molecules. ie avagadro number of molecules.
Hence every 1 g will have (6.023/17) x 1023
So for 32 g it would have (32/17) x 6.023 x 1023 molecules.
0,522 moles of ammonia contain 3,143.10e23 molecules of NH3.
There are 6.02x10^23 molecules in one mole of anything.
One mole=1000 Milli moles One mole=6.022 x 1023 molecules of the substance Therefore, one Milli mole of ammonia has 6.022 x 1023 /103 = 6.022 x 1020 molecules of ammonia.
Each molecule of ammonia has three hydrogen atoms; therefore, 26 molecules of ammonia contain 26 X 3 = 78. However, these hydrogen atoms do not constitute hydrogen molecules, so the literally correct answer is zero.
Ammonia has the chemical formula NH3, and thus there are three hydrogen atoms in a molecule of ammonia.
Ammonia has one nitrogen atom and three hydrogen atoms, so there are a total of 4 atoms in a molecule of ammonia.
To find the number of molecules in 0.75 g of ammonia, we need to first calculate the number of moles using the molar mass of ammonia (17 g/mol). Then we can use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. In this case, the number of molecules in 0.75 g of ammonia would be approximately 1.26 x 10^22 molecules.
1 g of ammonia (NH3) is equal to 0,059 mol.
To produce 525 grams of ammonia (NH3), you would need 25 moles of ammonia. Since the balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is 3H2 + N2 -> 2NH3, you would need 75 moles of hydrogen molecules (H2) to produce 525 grams of ammonia. This is equivalent to 4,500 molecules of hydrogen.
There are approximately 0.023 moles of ammonia in 1 g of ammonia (NH3).
One molecule of ammonia is composed of one nitrogen atom and three hydrogen atoms (chemical formula NH3).
The answer is 0,166.10e23 molecules.