Convert the 200 mol of water to kilograms of NaCl
The Molarity of the solution is .901
Convert the 200 mol of water to kilograms of water.
All you have to do is convert the 6.5 g HCl solution into moles, and then plug that value into the molarity formula. If you need help, here are the formulas: # mol = (mass of substance)/(molar mass) - the molar mass is just the molecular mass of the substance expressed in grams :) Molarity (M) = (# mol solute)/(# L solution) - the solute, in this case, is the HCl, and the solution is just one, based on your question Happy Calculating!!!
First, find the moles of NaCl. Because you have 400 milligrams of NaCl convert to grams by dividing 1000mg. 400mg/1000mg = 0.400 grams of NaCl. Now we need to convert to moles. For every mole of NaCl there is 58.44 grams. (22.99g Na + 35.45 g Cl) so using stoichiometry (grams cancel) I get .0068 moles of NaCl. Conver 100 mL to L by dividing by 1000mL. Therefore there is .001 L in the solution. Molarity is moles per Liter. So 0.0068 mols of NaCl / 0.001 L = 6.84 M
convert the .2 kg of NaCl to moles of NaCl.
Need moles NaCl first. 17.52 grams NaCl (1 mole NaCl/58.44 grams) = 0.29979 moles NaCl =====================Now. Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters ) Molarity = 0.29979 mole NaCl/2 Liters = 0.1499 M NaCl ----------------------
Yes, you definitely need to know the molecular weight of a compound to calculate molarity.
10 g of NaCl in 2 kg of water is 5 g of NaCl in 1 kg of water.The molar mass of NaCl is 39,666 g.5 g is equal to 0,318 molal.
The molar mass of sodium chloride is 58,439 769 28 ≈ 58,44 g.10 g NaCl in 2 kg water is 5 g/1 kg.This is equal to 5/58,44, so 0,0855 mol.
Not enough information. To calculate mass, you would need volume and density (mass = volume x density).
Need to find moles NaCl. 526 grams NaCl (1 mole NaCl/58.44 grams) = 9.0 moles NaCl --------------------------------now, Molarity = moles of solute/Liters of solution or, for our purposes Liters of solution = moles of solute/Molarity Liters of solution = 9.0 moles NaCl/3.0 M = 3.0 liters in volume ---------------------------------
volume of the solution
A liter is equal to a dm3. So, we have 3,292 dm3 solution. We need the amount of the NaCl. It is m/M -> 17,62 / 58,5 -> approx. 0,3012 mol. So, the molarity is 0,3012 / 3,292 -> 0,0915 mol dm-3 .
You need to know the moles of solute and the VOLUME of SOLUTION.
The Molarity of the solution is .901
You need to know the molar mass of NaCl. Then 10g/molar mass = moles.
Convert the 200 mol of water to kilograms of water.