To determine the mass of NH3 produced from 2.22 mol of N2, we use the balanced equation for the synthesis of ammonia: N2 + 3H2 → 2NH3. From the equation, 1 mole of N2 produces 2 moles of NH3. Therefore, 2.22 mol of N2 will yield 2 × 2.22 = 4.44 mol of NH3. The molar mass of NH3 is approximately 17.03 g/mol, so the mass produced is 4.44 mol × 17.03 g/mol = 75.7 grams of NH3.
There are approximately 7.83 ounces in 222 grams.
Radon-222 has a half-life of about 3.8 days. To calculate the time required for 200 grams of radon-222 to decay to 50 grams, you can use the formula: [N = N_0 \left(\frac{1}{2}\right)^{\frac{t}{t_{1/2}}}] where N is the final amount (50 grams), N0 is the initial amount (200 grams), t is the time in days, and t1/2 is the half-life. Solving for t gives around 7.6 days.
Is there an answer? The volume of 1 cup = 16 tablespoons The gram is a measurement of weight.
if 222 micrograms of fresh water of density 1 gm/cc, then 222 micrograms equals 222 micro-liters that equals 0.222 milliliters. Result: 0.222 milliliters
222
There are approximately 7.83 ounces in 222 grams.
7.64 it is the half life of radon-222 multipled by 2
7.64 days
After 76 seconds, half of the radium-222 would have decayed (its half-life is about 3.8 days). Therefore, the quantity of radium-222 remaining in the 12-gram sample would be 6 grams.
Radon-222 has a half-life of about 3.8 days. To calculate the time required for 200 grams of radon-222 to decay to 50 grams, you can use the formula: [N = N_0 \left(\frac{1}{2}\right)^{\frac{t}{t_{1/2}}}] where N is the final amount (50 grams), N0 is the initial amount (200 grams), t is the time in days, and t1/2 is the half-life. Solving for t gives around 7.6 days.
222
222 in = 5.6388 meters
222 in = 18.5 ft
There are 3 2's in 222.
37 6x37=222
There are 31.7 weeks in 222 days.
222 pounds is 15.9 stone.