To determine the number of hydrogen atoms in 2 mol of C8H18, we first need to calculate the molar mass of C8H18. Carbon has a molar mass of approximately 12 g/mol, and hydrogen has a molar mass of approximately 1 g/mol. Therefore, the molar mass of C8H18 is (812) + (181) = 114 g/mol. Next, we use Avogadro's number (6.022 x 10^23) to calculate the number of molecules in 2 mol of C8H18, which is 2 mol * 6.022 x 10^23 molecules/mol. Since there are 18 hydrogen atoms in each molecule of C8H18, the total number of hydrogen atoms in 2 mol of C8H18 is 2 mol * 6.022 x 10^23 molecules/mol * 18 atoms/molecule = 2.17 x 10^25 hydrogen atoms.
2 moles C8H18 (18 moles H/1 mole C8H18) = 36 moles of hydrogen =================
There are 3.12 x 10^23 chlorine atoms in 0.650 mol of Ca(ClO4)2. This is calculated by multiplying the number of moles by Avogadro's number (6.022 x 10^23 atoms/mol) and the number of chlorine atoms in one mole of Ca(ClO4)2 (2).
To determine the limiting reactant, compare the moles of each reactant to the stoichiometry of the balanced. In this case, the balanced equation is: 2 C8H18 + 25 O2 → 16 CO2 + 18 H2O The moles ratio between octane (C8H18) and oxygen (O2) is 2:25. Calculate the ratio for each reactant: Octane: 0.400 mol * (25 mol O2 / 2 mol C8H18) = 5.00 mol O2 needed Oxygen: 0.800 mol O2. Since the actual moles of oxygen available (0.800 mol) are greater than the moles needed for the reaction with octane (5.00 mol), oxygen is in excess and octane is the limiting reactant.
In 1 molecule of H2O, there are 2 atoms of H. Therefore, in 1 mol of H2O, there are 2 mol of H. So, in 4.51 mol of H2O, there would be 4.51 * 2 = 9.02 mol of H.
1 mol Ba X (137.33 g Ba / mol Ba) = 137.33 g Ba2 mol O X (16.00 g O / mol O) = 32.00 g O2 mol H X (1.01 g H / mol H) = 2.02 g HMolar mass of Ba(OH)2 = 171.35 g/mol
2 moles C8H18 (18 moles H/1 mole C8H18) = 36 moles of hydrogen =================
The number of atoms is 12, 044 280 171 4.10e23.
There are 3.12 x 10^23 chlorine atoms in 0.650 mol of Ca(ClO4)2. This is calculated by multiplying the number of moles by Avogadro's number (6.022 x 10^23 atoms/mol) and the number of chlorine atoms in one mole of Ca(ClO4)2 (2).
The formula shows that each mol contains 2 hydrogen atoms, and, for any substance, the number molecule per mole is Avogadro's Number. Therefore, 2 X 0.1262 X 6.022 X 1023 or about 1.520 X 1023 hydrogen atoms, to the justified number of significant digits.
To determine the limiting reactant, compare the moles of each reactant to the stoichiometry of the balanced. In this case, the balanced equation is: 2 C8H18 + 25 O2 → 16 CO2 + 18 H2O The moles ratio between octane (C8H18) and oxygen (O2) is 2:25. Calculate the ratio for each reactant: Octane: 0.400 mol * (25 mol O2 / 2 mol C8H18) = 5.00 mol O2 needed Oxygen: 0.800 mol O2. Since the actual moles of oxygen available (0.800 mol) are greater than the moles needed for the reaction with octane (5.00 mol), oxygen is in excess and octane is the limiting reactant.
In 5 moles of octane, C8H18, there are 40 moles of carbon atoms (5 moles octane x 8 carbon atoms) and 90 moles of hydrogen atoms (5 moles octane x 18 hydrogen atoms).
In 1 molecule of H2O, there are 2 atoms of H. Therefore, in 1 mol of H2O, there are 2 mol of H. So, in 4.51 mol of H2O, there would be 4.51 * 2 = 9.02 mol of H.
1 mol Ba X (137.33 g Ba / mol Ba) = 137.33 g Ba2 mol O X (16.00 g O / mol O) = 32.00 g O2 mol H X (1.01 g H / mol H) = 2.02 g HMolar mass of Ba(OH)2 = 171.35 g/mol
To calculate the number of atoms in 64 grams of sulfur, you first need to determine the molar mass of sulfur (32 g/mol). Then, you divide the given mass by the molar mass to find the number of moles (64 g / 32 g/mol = 2 mol). Finally, you use Avogadro's number (6.022 x 10^23) to find the number of atoms in 2 moles of sulfur, which would be 2 mol x 6.022 x 10^23 atoms/mol.
One molecule of sulfuric acid, H2SO4, contains 7 atoms (2 hydrogen, 1 sulfur, and 4 oxygen). Therefore, in 1.5 mol of sulfuric acid, there would be 1.5 x 6.022 x 10^23 atoms, which is approximately 9.033 x 10^23 atoms.
There are 2 atoms of chlorine and 1 atom of barium in each molecule of barium chloride (BaCl2). Therefore, in 0.550 mol of BaCl2, there are 0.550 mol x (1 Ba + 2 Cl) = 0.550 x 3 = 1.65 mol total atoms.
firstly, you cannot have 1.20105 molecules, it is physically impossible to have a non-integer number of molecules. But I will assume you mean 1.20105 mol. Simply multiply the number of mols of oxygen atoms by avagadros number so 1.20105 mol of n205 = 1.20105*5mol of oxygen atoms. 1.20105 x 5 x 6.022e-23 is your answer