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Moles = Mass / Molar Mass

6.155172414= 107.1/17.4

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14y ago

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How many moles are present in 1g of ammonia?

To calculate the number of moles in 1g of ammonia (NH3), you first need to determine the molar mass of ammonia. The molar mass of NH3 is approximately 17 g/mol. Then you can use the formula: number of moles = mass / molar mass. So for 1g of NH3, there would be approximately 0.059 moles present.


How many moles of NH3 can be produced from the reaction of 75g of N2?

0,044 moles of NH3 can be produced.


How many moles of NH3 are produced when 1.2 moles of H2 reacts?

How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?


How many moles of NH3 are produced when 1.2 moles H2 reacts?

How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?


How many moles of NH3 are produced when 1.4 moles H2 reacts?

Balanced equation. N2 + 3H2 --> 2NH3 1.4 moles H2 (2 moles NH3/3 moles H2) = 0.93 moles NH3 produced =======================


How many moles of NH3 is in 23g of NH3?

Atomic mass of NH3 is 17.So there are 1.353mol.


How many moles s are present in 1 g of ammonia?

1 g of ammonia (NH3) is equal to 0,059 mol.


How many moles are present in 1 g of ammonia?

There are approximately 0.023 moles of ammonia in 1 g of ammonia (NH3).


How many moles of NH3 are produced when 1.2 mol of H2 reacts?

The balanced chemical equation for the reaction between H2 and NH3 is: 3H2 + N2 → 2NH3 From the equation, we can see that 3 moles of H2 produce 2 moles of NH3. Therefore, when 1.2 moles of H2 react, we can calculate the moles of NH3 produced as: 1.2 mol H2 * (2 mol NH3 / 3 mol H2) = 0.8 mol NH3.


If 5.0 moles of NH3 are produce how many moles of N2 must have been used?

If 5.0 moles of NH3 are produced 2.5 moles of N2 are used.


How many moles of nh3 are produced from 1.5 moles h2?

The balanced chemical equation for the reaction is: 3H2 + N2 -> 2NH3 From the stoichiometry of the balanced equation, 3 moles of H2 produces 2 moles of NH3. Therefore, if you have 1.5 moles of H2, you will produce 1.5 moles * (2 moles NH3 / 3 moles H2) = 1 mole of NH3.


How many moles is 1.50 X1023 molecules of NH3?

2.49x10-1mol NH3Source: e2020