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The number of molecules is 0,391439155705.10e23.
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How many molecules are in 75g of N2O3?
1 mole N2O3 = 76.0116g N2O3 (atomic weights x subscripts) 1 mole N2O3 = 6.022 x 1023 molecules N2O3 75g N2O3 x (1mol N2O3/76.0116g N2O3) = 0.99mol N2O3 0.99mol N2O3 x (6.022 x 1023 molecules N2O3/1mol N2O3) = 6.0 x 1023 molecules N2O3
Number of N atoms in 0.410 mol NH3?
I actually have this problem in my chemistry book too. This is what is given in the "Solutions to Red Exercises" book that went along with the text: Analyze. Given: mol NH3, Find: N atoms Plan. mol NH3---> mol N atoms---> N atoms Solve. 0.410 mol NH3 * 1 mol N atoms/ 1 mol NH3 * 6.022*10^23 atoms/1mol = 2.47*10^23 N atoms Check. (0.4)(6*10^23)=2.4*10^23. I hope this helps.
How many moles of NH3 are produced when 1.2 mol of H2 reacts?
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
N2 plus 3H2 -- 2NH3 If you produce 55.5 grams of ammonia how many grams of nitrogen will you need?
You need the balanced chemical equation for N2 and H2 combining to form ammonia, NH3.N2 (g) + 3 H2 (g) -----> 2 NH3 (g)Moles NH3 = ( 55.5 g NH3 ) / ( 17.03 g/mol NH3 ) = 3.259 moles of NH3n N2 required = ( 3.259 mol NH3 ) ( 1 N2 mol / 2 NH3 mol ) = 1.629 moles N2m N2 required = ( 1.629 mol N2 ) ( 28.103 g N2 / mol N2 ) = 45.67 g N2 needed
How many grams of NH3 are needed to provide the same number of molecules as in 0.55 grams of SF6?
molar mass NH3 = 17 g/molmolar mass SF6 = 146 g/molmolecules in 0.55g SF6 = 0.55g x 1mol/146g x 6.02x10^23 molecules/mole = 2.27x10^21 moleculesgrams NH3 needed = 2.27x10^21 molecules x 1mol/6.02x10^23 molecules x 17g/mol = 0.064 grams
How many molecules are in 75g of N2O3?
1 mole N2O3 = 76.0116g N2O3 (atomic weights x subscripts) 1 mole N2O3 = 6.022 x 1023 molecules N2O3 75g N2O3 x (1mol N2O3/76.0116g N2O3) = 0.99mol N2O3 0.99mol N2O3 x (6.022 x 1023 molecules N2O3/1mol N2O3) = 6.0 x 1023 molecules N2O3
How many molecules are in 0.0710 mol NH3?
9.982 is the answer because you take the given mole and multiply it by the mass of N. So it would be 0.713 mol x 14.00 = 9.982 g
How many Molecules are contained in 0.900 mol O2?
5.418E23 molecules
Number of N atoms in 0.410 mol NH3?
I actually have this problem in my chemistry book too. This is what is given in the "Solutions to Red Exercises" book that went along with the text: Analyze. Given: mol NH3, Find: N atoms Plan. mol NH3---> mol N atoms---> N atoms Solve. 0.410 mol NH3 * 1 mol N atoms/ 1 mol NH3 * 6.022*10^23 atoms/1mol = 2.47*10^23 N atoms Check. (0.4)(6*10^23)=2.4*10^23. I hope this helps.
How many grams of NH3 can be produced from 2.08 grams of N2?
Ok, so I'm assuming that the chemical formula is written as - 3H2 + N2 ----> 2NH3 2.80 = moles of N2 17.03052 g/mol = Molar mass of NH3 (2.80 mol N2) x (2 NH3) / (1 N2) = 5.6 mol NH3 x (17.03052 g) / (1 mol NH3) = 95.4 g NH3
How many moles of NH3 are produced when 1.2 mol of H2 reacts?
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
N2 plus 3H2 -- 2NH3 If you produce 55.5 grams of ammonia how many grams of nitrogen will you need?
You need the balanced chemical equation for N2 and H2 combining to form ammonia, NH3.N2 (g) + 3 H2 (g) -----> 2 NH3 (g)Moles NH3 = ( 55.5 g NH3 ) / ( 17.03 g/mol NH3 ) = 3.259 moles of NH3n N2 required = ( 3.259 mol NH3 ) ( 1 N2 mol / 2 NH3 mol ) = 1.629 moles N2m N2 required = ( 1.629 mol N2 ) ( 28.103 g N2 / mol N2 ) = 45.67 g N2 needed
How many atoms are there in 0.850 mol of ammonia?
There are 6.02 x 1023 NH3 molecules in 1 mole of NH3.Therefore 0.850mol of ammonia would have 0.85 x 6.02 x 1023 molecules of NH3.In each NH3 molecule there are 4 atoms (one N and three H atoms).Therefore the number of atoms in 0.850mol of NH3 is4 x 0.85 x 6.02 x 1023 = 2.05 x 1024
HOW many grams pf ammonia are in 387x1021 molecules?
Assuming that this ammonia gas is at STP, you can use Avogadro's number to gind the number of moles of gas:(387 x 1021 molecules) x (1 mol / 6.02x1023particles) x (17.03 g / 1 mol) =110 g NH3
What is the molecular mass of NH3 when The atomic mass of N is 1401 gmole and the atomic mass of H is 1008 gmole?
Molecular mass = sum of all atoms masses = 1(molN/mol NH3)*14.01(g/mol N) + 3(molH/mol NH3)*1.008(g/mol H) = 17.03 g/mol NH3
How many molecules are there in 1.00 mol of H2O2?
There are 6.022x10^23 molecules in 1.00 mol of anything.
How many moles of nitrogen are required to produce 18 mol of ammonia?
18 mol of NH3 (ammonia) contains 18 mol of N atoms. 1 mole of N2 (nitrogen gas) contains 2 mol N atoms. so 9 mol N2 is used to produce 18 mol NH3.
