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To calculate the molality of a solution, you need to divide the moles of the solute (in this case, NaCl) by the mass of the solvent (water) in kilograms. First, convert the mass of NaCl to moles using its molar mass. Then, calculate the molality by dividing the moles of NaCl by the mass of water in kilograms.
What else can I help you with?
Is saline NaCI in water a compound or mixture?
Its a mixture
Why does table salt (NaCI) dissolve readily in water?
it is an ionic compound.
How much would the boiling point of water increase if 4 mole of NaCI were added to 1 kg of water?
Change in boiling point = (i)(m)(K)i = van't Hoff factor which for NaCl is 2 (2 particles form upon ionization) m = molality = moles/kg = 4 moles/1 kg = 4 K = boiling point constant for water = 0.512 degrees/m ∆T = (2)(4)(0.512) = 4.1 degrees So, the boiling point of water would increase by 4.1 degrees C (4 degrees to 1 sig. fig.)
Naci how many atoms?
3
How is NaCI dissolved in water an example of like dissolving in like?
Sodium chloride (NaCl) is a polar ionic compound that dissolves in water, which is also a polar solvent. Polar substances tend to dissolve well in other polar substances due to similar polarity and intermolecular forces. This dissolution of NaCl in water is an example of "like dissolving in like" based on the similar polar nature of the solute and solvent.
What would you need to calculate the molality of 10 g of NaCI in 2 kg of water?
To calculate the molality of 10 g of NaCl in 2 kg of water, you need to determine the number of moles of NaCl and the mass of the solvent (water) in kilograms. First, calculate the molar mass of NaCl, which is approximately 58.44 g/mol. Then, divide the mass of NaCl (10 g) by its molar mass to find the number of moles, and finally, use the formula for molality: molality = moles of solute / mass of solvent (in kg). In this case, the calculation would be molality = (10 g / 58.44 g/mol) / 2 kg.
What would you need to do to calculate the molality of 0.2 kg of NaCI in 3 kg of?
To calculate the molality of 0.2 kg of NaCl in 3 kg of water, first determine the number of moles of NaCl by using its molar mass (approximately 58.44 g/mol). Convert 0.2 kg of NaCl to grams (200 g) and calculate the moles: ( \text{moles} = \frac{200 \text{ g}}{58.44 \text{ g/mol}} ). Finally, use the formula for molality, which is moles of solute per kilogram of solvent: ( \text{molality} = \frac{\text{moles of NaCl}}{3 \text{ kg of water}} ).
What are the chemical compounds of salt water?
NaCI + H20 NaCI- Sodium Chloride-Salt. H20 is obviously Di-Hydrogen Oxide. Water.
Is saline NaCI in water a compound or mixture?
Its a mixture
What would need to be done to calculate the molarity of 10 g of NaCl in 2 kg of water?
To calculate the molarity of 10 g of NaCl in 2 kg of water, you would first need to convert the mass of NaCl to moles using its molar mass. Then, calculate the total volume of the solution by considering the density of water (1 kg = 1 L). Finally, divide the moles of NaCl by the volume of the solution in liters to determine the molarity.
How much would the freezing point of water decrease if 4 mol of NaCI were added to 1 kg of water?
The van't Hoff factor for NaCl is 2 since it dissociates into 2 ions in water. The freezing point depression constant for water is 1.86 °C kg/mol. By using the formula ΔTf = i * Kf * m, where i is 2, Kf is 1.86, and m is the molality of the solution (4 mol / 1 kg = 4 m), the freezing point of water will decrease by 14.88 °C.
Why does table salt (NaCI) dissolve readily in water?
it is an ionic compound.
Which property of NaCI allows it to be pumped from under the ground?
It dissolves in water
What is the name of the covalent compound SCI4?
using the initial mass of the NaCI and SiO2 mixture from part A as well as the mass of the dry NaCI recovered from part B, calculate the expert value of the percent composition by mass of NaCI in the mixture
What happens when 10 of NaCI is suspended into distilled water?
Please explain 10 !
How much would the boiling point of water increase if 4 mole of NaCI were added to 1 kg of water?
Change in boiling point = (i)(m)(K)i = van't Hoff factor which for NaCl is 2 (2 particles form upon ionization) m = molality = moles/kg = 4 moles/1 kg = 4 K = boiling point constant for water = 0.512 degrees/m ∆T = (2)(4)(0.512) = 4.1 degrees So, the boiling point of water would increase by 4.1 degrees C (4 degrees to 1 sig. fig.)
When was Naci Taşdöğen born?
Naci Taşdöğen was born in 1967.
