Several part problem. Get molarity of NaHCO3.
(150 ml)( M NaHCO3) = (150 ml)(0.44 M HCl)
= 0.44 M NaHCO3
---------------------------
get moles NaHCO3 ( 150 ml = 0.150 Liters )
0.44 M NaHCO3 = moles NaHCO3/0.150 Liters
= 0.066 moles NaHCO3
---------------------------------------get grams
0.066 moles NaHCO3 (84.008 grams/1 mole NaHCO3)
= 5.54 grams NaHCO3 needed
---------------------------------------------answer