Divide by molar mass of NaCl (not NaCI ! ) which is 58.44 g/mol NaCl.
Cf. Related questions on NaCl
72.0 grams NaCl (1 mole NaCl/58.44 grams) = 1.2 moles of sodium chloride
For this you need the atomic (molecular) mass of NaCl. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaCl=58.5 grams20.0 grams NaCl / (58.5 grams) =.342 moles NaCl
Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl =============
How many MOLES of sodium nitrate are present in 2.85 grams of this compound ?
The answer is 0,96 moles.
there is .42 moles
240 g of NaCl is equal to 4.11 moles.
116.88 grams
The answer is 648,68 g.
Cf. Related questions on NaCl
72.0 grams NaCl (1 mole NaCl/58.44 grams) = 1.2 moles of sodium chloride
For this you need the atomic (molecular) mass of NaCl. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaCl=58.5 grams20.0 grams NaCl / (58.5 grams) =.342 moles NaCl
The mass of NaCl is 280 g.
20.67 grams NaCl (1mol NaCl/58.44 g NaCl) = 0.3537 moles of sodium chloride
643.5 (:
90234.8=D