Amount of NH3 = 10.0/17.0 = 0.588mol
The ratio of H to NH3 is 3:1.
Amount of H = 3 x 0.588 = 1.76mol
Mass of H = 1.0 x 1.76 = 1.76g
The molar mass of ammonia (NH3) is 17.03 g/mol. Hydrogen's molar mass is 1.01 g/mol. The mass of hydrogen in ammonia is 3.03 g (3*1.01). To find the mass percentage of hydrogen in ammonia: (3.03 g / 17.03 g) * 100% ≈ 17.8%.
To find the percent yield, first calculate the theoretical yield of ammonia based on the given amounts of nitrogen and hydrogen. Then compare the actual yield (62g) with the theoretical yield to calculate the percent yield using the formula: (actual yield/theoretical yield) x 100%. The percent yield would be the actual mass of ammonia produced (62g) divided by the theoretical yield of ammonia.
lets see. H20 you have 2.016 grams of hydrogen here to 16.0 grams oxygen 2.016/16.0 X 100 = 12.6% hydrogen by mass H2O2 you have the same 2.016 grams hydrogen here, but you have 32.0 grams oxygen in this molecule 2.016/32.0 X 100 = 6.3% so H2O has the higher percent by mass of hydrogen
To determine the number of molecules in 100 grams of hydrogen chloride gas, you need to first calculate the number of moles present using its molar mass. The molar mass of HCl is about 36.5 g/mol. Then, you can use Avogadro's number (6.022 x 10^23) to convert moles to molecules.
100 micrograms is equal to 0.0001 grams.
For carbon 0.80 x 100 = 80 grams of carbon; and for hydrogen 0.20 x 100 = 20 grams of hydrogen
The molar mass of ammonia (NH3) is 17.03 g/mol. Hydrogen's molar mass is 1.01 g/mol. The mass of hydrogen in ammonia is 3.03 g (3*1.01). To find the mass percentage of hydrogen in ammonia: (3.03 g / 17.03 g) * 100% ≈ 17.8%.
For this you need the atomic (molecular) mass of NH3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. NH3=16.0 grams100 grams NH3 / (16.0 grams) = 6.25 moles NH3
To find the percent yield, first calculate the theoretical yield of ammonia based on the given amounts of nitrogen and hydrogen. Then compare the actual yield (62g) with the theoretical yield to calculate the percent yield using the formula: (actual yield/theoretical yield) x 100%. The percent yield would be the actual mass of ammonia produced (62g) divided by the theoretical yield of ammonia.
Onions do not naturally contain ammonia. They contain sulfur compounds that can produce a pungent smell and flavor when the onion is chopped or crushed, but this is different from the smell of ammonia.
100 grams = 3.5 ounces.
100 grams is 3.527 ounces.
For the reaction 2H₂ + O₂ → 2H₂O, we know that the molar ratio of H₂ to O₂ is 2:1. To produce 900 grams of water, we need 450 grams of hydrogen (900g / 2). Therefore, we need to add 450 grams of hydrogen to 800 grams of oxygen to produce 900 grams of water.
.1 Kg = 100 grams
To find the mass of water containing 5.0 grams of hydrogen, we need to set up a proportion using the mass percentage of hydrogen in water. Since water is 11.2% hydrogen by mass, we can calculate the mass of water using the formula: (5.0 grams of hydrogen) / (11.2 grams of hydrogen per 100 grams of water) = x grams of water. Converting grams to kilograms, the mass of water containing 5.0 grams of hydrogen would be 5.0 g / 11.2% = 44.64 g. This figure converted to kilograms is 0.04464 kg.
There are 1000 grams in a kilogram. One tenth of 1000 = 100 grams.
100 g = 3.527 oz