Cf. Related questions on NaCl
Sodium chloride has a molar mass of about 58.5 g/mol. So multiply 8 moles by molar mass to get about 468 grams.
the same amount would have to stay in grams, so if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
To find the number of hydrogen atoms in 5.839 grams of C8H8, first calculate the molar mass of C8H8, which is 104 g/mol. Next, find the number of moles of C8H8 in 5.839 grams using the molar mass. Since there are 8 hydrogen atoms per molecule of C8H8, multiply the number of moles by 8 to get the number of hydrogen atoms.
The balanced equation for the reaction is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O. This shows that 13 moles of diatomic oxygen are required to burn 2 moles of butane. By proportionality, (4.8/2)13 or 31.2 moles of oxygen are required to burn 4.8 moles of butane. This corresponds to 31.2(32) or 1.0 X 103 grams of oxygen.
The number of chlorine atoms in 2,00 moles of CCl4 is 48,113.10e23.
The mass is 467,52 g.
The answer is 8 g NaCl.
0,666 moles
To completely neutralize 100 ml of 1M H2SO4, you would need an equal number of moles of NaCl. H2SO4 is a diprotic acid, so you need 2 moles of NaCl for each mole of H2SO4. Therefore, you would need 2 moles of NaCl, which is equal to 117 grams (2 x molar mass of NaCl) to neutralize 100 ml of 1M H2SO4.
To calculate the grams of NaCl needed to make a 0.125 M solution in 200.0 mL, use the formula: moles = Molarity x Volume (L). First, convert 200.0 mL to 0.2 L. Then, calculate moles: 0.125 mol/L x 0.2 L = 0.025 moles of NaCl. Finally, convert moles to grams by multiplying by the molar mass of NaCl (58.44 g/mol): 0.025 moles x 58.44 g/mol = 1.46 grams of NaCl.
Sodium chloride has a molar mass of about 58.5 g/mol. So multiply 8 moles by molar mass to get about 468 grams.
0.2 mol
To find the number of moles, first determine the number of formula units in one mole of NaCl. One mole of NaCl contains Avogadro's number (6.022 x 10^23) of formula units. Therefore, 4.816 x 10^24 formula units of NaCl is equal to 8 moles.
the same amount would have to stay in grams, so if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
2 moles equals 8 g of helium or 12.046 x 1023 atoms
No it is true. 1 mole of helium is 4 g. So 2 moles will be 8 g.
To find the number of moles of NaOH in 8 g, first calculate the molar mass of NaOH (sodium hydroxide) which is approximately 40 g/mol (sodium - 23 g/mol, oxygen - 16 g/mol, hydrogen - 1 g/mol). Then, divide the given mass (8 g) by the molar mass to get the number of moles. So, 8 g / 40 g/mol = 0.2 moles of NaOH.