The percentage of sodium in NaCl is 39,666.
So, 75 x 39,666/100= 29,75 g sodium in 75 g NaCl
To find the answer, we multiply the 7 grams of NaCl by the ratio of the molar mass of chlorine over the molar mass of sodium chloride. By doing this, we find that there are about 4.25 grams of chlorine in 7 grams of NaCl.
Balanced equation first. 2Na + Cl2 -> 2NaCl 35 grams NaCl (1 mole NaCl/58.44 grams )( 1 mole Cl2/2 mole NaCl )( 70.9 grams Cl2/1 mole Cl2) = 21 grams of Cl2 needed
A person is dehydrated and is given 500 ml of normal saline.how many grams of sodium chloride will person recieve ?
96.75 grams of NaCl
.250M/.350L = .714 mol .714 mol x 58g/1mol = 41.7g 41.7g NaCl is the answer
The answer is 1,98 g sodium.
72.0 grams NaCl (1 mole NaCl/58.44 grams) = 1.2 moles of sodium chloride
There are 9.3504 grams of Sodium Chloride. Calculations: 0.160 mol NaCl (58.44g/mol) = 9.3504g NaCl
20.67 grams NaCl (1mol NaCl/58.44 g NaCl) = 0.3537 moles of sodium chloride
29
The answer is 2337,59 g NaCl.
To find the answer, we multiply the 7 grams of NaCl by the ratio of the molar mass of chlorine over the molar mass of sodium chloride. By doing this, we find that there are about 4.25 grams of chlorine in 7 grams of NaCl.
1 mole NaCl = 58.44g 0.1601mol NaCl x 58.44g NaCl/mol NaCl = 9.35g NaCl
145 grams NaCl (1 mole NaCl/58.44 grams)(1 mole Na +/1 mole NaCl)(6.022 X 1023/1 mole Na +) = 1.49 X 1024 ions of sodium =====================
1mole NaCl = 58.443g 20.0g NaCl x 1mol/58.443g = 0.342mol NaCl
The mass is 467,52 g.
Balanced equation first. 2Na + Cl2 -> 2NaCl 35 grams NaCl (1 mole NaCl/58.44 grams )( 1 mole Cl2/2 mole NaCl )( 70.9 grams Cl2/1 mole Cl2) = 21 grams of Cl2 needed