What mass of NaHCO3 is needed to neutralize 150ml of 044M HCl?

Answer 1

Several part problem. Get molarity of NaHCO3.

(150 ml)( M NaHCO3) = (150 ml)(0.44 M HCl)

= 0.44 M NaHCO3

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get moles NaHCO3 ( 150 ml = 0.150 Liters )

0.44 M NaHCO3 = moles NaHCO3/0.150 Liters

= 0.066 moles NaHCO3

---------------------------------------get grams

0.066 moles NaHCO3 (84.008 grams/1 mole NaHCO3)

= 5.54 grams NaHCO3 needed

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Answer 2

To neutralize 150 mL of 0.44 M HCl, you would need an equal number of moles of NaHCO3. First, calculate the number of moles of HCl (mol = Molarity x Volume) used. Then, since 1 mol of NaHCO3 neutralizes 1 mol of HCl, you would need the same number of moles of NaHCO3. From that, you can calculate the mass of NaHCO3 needed using its molar mass.