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I actually have this problem in my chemistry book too. This is what is given in the "Solutions to Red Exercises" book that went along with the text:
Analyze. Given: mol NH3, Find: N atoms
Plan. mol NH3---> mol N atoms---> N atoms
Solve. 0.410 mol NH3 * 1 mol N atoms/ 1 mol NH3 * 6.022*10^23 atoms/1mol = 2.47*10^23 N atoms
Check. (0.4)(6*10^23)=2.4*10^23.
I hope this helps.
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∙ 12y ago
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∙ 14y ago0.600 mol NH3 (1mol N/1mol NH3)(6.022 X 10^23/1mol N ) = 3.61 X 10^23 atoms N
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∙ 13y agoOne mole NH3 has 1 mole of Nitrogen and 3 moles of Hydrogen.
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∙ 6y ago0.0340 mole NH3 x 6.02x10^23 molecules/mole = 2.05x10^22 molecules
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∙ 14y ago3.3121x10>23
Wiki User
∙ 12y ago2.71x10^23
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What is the number of atoms of nitrogen of .755 mol of N2?
The number of atoms of nitrogen of 0,755 mol of N2 is 4,546716347035.10e23.
How many atoms are in 63.9g of ammonia?
Ammonia = NH3 and has a molar mass of 17.031 g/molmoles NH3 = 63.9 g x 1 mol/17.031 g = 3.752 molesmolecules NH3 = 3.752 moles x 6.02x10^23 molecules/mole = 2.259x10^24 moleculesEach molecule of NH3 has 4 atoms (1 N + 3 H), thus....number of atoms = 4 atoms/molecule x 2.259x10^24 molecules = 9.04x10^24 atoms (to 3 sig figs)
How many atoms are there in 0.750 mol of carbon monoxide?
The number of atoms is 9,0332112855.10e23.
N2 plus 3H2 -- 2NH3 If you produce 55.5 grams of ammonia how many grams of nitrogen will you need?
You need the balanced chemical equation for N2 and H2 combining to form ammonia, NH3.N2 (g) + 3 H2 (g) -----> 2 NH3 (g)Moles NH3 = ( 55.5 g NH3 ) / ( 17.03 g/mol NH3 ) = 3.259 moles of NH3n N2 required = ( 3.259 mol NH3 ) ( 1 N2 mol / 2 NH3 mol ) = 1.629 moles N2m N2 required = ( 1.629 mol N2 ) ( 28.103 g N2 / mol N2 ) = 45.67 g N2 needed
What is the mass of 1 mole of NH3?
the molecular mass number of NH3 = 17 atomic mass no.of N=14 x 1 atom (present in the compound)=14 atomic mass of H= 1 x 3 atoms (present in compound)=3 thus, molecular mass= atomic mass of N+ atomic mass of H3 = 14 + 3 = 17
How many moles of nitrogen are required to produce 18 mol of ammonia?
18 mol of NH3 (ammonia) contains 18 mol of N atoms. 1 mole of N2 (nitrogen gas) contains 2 mol N atoms. so 9 mol N2 is used to produce 18 mol NH3.
What is the molecular mass of NH3 when The atomic mass of N is 1401 gmole and the atomic mass of H is 1008 gmole?
Molecular mass = sum of all atoms masses = 1(molN/mol NH3)*14.01(g/mol N) + 3(molH/mol NH3)*1.008(g/mol H) = 17.03 g/mol NH3
How many atoms are there in 0.850 mol of ammonia?
There are 6.02 x 1023 NH3 molecules in 1 mole of NH3.Therefore 0.850mol of ammonia would have 0.85 x 6.02 x 1023 molecules of NH3.In each NH3 molecule there are 4 atoms (one N and three H atoms).Therefore the number of atoms in 0.850mol of NH3 is4 x 0.85 x 6.02 x 1023 = 2.05 x 1024
What is the number of atoms of nitrogen of .755 mol of N2?
The number of atoms of nitrogen of 0,755 mol of N2 is 4,546716347035.10e23.
How many atoms are in 63.9g of ammonia?
Ammonia = NH3 and has a molar mass of 17.031 g/molmoles NH3 = 63.9 g x 1 mol/17.031 g = 3.752 molesmolecules NH3 = 3.752 moles x 6.02x10^23 molecules/mole = 2.259x10^24 moleculesEach molecule of NH3 has 4 atoms (1 N + 3 H), thus....number of atoms = 4 atoms/molecule x 2.259x10^24 molecules = 9.04x10^24 atoms (to 3 sig figs)
Calculate the number of atom in 13.2 mol copper?
To calculate the number of atoms in 13.2 mol of copper, you can use Avogadro's number, which is approximately 6.022 x 10^23 atoms per mole. Multiply 13.2 mol by Avogadro's number to get the number of atoms: 13.2 mol * (6.022 x 10^23 atoms/mol) = 7.93 x 10^24 atoms. Therefore, there are approximately 7.93 x 10^24 atoms in 13.2 mol of copper.
How many atom of 1 mol of ammonia?
The molecular formula for ammonia is NH3, showing that each molecule contains four atoms. Therefore, the number of atoms in one mole of ammonia is 4 times Avogadro's Number or about 24.1 X 1024.
How many atoms of hydrogen are in 2NH3?
1 mole NH3 (3 mole H/1 mole NH3) = 3 mole hydrogen atoms
How many number of atoms are in 0.40 mole of sulfur?
The number of atoms in 0.40 mole of ANY element or compound is: 0.40 mol x 6.022x1023 atoms/mol = 2.4x1023 atoms.
How many grams of NH3 can be produced from 2.08 grams of N2?
Ok, so I'm assuming that the chemical formula is written as - 3H2 + N2 ----> 2NH3 2.80 = moles of N2 17.03052 g/mol = Molar mass of NH3 (2.80 mol N2) x (2 NH3) / (1 N2) = 5.6 mol NH3 x (17.03052 g) / (1 mol NH3) = 95.4 g NH3
How many hydrogen atoms are there in 0.5 mole of Hydrogen?
Avagadro's number = 6.022 × 1023 atoms/mol0.5 mol × (6.022 × 1023) atoms/mol = 3.011 ×1023 atoms
How many atoms are there in 0.750 mol of carbon monoxide?
The number of atoms is 9,0332112855.10e23.
