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3 moles of ammonia is 51grams. One mole is 17 grams.
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How many moles of ammonia is 170000g?
Ammonia = NH3Molecular mass = 16.0Formula of grams to moles: grams / molecular mass = moles170,000 g / (16.0) = 10,600 moles NH3Note that the answer is with three significant digits
How many moles are in 1200 grams of ammonia?
mol = mass/ Mr Mr = 14 + 3 = 17 mol = 1200/17 moles = 70.59
If you start with seventy grams of nitrogen and twenty grams of hydrogen how many grams of ammonia will be formed and how many grams of hydrogen are leftover?
there would be 50 grams of ammonia will be formed
100 grams of ammonia equals how many moles?
For this you need the atomic (molecular) mass of NH3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. NH3=16.0 grams100 grams NH3 / (16.0 grams) = 6.25 moles NH3
How many moles of ammonia are produced from 12.0 moles of hydrogen?
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
The formula for ammonia is NH3 the mass of 3 moles of ammonia would be how many grams?
The molar mass of ammonia is about 17 grams, so that 3 moles would have a mass of 51 grams.
How many moles of ammonia is 170000g?
Ammonia = NH3Molecular mass = 16.0Formula of grams to moles: grams / molecular mass = moles170,000 g / (16.0) = 10,600 moles NH3Note that the answer is with three significant digits
How many moles are in 12 x 10.3 grams of ammonia NH3?
Molar mass of ammonia is 17 g. Therefore in 12 x 10.3 g of ammonia there will be 7.27 moles of ammonia.
How many moles of ammonia are needed to produce 3.5 mole of nitrogen?
That amount of ammonia contains two moles of hydrogen gas. One mole of hydrogen gas weighs 2.016 grams. Therfore 3.75 grams of ammonia contains two moles of hydrogen.
How many moles of ammonia is 170000grams?
How many moles of ammonia is 170000grams?
How many grams of NH3 can be produced from 2.79 moles of N2?
The mass of ammonia will be 95,03 g.
How many moles of electrons are present in 17 grams of ammonia?
There are 10 electrons per molecule of NH3,17g of ammonia means one mole, therefore 10 moles of electrons are present.
How many moles are in 1.2 X 10.3 grams of ammonia NH2?
Ammonia is NH3 (not NH2) so its molar mass is 17 g/mol. In 1.2*10^3 g there are1.2*10^3(g) / 17 (g/mol) = (70.6 =) 71 mol NH3.
How many moles of which reactant will remain if 1.39 moles of N and 3.44 moles of H will react to form ammonia find out how many grams of ammonia can be formed and how many moles of limiting reactant?
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
How many moles are in 1200 grams of ammonia?
mol = mass/ Mr Mr = 14 + 3 = 17 mol = 1200/17 moles = 70.59
If you start with seventy grams of nitrogen and twenty grams of hydrogen how many grams of ammonia will be formed and how many grams of hydrogen are leftover?
there would be 50 grams of ammonia will be formed
100 grams of ammonia equals how many moles?
For this you need the atomic (molecular) mass of NH3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. NH3=16.0 grams100 grams NH3 / (16.0 grams) = 6.25 moles NH3
