Ammonia = NH3
Molecular mass = 16.0
Formula of grams to moles: grams / molecular mass = moles
170,000 g / (16.0) = 10,600 moles NH3
Note that the answer is with three significant digits
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โ 15y agoTo find the number of moles in 170000g of ammonia, you need to first calculate the molar mass of ammonia (NH3), which is approximately 17g/mol. Then, divide the given mass (170000g) by the molar mass to get the number of moles: 170000g / 17g/mol = 10000 moles of ammonia.
Ammonia is produced from the reaction of hydrogen and nitrogen in a 3:1 ratio. Therefore, 12.0 moles of hydrogen will produce 4.0 moles of ammonia.
For every mole of ammonia produced, we need one mole of nitrogen and three moles of hydrogen. Therefore, to produce 10 moles of ammonia, we would need: 10 moles of nitrogen 30 moles of hydrogen
There are approximately 0.023 moles of ammonia in 1 g of ammonia (NH3).
The balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is: 3H2 + N2 -> 2NH3 From the equation, it can be seen that 3 moles of hydrogen react to produce 2 moles of ammonia. Therefore, 18 moles of hydrogen can produce (2/3) x 18 = 12 moles of ammonia.
The molar mass of ammonia (NH3) is approximately 17 grams per mole. Therefore, the mass of 3 moles of ammonia would be 51 grams (3 moles x 17 grams/mole).
To find the number of moles in 170000 grams of ammonia, you need to divide the given mass by the molar mass of ammonia. The molar mass of ammonia (NH3) is about 17 grams/mol. Therefore, 170000g รท 17g/mol โ 10000 moles of ammonia.
There are 0.75 moles of ammonia in 0.75 moles of ammonia.
Ammonia is produced from the reaction of hydrogen and nitrogen in a 3:1 ratio. Therefore, 12.0 moles of hydrogen will produce 4.0 moles of ammonia.
For every mole of ammonia produced, we need one mole of nitrogen and three moles of hydrogen. Therefore, to produce 10 moles of ammonia, we would need: 10 moles of nitrogen 30 moles of hydrogen
There are approximately 0.023 moles of ammonia in 1 g of ammonia (NH3).
The balanced chemical equation for the reaction between ammonia (NH3) and water (H2O) is: 4NH3 + 5O2 โ 4NO + 6H2O. This means that for every 4 moles of ammonia, 6 moles of water are produced. Therefore, if 2 moles of ammonia are used, 3 moles of water vapor can be produced.
The balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is: 3H2 + N2 -> 2NH3 From the equation, it can be seen that 3 moles of hydrogen react to produce 2 moles of ammonia. Therefore, 18 moles of hydrogen can produce (2/3) x 18 = 12 moles of ammonia.
It depends on the stoichiometry of the reaction. You need the balanced chemical equation to determine the number of moles of ammonia produced from the reaction of nitrogen.
Since ammonia has a chemical formula of NH3, it contains one mole of nitrogen and three moles of hydrogen per mole of ammonia. Therefore, 3 moles of ammonia contain 3 moles of nitrogen and 9 moles of hydrogen atoms.
There are 3.14 x 10^23 molecules of ammonia in 0.522 moles of ammonia, as 1 mole of a substance contains Avogadro's number (6.02 x 10^23) of molecules.
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
The molar mass of ammonia (NH3) is approximately 17 grams per mole. Therefore, the mass of 3 moles of ammonia would be 51 grams (3 moles x 17 grams/mole).