7,02 g ammonia
Molar mass of ammonia is 17.031 whereas molar mass of hydrogen chloride (or hydrochloric acid) is 36.461. Hence if given masses, there is 1 mole ammonia and 2 moles HCl. Hence there is more number of hydrogen chloride.
1,25 grams of CH4 contain 0,156696.10e23 atoms.
In ammonia (NH3), there are three hydrogen atoms for every molecule. The molar mass of ammonia is 17 grams per mole. To find the mass of hydrogen in 150 grams of ammonia, you can calculate as follows: 150 g x (3 g H2 / 17 g NH3) = 26.47 g of hydrogen.
Since the molar mass of ammonia (NH3) is 17 g/mol and it contains 3 hydrogen atoms per molecule, the molar mass of hydrogen in ammonia is 3 g/mol. Therefore, in 150g of ammonia, there are (3/17) * 150 = 26.47g of hydrogen.
45,0 grams of hydrogen gas have 135,5.10e23 atoms.
To determine the amount of hydrogen in 150 g of ammonia (NH3), we first need to calculate the molar mass of ammonia. The molar mass of NH3 is approximately 17 g/mol (1 nitrogen atom with a molar mass of 14 g/mol and 3 hydrogen atoms with a molar mass of 1 g/mol each). Next, we find the molar ratio of hydrogen to ammonia, which is 3:1. Therefore, in 150 g of ammonia, there are approximately 33.53 grams of hydrogen (150 g / 17 g/mol * 3 mol H2 / 1 mol NH3).
To form ammonia (NH3) from nitrogen (N2) and hydrogen (H2), the balanced chemical equation is N2 + 3H2 → 2NH3. This means that for every mole of nitrogen, 3 moles of hydrogen are required. Given that nitrogen is limiting in this case, all 70 grams of nitrogen will react with 210 grams (3 times 70) of hydrogen to form 70 grams of ammonia. This reaction will consume all the hydrogen, leaving no grams of hydrogen leftover.
Ammonia is composed of one nitrogen atom and three hydrogen atoms. The molar mass of ammonia is 17.03 g/mol, with 3.04 g/mol from the hydrogen atoms. To find the grams of hydrogen in 10.0 g of ammonia, we need to calculate the proportion of hydrogen in the compound. This comes out to 3.04 g H x (10.0 g NH3 / 17.03 g NH3) = 1.79 g H.
The reaction between hydrogen and ammonia to form ammonia is 3H2 + N2 → 2NH3. To find the amount of ammonia produced when 6.00g of hydrogen reacts, first convert the mass of hydrogen to moles using its molar mass. Then, use the mole ratio from the balanced equation to find the moles of ammonia produced, and finally, convert this to grams using the molar mass of ammonia.
To produce 525 grams of ammonia (NH3), you would need 25 moles of ammonia. Since the balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is 3H2 + N2 -> 2NH3, you would need 75 moles of hydrogen molecules (H2) to produce 525 grams of ammonia. This is equivalent to 4,500 molecules of hydrogen.
Onions do not naturally contain ammonia. They contain sulfur compounds that can produce a pungent smell and flavor when the onion is chopped or crushed, but this is different from the smell of ammonia.
To calculate the number of atoms in 170 grams of ammonia (NH3), you would first determine the number of moles using the molar mass of ammonia (17.03 g/mol). Then, using Avogadro's number (6.022 x 10^23 atoms/mol), you find that there are approximately 1.79 x 10^24 atoms in 170 grams of ammonia.