The answer is 8 g NaCl.
50 g
There is 20mg of NaCl in 200mg of a 10% salt solution. To convert mg to g, divide by 1000: 20mg = 0.02g of NaCl.
It depends how strong a solution you want to make. The molecular mass of NaCl is 58.44, so for a 1 molar solution you would dissolve 58.44 grams in water and make the volume up to 1 litre. For a 0.1 mol solution you'd take 5.844g to a litre, and a 2 mol solution you'd take 116.88g to a litre of water.
To prepare a 5% NaCl solution, you will need 200 grams of NaCl for 4000 mL (4 L) of solution. This is calculated as 5% of 4000 mL, which equals 200 grams.
That refers to a mixture consisting of 2/100 of sodium chloride (salt) and 98/100 of something else (usually water).
The Molecular Weight of NaCl = 58.5 So to make 1L of 4M NaCl solution you need 4*58.5=234g of NaCl So to make 100mL of the above solution you need 23.4 grams of NaCl
The answer is 0,9 g pure, dried NaCl.
You need 841,536 g NaCl.
If the percent by mass of sodium hypochlorite (NaClO) in the bleach solution is 5.24%, then 100% - 5.24% = 94.76% is the water weight. For a 2500.0g solution, the mass of NaClO is 5.24% of 2500g = 131g. Since the remaining mass is water, the mass of NaCl (sodium chloride) in the solution would be zero.
40.8 grams
NaCl has a molar mass of 22,989 769 28 + 35,453 = 58,442 769 28 g Na has an atomic weight of 22,989 769 28 g. % Na = 22,989 769 28 ÷ 58,442 769 28 = 39,337 200 mL of 0,45 % sodium chloride contain 0,9 g NaCl. Mass of Na in 0,9 grams of NaCl = 0,39337 x 0,9 g = 0,354 g
This depends on the volume and concentration of this solution.