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How many moles of (NH4)2S are there in 150 g of (NH4)2S?
To find the number of moles in 150 g of (NH4)2S, we first need to calculate the molar mass of (NH4)2S. The molar mass of (NH4)2S is 68.15 g/mol. Next, we use the formula: moles = mass / molar mass. Plugging in the values, we get moles = 150 g / 68.15 g/mol, which is approximately 2.20 moles of (NH4)2S.
How many moles are in 150 grams what compound NaCl?
To calculate the number of moles in 150 grams of NaCl, you need to know the molar mass of NaCl, which is approximately 58.44 g/mol. You can then divide the given mass (150 grams) by the molar mass to get the number of moles. In this case, 150 g / 58.44 g/mol ≈ 2.57 moles of NaCl.
How many grams of HCl can be prepared from 2.00 mol H2So4 and 150 g NaCl?
2NaCl + H2SO4 ----> 2HCl + Na2SO4 *molar mass of H2SO4 is 98.09g *molar mass of NaCl is 58.44g *molar mass HCl is is 36.46g Moles NaCl = 150 g / 58.44 = 2.56 The ratio between NaCl and H2SO4 is 2 : 1 so NaCl is the limiting reactant We would get 2.56 mol HCl => 2.56 mol x 36.46 g/mol = 93.3 g
What mass of calcium bromide is needed to prepare 150.0 mL of a 3.50 M solution?
To calculate the mass of calcium bromide needed, you would first find the number of moles needed using the equation moles = Molarity * Volume (in liters). Then, you would use the molar mass of calcium bromide to convert moles to grams. The molar mass of calcium bromide is 199.89 g/mol.
What is the molarity of a solution made by dissolving 29.0 grams of NaCl in 150 ml of water?
29g/150*1000 is 193.333g. The molecular weight of NaCl is 58.433. Therefore 193.333/58.433 is 3.31 molar.
How many moles of atoms are there in 150 g S?
To find the number of moles of atoms in 150 g of sulfur (S), first, we need the molar mass of sulfur, which is approximately 32.07 g/mol. The number of moles of sulfur in 150 g can be calculated using the formula: moles = mass (g) / molar mass (g/mol). Therefore, 150 g of S corresponds to about 4.68 moles of sulfur. Since each sulfur atom is a single atom, there are also 4.68 moles of atoms in 150 g of sulfur.
How many atoms are present in 23.0 mol of Ti?
1 mol = 6,022 x 10^23 molecules of HI. So: 6,022E23 *0,3 = Your answer !
How many moles of atoms are in 150 g sulfur?
To find the number of moles of atoms in 150 g of sulfur, you need to first determine the molar mass of sulfur, which is about 32 g/mol. Then, you can use the formula moles = mass/molar mass. So, 150 g / 32 g/mol ≈ 4.69 moles of sulfur atoms.
How deep can moles dig?
150
If 20.0 mL of 150 M NaOH are used in a titration how many moles of NaOH are used?
To calculate the moles of NaOH used in the titration, multiply the volume (in liters) by the molarity. Converting 20.0 mL to liters (20.0 mL * 1 L/1000 mL = 0.020 L), the moles of NaOH used would be (0.020 L * 150 mol/L = 3.0 moles of NaOH).
How many moles of (NH4)2S are there in 150 g of (NH4)2S?
To find the number of moles in 150 g of (NH4)2S, we first need to calculate the molar mass of (NH4)2S. The molar mass of (NH4)2S is 68.15 g/mol. Next, we use the formula: moles = mass / molar mass. Plugging in the values, we get moles = 150 g / 68.15 g/mol, which is approximately 2.20 moles of (NH4)2S.
How many moles are in 150 grams what compound NaCl?
To calculate the number of moles in 150 grams of NaCl, you need to know the molar mass of NaCl, which is approximately 58.44 g/mol. You can then divide the given mass (150 grams) by the molar mass to get the number of moles. In this case, 150 g / 58.44 g/mol ≈ 2.57 moles of NaCl.
How many moles of sulfuric acid are present in 0.550 L of a 0.150 M sulfuric acid solution?
.150 M is the molarity of the solution, which is the number of moles per liter. So all you need to do is multiply the molarity by the number of liters. So .150 moles/liter x .550 L = .0825 moles
Is .15 and .150 the same amount?
Is .15 and .150 the same amount? *********************************** Yes.
What mass of NaCl is dissolved in 150 g of water in a .050 m solution?
To find the mass of NaCl present in the solution, we first need to calculate the number of moles of NaCl in the solution using the formula: moles = molarity x volume. The volume here is 150 g of water, which is approximately 150 mL. Therefore, the moles of NaCl in the solution would be (0.050 mol/L) x (0.150 L) = 0.0075 moles. The molar mass of NaCl is 58.44 g/mol, so the mass of NaCl in the solution is 0.0075 moles x 58.44 g/mol = approximately 0.44 g.
How many grams of H2O are needed to produce 150 g of Mg(OH)2?
To find the amount of water needed, we first calculate the molar mass of Mg(OH)2. Mg has a molar mass of 24.31 g/mol, O has 16.00 g/mol, and H has 1.01 g/mol. So, the molar mass of Mg(OH)2 is 24.31 + 2(16.00) + 2(1.01) = 58.33 g/mol. To produce 150 g of Mg(OH)2, we need 150 g / 58.33 g/mol = 2.57 moles of Mg(OH)2. Since there are 2 moles of H2O per 1 mole of Mg(OH)2, we need 2.57 moles x 2 = 5.14 moles of H2O. Finally, converting moles to grams, we get 5.14 moles x 18.02 g/mol = 92.54 g of H2O required.
What mass of NaHCO3 is needed to neutralize 150ml of 044M HCl?
Several part problem. Get molarity of NaHCO3. (150 ml)( M NaHCO3) = (150 ml)(0.44 M HCl) = 0.44 M NaHCO3 --------------------------- get moles NaHCO3 ( 150 ml = 0.150 Liters ) 0.44 M NaHCO3 = moles NaHCO3/0.150 Liters = 0.066 moles NaHCO3 ---------------------------------------get grams 0.066 moles NaHCO3 (84.008 grams/1 mole NaHCO3) = 5.54 grams NaHCO3 needed ---------------------------------------------answer
