The molar mass of sodium chloride is 58,439 769 28 ≈ 58,44 g.
10 g NaCl in 2 kg water is 5 g/1 kg.
This is equal to 5/58,44, so 0,0855 mol.
To calculate the molarity of 10 g of NaCl in 2 kg of water, you would first need to convert the mass of NaCl to moles using its molar mass. Then, calculate the total volume of the solution by considering the density of water (1 kg = 1 L). Finally, divide the moles of NaCl by the volume of the solution in liters to determine the molarity.
To calculate the molarity of the NaCl solution, first convert the mass of NaCl to moles using its molar mass. The molar mass of NaCl is 58.44 g/mol. Then, divide the moles of NaCl by the volume of the solution in liters (750 mL = 0.75 L) to get the molarity. In this case, the molarity of the NaCl solution is 1.5 M.
Get moles NaCl and change 245 ml to 0.245 Liters. 3.8 grams NaCl (1 mole NaCl/58.54 grams) = 0.0650 moles NaCl Molarity = moles of solute/Liters of solution Molarity = 0.0650 moles NaCl/0.245 Liters = 0.27 M NaCl ----------------------
Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========
To calculate the molarity, you first need to convert the mass of NaCl to moles using its molar mass. The molar mass of NaCl is approximately 58.5 g/mol. Then, divide the moles of NaCl by the volume of the solution in liters to get the molarity. In this case, molarity = (58 grams / 58.5 g/mol) / 2.0 L.
To calculate the molarity of a solution, you would need to divide the number of moles of solute (in this case, 10 mol of NaCl) by the volume of solution in liters (in this case, 200 L). Molarity = moles of solute / liters of solution So, Molarity = 10 mol / 200 L = 0.05 M.
To calculate the molarity of 10 g of NaCl in 2 kg of water, you would first need to convert the mass of NaCl to moles using its molar mass. Then, calculate the total volume of the solution by considering the density of water (1 kg = 1 L). Finally, divide the moles of NaCl by the volume of the solution in liters to determine the molarity.
To calculate the molarity of a 5% NaCl solution, you need to know the density of the solution. Once you have the density, you can convert the percentage to grams per liter. Then, using the molar mass of NaCl (58.44 g/mol), you can calculate the molarity using the formula Molarity = (mass of solute in g) / (molar mass of solute in g/mol) / (volume of solution in L).
To find the molarity, first calculate the moles of NaCl using its molar mass (58.44 g/mol). Then, divide the moles of NaCl by the volume of solution in liters (0.1 L) to get the molarity in moles per liter.
Need moles NaCl first. 17.52 grams NaCl (1 mole NaCl/58.44 grams) = 0.29979 moles NaCl =====================Now. Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters ) Molarity = 0.29979 mole NaCl/2 Liters = 0.1499 M NaCl ----------------------
To calculate the molarity of the NaCl solution, first convert the mass of NaCl to moles using its molar mass. The molar mass of NaCl is 58.44 g/mol. Then, divide the moles of NaCl by the volume of the solution in liters (750 mL = 0.75 L) to get the molarity. In this case, the molarity of the NaCl solution is 1.5 M.
Get moles NaCl and change 245 ml to 0.245 Liters. 3.8 grams NaCl (1 mole NaCl/58.54 grams) = 0.0650 moles NaCl Molarity = moles of solute/Liters of solution Molarity = 0.0650 moles NaCl/0.245 Liters = 0.27 M NaCl ----------------------
Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========
This molarity is 3 M.
m (molality)=moles of solute/kg of solvent To calculate moles of solute you convert 292.5 g of NaCl to moles of NaCl. So (292.5gNaCl)(1mole NaCl / 58.4gNaCl)= 5.0085 moles NaCl Now plug and chug. 0.25m=5.0085moles NaCl / x x=5.0085 moles NaCl /.25m x=20kg
To calculate the molarity (M) of the NaCl solution, first find the number of moles of NaCl. The molar mass of NaCl is approximately 58.44 g/mol, so 21.04 g of NaCl is about 0.360 moles (21.04 g ÷ 58.44 g/mol). Molarity is defined as moles of solute per liter of solution; therefore, for 750 ml (0.750 L), the molarity is 0.360 moles ÷ 0.750 L = 0.480 M. Thus, the molarity of the NaCl solution is 0.480 M.
Concentration = Molarity = mol/L24 g NaCl = ?? mol NaCl?? mol NaCl/2 L water = ?? M (M is unit of molarity)