0
7.95 X 1022 molecules NH3 (1 mole NH3/6.022 X 1023)
= 0.132 moles ammonia
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∙ 12y ago
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How many molecules of ammonia NH3 are present in 0.522 moles of ammonia?
0,522 moles of ammonia contain 3,143.10e23 molecules of NH3.
Results for Calculate The Amount In Moles Of Molecules For Each Substance. A) A Sample Of Ammonia NH3(g) Containing 8.1x1020 Atoms Of Hydrogen?
NH3 Molecules = ( 8.1 x 10^20 H atoms ) ( 1 NH3 molecule / 3 H atoms ) NH3 Molecules = 2.7 x 10^20 NH3 molecules NH3 moles = ( NH3 molecules ) / ( N Avogadro ) NH3 moles = ( 2.7 x 10^20 NH3 molecules ) / ( 6.022 x 10^23 molecules / mole ) NH3 moles = 4.48 x 10^-4 NH3 moles <--------------
How many molecules (not moles) of NH3 are produced from 5.69104 g of H2?
The reaction would be H2 + 3N2 ==>2NH3moles H2 used = 5.69104 g x 1 mole/2.00 = 2.84552 moles H2moles NH3 produced (assuming N2 is NOT limiting) = 2 moles NH3/mole H2 x 2.84552 moles H2 = 5.69104 moles NH3 producedMolecules of NH3 produced = 5.69104 moles x 6.02x10^23 molecules/mole = 3.4x10^24 molecules
How many moles is 1.50 X1023 molecules of NH3?
2.49x10-1mol NH3Source: e2020
How many molecules (not moles) of NH3 are produced from 5.95104 g of H2?
The number of ammonia molecules is 59 720.10e23.
How many molecules of ammonia NH3 are present in 0.522 moles of ammonia?
0,522 moles of ammonia contain 3,143.10e23 molecules of NH3.
Results for Calculate The Amount In Moles Of Molecules For Each Substance. A) A Sample Of Ammonia NH3(g) Containing 8.1x1020 Atoms Of Hydrogen?
NH3 Molecules = ( 8.1 x 10^20 H atoms ) ( 1 NH3 molecule / 3 H atoms ) NH3 Molecules = 2.7 x 10^20 NH3 molecules NH3 moles = ( NH3 molecules ) / ( N Avogadro ) NH3 moles = ( 2.7 x 10^20 NH3 molecules ) / ( 6.022 x 10^23 molecules / mole ) NH3 moles = 4.48 x 10^-4 NH3 moles <--------------
How many molecules (not moles) of NH3 are produced from 1.57104 g of H2?
The answer is 1,57.10e27 molecules.
How many molecules (not moles) of NH3 are produced from 5.69104 g of H2?
The reaction would be H2 + 3N2 ==>2NH3moles H2 used = 5.69104 g x 1 mole/2.00 = 2.84552 moles H2moles NH3 produced (assuming N2 is NOT limiting) = 2 moles NH3/mole H2 x 2.84552 moles H2 = 5.69104 moles NH3 producedMolecules of NH3 produced = 5.69104 moles x 6.02x10^23 molecules/mole = 3.4x10^24 molecules
How many moles is 1.50 X1023 molecules of NH3?
2.49x10-1mol NH3Source: e2020
How many moles of NH3 can be produced from 2.37x10-4 moles of H2?
First we are going to find number of H2 moles form it mass H2 moles=(2.37*10^-4)/2 = 1.185*10^-4moles Since 3 moles of H2 makes 2 moles of NH3 then by using this ration, we can find number of moles in NH3 NH3 moles= (2 * 1.185*10^-4)/3 = 0.79*10^-4 moles Finally, we find number of NH3 molecules by multiplying the number of moles with (6.022*10^23). #NH3 molecules = (0.79*10^-4) *(6.022*10^23) =4.75 * 10^19 molecules of NH3 Good luck Enas
How many molecules (not moles) of NH3 are produced from 5.95104 g of H2?
The number of ammonia molecules is 59 720.10e23.
How many molecules -not moles- of NH3 are produced from 3.07104 g of H2?
Balanced equation is N2 + 3H2 ==> 2NH33.07104 g H2 x 1 mol/1.0079 g = 1.7679 moles H2 presentmoles NH3 produced = 2/3 x 1.7679 moles = 1.1786 moles NH3 formedmolecules NH3 = 1.1786 moles x 6.022x10^23 molecules/mole = 7.098x10^23 molecules (4 sig figs based on sig figs used in 6.022x10^23)
How many moles of NH3 can be produced from the reaction of 75g of N2?
0,044 moles of NH3 can be produced.
How many moles of NH3 are produced when 1.4 moles H2 reacts?
Balanced equation. N2 + 3H2 --> 2NH3 1.4 moles H2 (2 moles NH3/3 moles H2) = 0.93 moles NH3 produced =======================
How many moles of NH3 are produced when 1.2 moles of H2 reacts?
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
How many molecules are in 0.0650 mol NH3?
The number of molecules is 0,391439155705.10e23.
