For this you need the atomic (molecular) mass of NaCl. Take the number of grams and divide it by the Atomic Mass. Multiply by one mole for units to cancel. NaCl=58.5 grams
20.0 grams NaCl / (58.5 grams) =.342 moles NaCl
5
First You have to express the 200 g NaCl as moles of NaCl. The molar mass of NaCl is 58.5 g/mole. Consequently you need 200/58.5 g/(g/mole) = 3.42 moles of NaCl.Having a 2.10 M NaCl solution You need 3.42/2.10 mole/(mole/l) = 1.63 l of the given solution.
20.0 g = 20.0 (g) / 40.0 (g/mol) = 0.500 mol200 mL = 200 (mL) / 1000 (mL/L) = 0.200 LFinally:molarity = 0.500 (mol) / 0.200 (L) = 2.50 mol/L
14.575 round is 14.6 g
Convert the 200 mol of water to kilograms of NaCl
1 mole of NaCl is 58.44 g 200 g NaCl * (1 mol NaCl/58.44 g NaCl) = 3.422 mol NaCl There are about 3.4 moles in 200 grams of NaCl.
5
200g times 342.2965 g/mol = 68459.3 moles
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
The molecular weight of Calcium Bromide is extremely close to 200. So 1200/200 = 6 moles present.
200
First You have to express the 200 g NaCl as moles of NaCl. The molar mass of NaCl is 58.5 g/mole. Consequently you need 200/58.5 g/(g/mole) = 3.42 moles of NaCl.Having a 2.10 M NaCl solution You need 3.42/2.10 mole/(mole/l) = 1.63 l of the given solution.
The answer is 29,22 g NaCl.
200 (mol) * 56.0 (g/mol) = 11,200.0 grams
For this you need the atomic (molecular) mass of FeCl3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. FeCl3=162.4 grams .200 moles FeCl3
There are 200 grams in 200 grams.
200/1000 x 6 = 1.2 moles