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To determine the number of hydrogen atoms in 2 mol of C8H18, we first need to calculate the molar mass of C8H18. Carbon has a molar mass of approximately 12 g/mol, and hydrogen has a molar mass of approximately 1 g/mol. Therefore, the molar mass of C8H18 is (812) + (181) = 114 g/mol. Next, we use Avogadro's number (6.022 x 10^23) to calculate the number of molecules in 2 mol of C8H18, which is 2 mol * 6.022 x 10^23 molecules/mol. Since there are 18 hydrogen atoms in each molecule of C8H18, the total number of hydrogen atoms in 2 mol of C8H18 is 2 mol * 6.022 x 10^23 molecules/mol * 18 atoms/molecule = 2.17 x 10^25 hydrogen atoms.
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How many moles of H are in 2 mol of c8h18?
2 moles C8H18 (18 moles H/1 mole C8H18) = 36 moles of hydrogen =================
How many chlorine atoms are in 0.650 mol of Ca(ClO4)2?
There are 3.12 x 10^23 chlorine atoms in 0.650 mol of Ca(ClO4)2. This is calculated by multiplying the number of moles by Avogadro's number (6.022 x 10^23 atoms/mol) and the number of chlorine atoms in one mole of Ca(ClO4)2 (2).
0.400mol of octane is allowed to react with 0.800mol of oxygen Which is the limiting reactant?
To determine the limiting reactant, compare the moles of each reactant to the stoichiometry of the balanced. In this case, the balanced equation is: 2 C8H18 + 25 O2 → 16 CO2 + 18 H2O The moles ratio between octane (C8H18) and oxygen (O2) is 2:25. Calculate the ratio for each reactant: Octane: 0.400 mol * (25 mol O2 / 2 mol C8H18) = 5.00 mol O2 needed Oxygen: 0.800 mol O2. Since the actual moles of oxygen available (0.800 mol) are greater than the moles needed for the reaction with octane (5.00 mol), oxygen is in excess and octane is the limiting reactant.
How many mol of H are in 4.51 mol H2O?
In 1 molecule of H2O, there are 2 atoms of H. Therefore, in 1 mol of H2O, there are 2 mol of H. So, in 4.51 mol of H2O, there would be 4.51 * 2 = 9.02 mol of H.
How many atoms are in Ba OH 2?
1 mol Ba X (137.33 g Ba / mol Ba) = 137.33 g Ba2 mol O X (16.00 g O / mol O) = 32.00 g O2 mol H X (1.01 g H / mol H) = 2.02 g HMolar mass of Ba(OH)2 = 171.35 g/mol
How many moles of H are in 2 mol of c8h18?
2 moles C8H18 (18 moles H/1 mole C8H18) = 36 moles of hydrogen =================
How many atoms are there in 2 mol of hafnium?
The number of atoms is 12, 044 280 171 4.10e23.
How many chlorine atoms are in 0.650 mol of Ca(ClO4)2?
There are 3.12 x 10^23 chlorine atoms in 0.650 mol of Ca(ClO4)2. This is calculated by multiplying the number of moles by Avogadro's number (6.022 x 10^23 atoms/mol) and the number of chlorine atoms in one mole of Ca(ClO4)2 (2).
How many hydrogen atoms are in 0.1262 mol of H2SO4?
The formula shows that each mol contains 2 hydrogen atoms, and, for any substance, the number molecule per mole is Avogadro's Number. Therefore, 2 X 0.1262 X 6.022 X 1023 or about 1.520 X 1023 hydrogen atoms, to the justified number of significant digits.
0.400mol of octane is allowed to react with 0.800mol of oxygen Which is the limiting reactant?
To determine the limiting reactant, compare the moles of each reactant to the stoichiometry of the balanced. In this case, the balanced equation is: 2 C8H18 + 25 O2 → 16 CO2 + 18 H2O The moles ratio between octane (C8H18) and oxygen (O2) is 2:25. Calculate the ratio for each reactant: Octane: 0.400 mol * (25 mol O2 / 2 mol C8H18) = 5.00 mol O2 needed Oxygen: 0.800 mol O2. Since the actual moles of oxygen available (0.800 mol) are greater than the moles needed for the reaction with octane (5.00 mol), oxygen is in excess and octane is the limiting reactant.
How many moles of carbon and hydrogen are there in 5 moles of octane?
In 5 moles of octane, C8H18, there are 40 moles of carbon atoms (5 moles octane x 8 carbon atoms) and 90 moles of hydrogen atoms (5 moles octane x 18 hydrogen atoms).
How many mol of H are in 4.51 mol H2O?
In 1 molecule of H2O, there are 2 atoms of H. Therefore, in 1 mol of H2O, there are 2 mol of H. So, in 4.51 mol of H2O, there would be 4.51 * 2 = 9.02 mol of H.
How many atoms are in Ba OH 2?
1 mol Ba X (137.33 g Ba / mol Ba) = 137.33 g Ba2 mol O X (16.00 g O / mol O) = 32.00 g O2 mol H X (1.01 g H / mol H) = 2.02 g HMolar mass of Ba(OH)2 = 171.35 g/mol
How many atoms are in 64 grams of sulfur?
To calculate the number of atoms in 64 grams of sulfur, you first need to determine the molar mass of sulfur (32 g/mol). Then, you divide the given mass by the molar mass to find the number of moles (64 g / 32 g/mol = 2 mol). Finally, you use Avogadro's number (6.022 x 10^23) to find the number of atoms in 2 moles of sulfur, which would be 2 mol x 6.022 x 10^23 atoms/mol.
How many atoms are present in 1.5 mol of sulfuric acid?
One molecule of sulfuric acid, H2SO4, contains 7 atoms (2 hydrogen, 1 sulfur, and 4 oxygen). Therefore, in 1.5 mol of sulfuric acid, there would be 1.5 x 6.022 x 10^23 atoms, which is approximately 9.033 x 10^23 atoms.
How many total atoms are there in 0.550 mol of barium chloride (BaCl2)?
There are 2 atoms of chlorine and 1 atom of barium in each molecule of barium chloride (BaCl2). Therefore, in 0.550 mol of BaCl2, there are 0.550 mol x (1 Ba + 2 Cl) = 0.550 x 3 = 1.65 mol total atoms.
How many oxygen atoms in 2.15 mol of N2O?
firstly, you cannot have 1.20105 molecules, it is physically impossible to have a non-integer number of molecules. But I will assume you mean 1.20105 mol. Simply multiply the number of mols of oxygen atoms by avagadros number so 1.20105 mol of n205 = 1.20105*5mol of oxygen atoms. 1.20105 x 5 x 6.022e-23 is your answer
