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Assuming that this ammonia gas is at STP, you can use Avogadro's number to gind the number of moles of gas:

(387 x 1021 molecules) x (1 mol / 6.02x1023particles) x (17.03 g / 1 mol) =110 g NH3

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How many hydrogen molecules are needed to produce 525 grams of ammonia?

To produce 525 grams of ammonia (NH3), you would need 25 moles of ammonia. Since the balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is 3H2 + N2 -> 2NH3, you would need 75 moles of hydrogen molecules (H2) to produce 525 grams of ammonia. This is equivalent to 4,500 molecules of hydrogen.


How many grams are there in 200 g of ammonia?

There are 200 grams of ammonia in 200 grams of ammonia.


How many grams does 7.74 x 1025 molecules of ammonia (NH3) represent?

This value is 21,85 g.


How many ammonia molecules are in a mole of ammonia?

There are 6.02x10^23 molecules in one mole of anything.


How many grams of ammonia NH3 will produce 300 grams of N2?

394.794 grams


How many molecules of ammonia NH3 are present in 0.522 moles of ammonia?

0,522 moles of ammonia contain 3,143.10e23 molecules of NH3.


How many moles of ammonia is 170000grams?

To find the number of moles in 170000 grams of ammonia, you need to divide the given mass by the molar mass of ammonia. The molar mass of ammonia (NH3) is about 17 grams/mol. Therefore, 170000g ÷ 17g/mol ≈ 10000 moles of ammonia.


The mass of 3 moles of ammonia would be how many grams?

3 moles of ammonia is 51grams. One mole is 17 grams.


The formula for ammonia is NH3 the mass of 3 moles of ammonia would be how many grams?

The molar mass of ammonia is about 17 grams, so that 3 moles would have a mass of 51 grams.


How many grams of ammonia contain 1.80 x 1025 atoms of hydrogen?

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If you have 3 64 grams of H2 how many grams of NH3 can be produced?

The answer is 20,664 g ammonia.


How many moles are in 1200 grams of ammonia?

To find the number of moles in 1200 grams of ammonia, divide the given mass by the molar mass of ammonia. The molar mass of ammonia (NH3) is approximately 17 grams/mole. Therefore, 1200 grams divided by 17 grams/mole equals approximately 70.59 moles of ammonia.