0
The reaction equation is 2 NaHCO3 + H2SO4 = 2 CO2 + 2H2O + Na2SO4. This means that for every mole of sulfuric acid, two moles of NaHCO3 are needed. 150 grams of H2SO4 is 1.53 moles, so 3.06 moles of NaHCO3 are required.
Wiki User
∙ 9y ago
Wiki User
∙ 15y agomolecular mass of sodium hydroxide (NaOH) = 23(Na)+16(O)+1(H) =40 mass = (150 x 40)g =6000g
Wiki User
∙ 13y agoDivide by molar mass of NaCl which is 58.44 g/mol NaCl.
Wiki User
∙ 9y agoThe Atomic Mass of the element sulfur, chemical symbol S is 32.1Amount of S = atomic mass/molar mass = 150/32.1= 4.67mol
There are 4.67 moles of sulfur in a 150 gram pure sample.
Wiki User
∙ 8y ago150 g sulfur is equal to 4,679 moles.
Wiki User
∙ 7y agoThe atomic mass of the element sulfur, chemical symbol S is 32.1Amount of S = atomic mass/molar mass = 150/32.1= 4.67molThere are 4.67 moles of sulfur in a 150 gram pure sample.
Add your answer:
Earn +20 pts
How many moles of ammonium sulfate are in 150g sample?
150/132 equals 1.136moles
How many moles of sulfuric acid are present in 0.550 L of a 0.150 M sulfuric acid solution?
.150 M is the molarity of the solution, which is the number of moles per liter. So all you need to do is multiply the molarity by the number of liters. So .150 moles/liter x .550 L = .0825 moles
How many moles are there in 150 grams of Al(OH)3?
The approximate molar mass of Al(OH)3 = 27 + 48 + 3 = 78 g/mol150 g x 1 mol/78 g = 1.92 moles
A sample of nitric acid contains 50 HNO3 molecules How many oxygen atoms are in this sample?
150 (50 x 3)
What is yardstick of atoms?
The atomic radius is approx. 150 pm and is different for each element.
If 20.0 mL of 150 M NaOH are used in a titration how many moles of NaOH are used?
150 M NaOH = 150 mole / liter 20.0 mL = 0.0200 L 150 * 0.0200 = 3 moles
How many moles of (NH4)2S are there in 150 g of (NH4)2S?
150 g x 1 mol/68.154 g = 2.2 moles (2 sig figs)
How many moles of ammonium sulfate are in 150g sample?
150/132 equals 1.136moles
How deep can moles dig?
150
How many moles of sulfuric acid are present in 0.550 L of a 0.150 M sulfuric acid solution?
.150 M is the molarity of the solution, which is the number of moles per liter. So all you need to do is multiply the molarity by the number of liters. So .150 moles/liter x .550 L = .0825 moles
How many atoms are present in 23.0 mol of Ti?
1 mol = 6,022 x 10^23 molecules of HI. So: 6,022E23 *0,3 = Your answer !
How many moles are there in 150 grams of Al(OH)3?
The approximate molar mass of Al(OH)3 = 27 + 48 + 3 = 78 g/mol150 g x 1 mol/78 g = 1.92 moles
150 ml gas how many grms?
This depends on many things including temperature, pressure, number of moles and molecular weight or the density
Iron and sulfur mixture at boiling point?
150%*C
How many moles are in 150 grams what compound NaCl?
Divide by molar mass of NaCl (not NaCI ! ) which is 58.44 g/mol NaCl.
You were hired by a laboratory to recycle 6 moles of silver ions You were given 150 g of copper How many grams of silver can you recover Is this enough copper to recycle 6 moles of silver ions?
No you need more copper
What mass of NaHCO3 is needed to neutralize 150ml of 044M HCl?
Several part problem. Get molarity of NaHCO3. (150 ml)( M NaHCO3) = (150 ml)(0.44 M HCl) = 0.44 M NaHCO3 --------------------------- get moles NaHCO3 ( 150 ml = 0.150 Liters ) 0.44 M NaHCO3 = moles NaHCO3/0.150 Liters = 0.066 moles NaHCO3 ---------------------------------------get grams 0.066 moles NaHCO3 (84.008 grams/1 mole NaHCO3) = 5.54 grams NaHCO3 needed ---------------------------------------------answer
