Moles = Mass / Molar Mass
6.155172414= 107.1/17.4
To calculate the number of moles in 1g of ammonia (NH3), you first need to determine the molar mass of ammonia. The molar mass of NH3 is approximately 17 g/mol. Then you can use the formula: number of moles = mass / molar mass. So for 1g of NH3, there would be approximately 0.059 moles present.
Balanced equation. N2 + 3H2 --> 2NH3 1.4 moles H2 (2 moles NH3/3 moles H2) = 0.93 moles NH3 produced =======================
The balanced chemical equation for the reaction between H2 and NH3 is: 3H2 + N2 → 2NH3 From the equation, we can see that 3 moles of H2 produce 2 moles of NH3. Therefore, when 1.2 moles of H2 react, we can calculate the moles of NH3 produced as: 1.2 mol H2 * (2 mol NH3 / 3 mol H2) = 0.8 mol NH3.
2.49x10-1mol NH3Source: e2020
To find the number of moles of electrons in ammonia (NH3), we first need to calculate the number of moles of ammonia using its molar mass. The molar mass of NH3 is 17 g/mol. Therefore, 17 grams of NH3 is equal to 1 mole. Since there are 3 electrons in each molecule of ammonia, there are 6.022 x 10^23 electrons present in 1 mole of NH3.
To calculate the number of moles in 1g of ammonia (NH3), you first need to determine the molar mass of ammonia. The molar mass of NH3 is approximately 17 g/mol. Then you can use the formula: number of moles = mass / molar mass. So for 1g of NH3, there would be approximately 0.059 moles present.
0,044 moles of NH3 can be produced.
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
Balanced equation. N2 + 3H2 --> 2NH3 1.4 moles H2 (2 moles NH3/3 moles H2) = 0.93 moles NH3 produced =======================
Atomic mass of NH3 is 17.So there are 1.353mol.
1 g of ammonia (NH3) is equal to 0,059 mol.
There are approximately 0.023 moles of ammonia in 1 g of ammonia (NH3).
The balanced chemical equation for the reaction between H2 and NH3 is: 3H2 + N2 → 2NH3 From the equation, we can see that 3 moles of H2 produce 2 moles of NH3. Therefore, when 1.2 moles of H2 react, we can calculate the moles of NH3 produced as: 1.2 mol H2 * (2 mol NH3 / 3 mol H2) = 0.8 mol NH3.
If 5.0 moles of NH3 are produced 2.5 moles of N2 are used.
The balanced chemical equation for the reaction is: 3H2 + N2 -> 2NH3 From the stoichiometry of the balanced equation, 3 moles of H2 produces 2 moles of NH3. Therefore, if you have 1.5 moles of H2, you will produce 1.5 moles * (2 moles NH3 / 3 moles H2) = 1 mole of NH3.
2.49x10-1mol NH3Source: e2020