98.8
180g I2
13g Cl2 * (1mol cl / 34.45 ) * (2 mol / 2 mol) * (58.44g NaCl / 1 mol NaCl) = 22g NaCl
Balanced equation. 2Na + Cl2 >> 2NaCl 46 grams sodium = 2 mol 23 grams Chlorine = 0.65 mol ( I think Chlorine is limiting ) 0.65 mol Cl (2mol Na/1mol Cl ) = 1.3 mol ( you do not have that; Cl limits ) 0.65 mol Cl (2mol NaCl/1mol Cl2 )(58.44g/1mol NaCl ) = 75.9 grams
As the molar mass of NaCl is 58.5 g/mol, 1.6 moles weight is 93.6 grams.
182.88
CaC12
8 mol x (4 mol / 2 mol) x 133.5 g / 1 mol = 2136 grams
180g I2
The mass of ammonia is 147,5 g.
110 g ammonia are produced.
13g Cl2 * (1mol cl / 34.45 ) * (2 mol / 2 mol) * (58.44g NaCl / 1 mol NaCl) = 22g NaCl
76 g ammonia are obtained.
89,6 g ammonia are obtained.
1.3 mole C2H2 will produce 2.6 mole CO2, weighting 2.6(mol) x 44 (g/mol) = 114 g CO2
Cu + 2 HCl --> CuCl2 + H2 167.12 g HCl * (1 mol HCl/36.46 g HCl) * (1 mol H2/2 mol HCl) * (2.02 g/1 mol H2) = 4.629 g H2 4.63 grams of hydrogen gas is produced when 167.12 grams of hydrochloric acid reacts with copper.
Balanced equation. 2Na + Cl2 >> 2NaCl 46 grams sodium = 2 mol 23 grams Chlorine = 0.65 mol ( I think Chlorine is limiting ) 0.65 mol Cl (2mol Na/1mol Cl ) = 1.3 mol ( you do not have that; Cl limits ) 0.65 mol Cl (2mol NaCl/1mol Cl2 )(58.44g/1mol NaCl ) = 75.9 grams
(7.6g LiBr)/(86.84g/mol) x (1molLi/1molBr) = .0875 mol Li or with sig figs, .088