NaCl has a molar mass of 22,989 769 28 + 35,453 = 58,442 769 28 g
Na has an atomic weight of 22,989 769 28 g.
% Na = 22,989 769 28 ÷ 58,442 769 28 = 39,337
200 mL of 0,45 % sodium chloride contain 0,9 g NaCl.
Mass of Na in 0,9 grams of NaCl = 0,39337 x 0,9 g = 0,354 g
The percentage of sodium in NaCl is 39,666.So, 75 x 39,666/100= 29,75 g sodium in 75 g NaCl
The density of sodium chloride (NaCl) is 2.165 grams per milliliter.
The percent by weight of NaCl in a saturated solution at 50 degrees Celsius is approximately 26.3%. This means that in every 100 grams of the solution, 26.3 grams is NaCl.
To find the answer, we multiply the 7 grams of NaCl by the ratio of the molar mass of chlorine over the molar mass of sodium chloride. By doing this, we find that there are about 4.25 grams of chlorine in 7 grams of NaCl.
Since the reaction involves the formation of sodium chloride (NaCl), the molar ratio of sodium to chlorine is 1:1. Therefore, if 10 grams of sodium reacts to form 35 grams of NaCl, then 35 grams of chlorine is also needed for this reaction.
The percentage of sodium in NaCl is 39,666.So, 75 x 39,666/100= 29,75 g sodium in 75 g NaCl
The answer is 1,98 g sodium.
The density of sodium chloride (NaCl) is 2.165 grams per milliliter.
The percent by weight of NaCl in a saturated solution at 50 degrees Celsius is approximately 26.3%. This means that in every 100 grams of the solution, 26.3 grams is NaCl.
1.946 moles NaCl (58.44 grams/1 mole NaCl) = 113.7 grams sodium chloride ======================
The answer is 8 g NaCl.
0.9% w/v (weight per volume, otherwise known as grams per 100ml) sodium chloride is NaCl abbreviated
To find the answer, we multiply the 7 grams of NaCl by the ratio of the molar mass of chlorine over the molar mass of sodium chloride. By doing this, we find that there are about 4.25 grams of chlorine in 7 grams of NaCl.
The answer is 28,81 %.
There are 9.3504 grams of Sodium Chloride. Calculations: 0.160 mol NaCl (58.44g/mol) = 9.3504g NaCl
Mass of NaCl = 22.99 + 35.45 = 58.44 g/mol (taken from periodic table) 3.40mol (58.44g/1 mol) = 198.696 g of NaCl
Since the reaction involves the formation of sodium chloride (NaCl), the molar ratio of sodium to chlorine is 1:1. Therefore, if 10 grams of sodium reacts to form 35 grams of NaCl, then 35 grams of chlorine is also needed for this reaction.