Ammonia = NH3
Molecular mass = 16.0
Formula of grams to moles: grams / molecular mass = moles
170,000 g / (16.0) = 10,600 moles NH3
Note that the answer is with three significant digits
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
The reaction of nitrogen with hydrogen to form ammonia is: N2 +3H2 = 2NH3 Therefore to make 10 moles of ammonia you need 5 moles N2 and 15 moles H2
2N + 3H2 -> 2NH3 18 moles H2 (2 moles NH3/3 moles H2) = 12 mole ammonia
4NH3 + 3O2 -----> 2N2 + 6H2O 4 moles of ammonia react with 3 of oxygen. So 10 moles of ammonia requires 7.5 moles of oxygen.
3 moles of ammonia is 51grams. One mole is 17 grams.
How many moles of ammonia is 170000grams?
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
0,522 moles of ammonia contain 3,143.10e23 molecules of NH3.
8,038 moles of ammonia were produced.
this is a easy one. There are only 0.04166 moles.
The reaction of nitrogen with hydrogen to form ammonia is: N2 +3H2 = 2NH3 Therefore to make 10 moles of ammonia you need 5 moles N2 and 15 moles H2
2N + 3H2 -> 2NH3 18 moles H2 (2 moles NH3/3 moles H2) = 12 mole ammonia
4NH3 + 3O2 -----> 2N2 + 6H2O 4 moles of ammonia react with 3 of oxygen. So 10 moles of ammonia requires 7.5 moles of oxygen.
3 moles of ammonia is 51grams. One mole is 17 grams.
Molar mass of ammonia is 17 g. Therefore in 12 x 10.3 g of ammonia there will be 7.27 moles of ammonia.
6 moles COULD be produced
N2 + 3H2 ---> 2NH3 so 3 moles of Hydrogen produces 2 moles of ammonia. Thus 1.8 moles will produce 1.8/3 x 2 = 1.2 moles of ammonia.