The reaction equation is 2 NaHCO3 + H2SO4 = 2 CO2 + 2H2O + Na2SO4. This means that for every mole of sulfuric acid, two moles of NaHCO3 are needed. 150 grams of H2SO4 is 1.53 moles, so 3.06 moles of NaHCO3 are required.
.150 M is the molarity of the solution, which is the number of moles per liter. So all you need to do is multiply the molarity by the number of liters. So .150 moles/liter x .550 L = .0825 moles
To determine the number of moles in 150 grams of Al(OH)3, we first need to calculate the molar mass of Al(OH)3: Aluminum (Al) has a molar mass of 26.98 g/mol, oxygen (O) has a molar mass of 16.00 g/mol, and hydrogen (H) has a molar mass of 1.01 g/mol. Molar mass of Al(OH)3 = 26.98 + 3(16.00) + 3(1.01) = 78.03 g/mol Now, we can calculate the number of moles: Number of moles = Mass (g) / Molar mass Number of moles = 150 g / 78.03 g/mol ≈ 1.92 moles.
To find the number of moles of ammonium sulfate in a 150g sample, you first need to calculate the molar mass of ammonium sulfate (NH4)2SO4, which is approximately 132.14 g/mol. Then, divide the given mass (150g) by the molar mass to get the number of moles, which would be approximately 1.14 moles.
To find the mass of NaCl present in the solution, we first need to calculate the number of moles of NaCl in the solution using the formula: moles = molarity x volume. The volume here is 150 g of water, which is approximately 150 mL. Therefore, the moles of NaCl in the solution would be (0.050 mol/L) x (0.150 L) = 0.0075 moles. The molar mass of NaCl is 58.44 g/mol, so the mass of NaCl in the solution is 0.0075 moles x 58.44 g/mol = approximately 0.44 g.
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To find the number of moles of atoms in 150 g of sulfur (S), first, we need the molar mass of sulfur, which is approximately 32.07 g/mol. The number of moles of sulfur in 150 g can be calculated using the formula: moles = mass (g) / molar mass (g/mol). Therefore, 150 g of S corresponds to about 4.68 moles of sulfur. Since each sulfur atom is a single atom, there are also 4.68 moles of atoms in 150 g of sulfur.
To calculate the moles of NaOH used in the titration, multiply the volume (in liters) by the molarity. Converting 20.0 mL to liters (20.0 mL * 1 L/1000 mL = 0.020 L), the moles of NaOH used would be (0.020 L * 150 mol/L = 3.0 moles of NaOH).
To calculate the number of moles in 150 grams of NaCl, you need to know the molar mass of NaCl, which is approximately 58.44 g/mol. You can then divide the given mass (150 grams) by the molar mass to get the number of moles. In this case, 150 g / 58.44 g/mol ≈ 2.57 moles of NaCl.
150
To find the number of moles in 150 g of (NH4)2S, we first need to calculate the molar mass of (NH4)2S. The molar mass of (NH4)2S is 68.15 g/mol. Next, we use the formula: moles = mass / molar mass. Plugging in the values, we get moles = 150 g / 68.15 g/mol, which is approximately 2.20 moles of (NH4)2S.
.150 M is the molarity of the solution, which is the number of moles per liter. So all you need to do is multiply the molarity by the number of liters. So .150 moles/liter x .550 L = .0825 moles
1 mol = 6,022 x 10^23 molecules of HI. So: 6,022E23 *0,3 = Your answer !
This depends on many things including temperature, pressure, number of moles and molecular weight or the density
150%*C
No you need more copper
To determine the number of moles in 150 grams of Al(OH)3, we first need to calculate the molar mass of Al(OH)3: Aluminum (Al) has a molar mass of 26.98 g/mol, oxygen (O) has a molar mass of 16.00 g/mol, and hydrogen (H) has a molar mass of 1.01 g/mol. Molar mass of Al(OH)3 = 26.98 + 3(16.00) + 3(1.01) = 78.03 g/mol Now, we can calculate the number of moles: Number of moles = Mass (g) / Molar mass Number of moles = 150 g / 78.03 g/mol ≈ 1.92 moles.
To find the number of moles of ammonium sulfate in a 150g sample, you first need to calculate the molar mass of ammonium sulfate (NH4)2SO4, which is approximately 132.14 g/mol. Then, divide the given mass (150g) by the molar mass to get the number of moles, which would be approximately 1.14 moles.