Moles = Mass / Molar Mass
6.155172414= 107.1/17.4
6.3 moles. One mole of NH3 is 17 g, and 107.1 / 17 = 6.3
14,35 g of NH3 is equal to 0,842 moles.
there are 500210 g of atoms
0,522 moles of ammonia contain 3,143.10e23 molecules of NH3.
Balanced equation. N2 + 3H2 --> 2NH3 1.4 moles H2 (2 moles NH3/3 moles H2) = 0.93 moles NH3 produced =======================
7.95 X 1022 molecules NH3 (1 mole NH3/6.022 X 1023) = 0.132 moles ammonia =================
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
NH3 is balanced at 1:3, so in 3 moles NH3 there are 3*3 = 9 moles H atoms
0,522 moles of ammonia contain 3,143.10e23 molecules of NH3.
0,044 moles of NH3 can be produced.
Balanced equation. N2 + 3H2 --> 2NH3 1.4 moles H2 (2 moles NH3/3 moles H2) = 0.93 moles NH3 produced =======================
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
If 5.0 moles of NH3 are produced 2.5 moles of N2 are used.
Atomic mass of NH3 is 17.So there are 1.353mol.
1 g of ammonia (NH3) is equal to 0,059 mol.
7.95 X 1022 molecules NH3 (1 mole NH3/6.022 X 1023) = 0.132 moles ammonia =================
1 mole
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
NH3 is balanced at 1:3, so in 3 moles NH3 there are 3*3 = 9 moles H atoms