5,812 561 184.1024
mol. mass of ethane = 2x12.01+ 6x1.008= 30.01g/mol # of mole in 0.334 of ethane= 0.334/30.01= 0.01mol
2C(s) + 2H2(g) + 52.5 kJ -> C2H4
The number of molecules is 7,2265690284.10e23.
1296 g N2O5 x 1 mol N2O5/108 g x 6.02x10^23 molecules/mole = 7.22x10^24 molecules
my Glizzy
C2H4 + H2O --> C2H5OHReaction balanced at 1:1:1 mole of each compound, so you'll need 0.132 mol C2H4 and this is equal to:0.132 (mol C2H4) * 28 (g/mol C2H4) = 3.696 g C2H4 = 3.70 g C2H4
2.01 mol
There are 1.28x10^24 molecules of SF4. 2.13 mol * 6.022x10^23 molecules/mol = 1.28x10^24 molecules.
1 mole gas = 22.4L 1.5mol C2H4 x 22.4L/mol = 33.6L ethane gas (C2H4)
C2H4 + 3 O2 --> 2 CO2 + 2 H2OSo 2.16 mol O2 will produce 1.44 mol H2O(and 1.44 mol CO2)because 3:2 = 2.16 : 1.44
2.65 mol * 64.07 g/mol = 169.79 g
5.418E23 molecules
? molc' MgBr2 = (13.77lbs)(453.59g/1lbs)(1 mol/184.11g)(6.02e23 molc'/1 mol) 13.77 lbs =2.04e25 molecules
4.91 mol * 6.02214129(27)×1023 / mol = 2.96 ×1024
There are 6.022x10^23 molecules in 1.00 mol of anything.
mol. mass of ethane = 2x12.01+ 6x1.008= 30.01g/mol # of mole in 0.334 of ethane= 0.334/30.01= 0.01mol
2C(s) + 2H2(g) + 52.5 kJ -> C2H4