Convert the 200 mol of water to kilograms of water.
convert the .2 kg of NaCl to moles of NaCl.
To find molality, first convert grams of NaCl to moles: 0.630g NaCl / 58.44 g/mol NaCl = 0.0108 mol NaCl. Next, calculate molality using moles of solute and mass of solvent: molality = moles of solute / kg of solvent = 0.0108 mol NaCl / 0.525 kg water = 0.0206 mol/kg.
The boiling point elevation of a solution can be calculated using the formula: ΔTb = i * Kf * m, where i is the van't Hoff factor, Kf is the cryoscopic constant for water (0.52 °C kg/mol), and m is the molality of the solution. First, calculate the molality of the NaCl solution using the given mass of NaCl and the molecular weight of NaCl to find the molality. Then, use this molality value in the formula along with the van't Hoff factor for NaCl in water (i = 2) to determine the boiling point elevation.
m (molality)=moles of solute/kg of solvent To calculate moles of solute you convert 292.5 g of NaCl to moles of NaCl. So (292.5gNaCl)(1mole NaCl / 58.4gNaCl)= 5.0085 moles NaCl Now plug and chug. 0.25m=5.0085moles NaCl / x x=5.0085 moles NaCl /.25m x=20kg
Molality(m)= moles of solute divided by kilograms(kg) of solvent you need to find the moles of NaCl by using a conversion factor 70g NaCl = 1mol divided by 58.44g NaCl =1.20mol then you need to convert 300g of water which is the solvent to kilograms by moving the decimal over 3 units to the left which makes .300 kg of solvent Molality= 1.20mol divided by .300kg Molality=4.00
To calculate the molality of a solution, you need to know the moles of solute (in this case, NaCl) and the mass of the solvent (water). First, convert the mass of NaCl to moles using its molar mass. Then, calculate the molality using the formula molality = moles of solute / mass of solvent in kg.
To calculate the molality of a solution, you need to divide the moles of the solute (in this case, NaCl) by the mass of the solvent (water) in kilograms. First, convert the mass of NaCl to moles using its molar mass. Then, calculate the molality by dividing the moles of NaCl by the mass of water in kilograms.
58,49 g NaCl---------------------1 N10 g---------------------------------xx= 10/58,49=0,171 N58,49 is the molar mass of NaCl (for the foemula unit).Molality= 0,171/2=0,085
To calculate the molality of 10 g of NaCl in 2 kg of water, you need to determine the number of moles of NaCl and the mass of the solvent (water) in kilograms. First, calculate the molar mass of NaCl, which is approximately 58.44 g/mol. Then, divide the mass of NaCl (10 g) by its molar mass to find the number of moles, and finally, use the formula for molality: molality = moles of solute / mass of solvent (in kg). In this case, the calculation would be molality = (10 g / 58.44 g/mol) / 2 kg.
To calculate the molality of a solution, you need to know the moles of solute and the mass of the solvent in kilograms. First, calculate the moles of NaCl in 0.2 kg: moles = mass (g) / molar mass. Then, calculate the molality by dividing the moles of solute by the mass of solvent in kg: molality = moles of solute / mass of solvent in kg.
To calculate the molality of NaCl in water, first, determine the number of moles of NaCl by dividing the mass of NaCl (0.2 kg or 200 g) by its molar mass (approximately 58.44 g/mol). Then, divide the number of moles of NaCl by the mass of the solvent (water) in kilograms (3 kg). The formula for molality (m) is m = moles of solute / mass of solvent in kg.
Convert the 200 mol of water to kilograms of water.
Convert the 200 mol of water to kilograms of water.
58,49 g NaCl---------------------1 N10 g---------------------------------xx= 10/58,49=0,171 N58,49 is the molar mass of NaCl (for the foemula unit).Molality= 0,171/2=0,085
convert the .2 kg of NaCl to moles of NaCl.
To find molality, first convert grams of NaCl to moles: 0.630g NaCl / 58.44 g/mol NaCl = 0.0108 mol NaCl. Next, calculate molality using moles of solute and mass of solvent: molality = moles of solute / kg of solvent = 0.0108 mol NaCl / 0.525 kg water = 0.0206 mol/kg.
The concentration of NaCl is 263 g/L