Cf. Related questions on NaCl
Sodium chloride has a molar mass of about 58.5 g/mol. So multiply 8 moles by molar mass to get about 468 grams.
2NH4OH + H2SO4 >> (NH4)2SO4 + 2H2O 8 moles NH4OH (1mol H2SO4/2mol NH4OH)(98.086g H2SO4/1mol H2SO4) = 392.34 grams H2SO4 needed
The balanced equation for the reaction is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O. This shows that 13 moles of diatomic oxygen are required to burn 2 moles of butane. By proportionality, (4.8/2)13 or 31.2 moles of oxygen are required to burn 4.8 moles of butane. This corresponds to 31.2(32) or 1.0 X 103 grams of oxygen.
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
The formula for normal octane is C8H10. Each mole burned creates 8 moles of CO2. A mole of octane is 106 grams, 8 moles of CO2 is 8x44 = 352 grams So 1.8 kg of octane would produce 1.8x(352/106) = 5.98 g CO2. As the octane value is given to 1 decimal place the answer can be no more accurate so 6.0 kg.
The mass is 467,52 g.
The answer is 8 g NaCl.
0,666 moles
8 grams NaOH (1 mole NaOH/39.998 grams) = 0.2 moles NaOH
0.2 mol
100ml / 1000 = 0.1mol *1M = divide by 1000 moles = mass / molecular mass mass = mole x molecular mass of nacl mass = 0.1 x 58.5 mass = 5.85 answer is 5.85 grams
No it is true. 1 mole of helium is 4 g. So 2 moles will be 8 g.
2,6.10-8 mol
Sodium chloride has a molar mass of about 58.5 g/mol. So multiply 8 moles by molar mass to get about 468 grams.
8
Since 14 (4+10) moles of P4O10 contains 4 moles of Phosphorus, 8 moles of P4O10 will contain :: (8 x 4)/14 = 2.286 moles of Phosphorus
Molarity = moles of solute/volume of solution 0.450 M = m/200ml = 90 millimoles, or, what we need; 0.09 moles 0.09 moles NaOH (39.998 grams NaOH/1 mole NaOH) = 3.60 grams of NaOH needed