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Moles = Mass / Molar Mass

6.155172414= 107.1/17.4

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13y ago
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14y ago

6.3 moles. One mole of NH3 is 17 g, and 107.1 / 17 = 6.3

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8y ago

14,35 g of NH3 is equal to 0,842 moles.

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14y ago

there are 500210 g of atoms

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Q: How many moles of NH3 are present in 107.1g?
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