For this you need the atomic (molecular) mass of NaCl. Take the number of grams and divide it by the Atomic Mass. Multiply by one mole for units to cancel. NaCl=58.5 grams
20.0 grams NaCl / (58.5 grams) =.342 moles NaCl
There are 5 moles of calcium in 200 grams of calcium. This calculation is based on the molar mass of calcium, which is approximately 40 grams per mole.
To prepare a 5% NaCl solution, you will need 200 grams of NaCl for 4000 mL (4 L) of solution. This is calculated as 5% of 4000 mL, which equals 200 grams.
First You have to express the 200 g NaCl as moles of NaCl. The molar mass of NaCl is 58.5 g/mole. Consequently you need 200/58.5 g/(g/mole) = 3.42 moles of NaCl.Having a 2.10 M NaCl solution You need 3.42/2.10 mole/(mole/l) = 1.63 l of the given solution.
Convert the 200 mol of water to kilograms of water.
To calculate the molarity of a solution, you would need to divide the number of moles of solute (in this case, 10 mol of NaCl) by the volume of solution in liters (in this case, 200 L). Molarity = moles of solute / liters of solution So, Molarity = 10 mol / 200 L = 0.05 M.
To convert 200mL to moles, you need to know the substance's molar mass. Once you have the molar mass, you can use the formula moles = volume (in liters) / molar volume to determine the number of moles. Remember to convert milliliters to liters by dividing by 1000.
There are 5 moles of calcium in 200 grams of calcium. This calculation is based on the molar mass of calcium, which is approximately 40 grams per mole.
To calculate the grams of NaCl needed to make a 0.125 M solution in 200.0 mL, use the formula: moles = Molarity x Volume (L). First, convert 200.0 mL to 0.2 L. Then, calculate moles: 0.125 mol/L x 0.2 L = 0.025 moles of NaCl. Finally, convert moles to grams by multiplying by the molar mass of NaCl (58.44 g/mol): 0.025 moles x 58.44 g/mol = 1.46 grams of NaCl.
To calculate the number of moles of sucrose in 200 grams, you need to divide the given mass by the molar mass of sucrose. The molar mass of sucrose is approximately 342 grams/mol. Therefore, 200 grams of sucrose is equal to 0.585 moles.
To completely neutralize 100ml of 1M H2SO4, you would need an equal number of moles of NaCl. H2SO4 is a diprotic acid, so it will require 2 moles of NaCl to neutralize 1 mole of H2SO4. Therefore, you would need 2 moles of NaCl for every mole of H2SO4. With a 1M solution of H2SO4 in 100ml, you have 0.1 moles of H2SO4. Therefore, you would need 0.2 moles of NaCl. The molar mass of NaCl is approximately 58.44g/mol, so you would need approximately 11.7 grams of NaCl to completely neutralize the 1M H2SO4 solution.
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
The molecular weight of Calcium Bromide is extremely close to 200. So 1200/200 = 6 moles present.
To prepare a 5% NaCl solution, you will need 200 grams of NaCl for 4000 mL (4 L) of solution. This is calculated as 5% of 4000 mL, which equals 200 grams.
200
First You have to express the 200 g NaCl as moles of NaCl. The molar mass of NaCl is 58.5 g/mole. Consequently you need 200/58.5 g/(g/mole) = 3.42 moles of NaCl.Having a 2.10 M NaCl solution You need 3.42/2.10 mole/(mole/l) = 1.63 l of the given solution.
The answer is 29,22 g NaCl.
There are 200 grams in 200 grams.