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There are 6.02 x 1023 NH3 molecules in 1 mole of NH3.

Therefore 0.850mol of ammonia would have 0.85 x 6.02 x 1023 molecules of NH3.

In each NH3 molecule there are 4 atoms (one N and three H atoms).

Therefore the number of atoms in 0.850mol of NH3 is

4 x 0.85 x 6.02 x 1023 = 2.05 x 1024

Q: How many atoms are there in 0.850 mol of ammonia?

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18 mol of NH3 (ammonia) contains 18 mol of N atoms. 1 mole of N2 (nitrogen gas) contains 2 mol N atoms. so 9 mol N2 is used to produce 18 mol NH3.

The molecular formula for ammonia is NH3, showing that each molecule contains four atoms. Therefore, the number of atoms in one mole of ammonia is 4 times Avogadro's Number or about 24.1 X 1024.

the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol

There are 1.41 e24 atoms of Na in 2.35 mol of NaCl.

481,7713432.1023 atoms

Related questions

18 mol of NH3 (ammonia) contains 18 mol of N atoms. 1 mole of N2 (nitrogen gas) contains 2 mol N atoms. so 9 mol N2 is used to produce 18 mol NH3.

The molecular formula for ammonia is NH3, showing that each molecule contains four atoms. Therefore, the number of atoms in one mole of ammonia is 4 times Avogadro's Number or about 24.1 X 1024.

the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol

A mol = 6,022x10^23 atoms 1,5 mol = 9,033x10^23 atoms Always.

There are 1.204 x 1023 atoms in .200 mol of Pb.

The gram molecular mass of ammonia is 17.03. The formula shows that only one atom of nitrogen is required for each mole of ammonia; 4.12 mol of diatomic nitrogen contains 8.24 mol of nitrogen atoms, and with excess H, all of this nitrogen can be converted to ammonia. Therefore, 8.24 mol of ammonia can be produced, and multiplying this number by17.03 yields a total mass of 140.3 grams of ammonia, to the justified number of significant digits.

There are 1.41 e24 atoms of Na in 2.35 mol of NaCl.

0.45 mol BaSO4 have 2,698.10e23 sulfur atoms.

1.3 mol

The answer is 18,061.1023 atoms.

481,7713432.1023 atoms

48,177 134 32.1023 atoms