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How many moles are in 150 grams what compound NaCl?
To calculate the number of moles in 150 grams of NaCl, you need to know the molar mass of NaCl, which is approximately 58.44 g/mol. You can then divide the given mass (150 grams) by the molar mass to get the number of moles. In this case, 150 g / 58.44 g/mol ≈ 2.57 moles of NaCl.
How many moles of calcium are in 425 g?
To calculate the number of moles of calcium in 425 g, you need to divide the given mass by the molar mass of calcium. The molar mass of calcium is approximately 40.08 g/mol. moles = 425 g / 40.08 g/mol ≈ 10.61 moles of calcium.
How many moles are in 25.6 g of NO2?
To calculate the number of moles in 25.6 g of NO2, you need to divide the given mass by the molar mass of NO2, which is 46.01 g/mol. Moles = 25.6 g / 46.01 g/mol = 0.556 moles. Therefore, there are 0.556 moles of NO2 in 25.6 g.
How many grams of oxygen are needed to react completely with 200.0 g of ammonia NH3?
The balanced chemical equation for the reaction between ammonia (NH3) and oxygen (O2) is 4NH3 + 3O2 → 2N2 + 6H2O. From the equation, we can see that 3 moles of O2 are needed to react with 4 moles of NH3. This means the molar ratio of O2 to NH3 is 3:4. First, calculate the number of moles of NH3 in 200.0 g: 200.0 g NH3 / 17.03 g/mol NH3 = 11.75 moles NH3 Now, calculate the number of moles of O2 needed using the molar ratio: 11.75 moles NH3 * (3 moles O2 / 4 moles NH3) = 8.81 moles O2 Finally, convert moles of O2 to grams: 8.81 moles O2 * 32 g/mol O2 = 282.0 g O2.
How many moles of bromine are in 2.60100 grams of bromine?
To determine the number of moles in 2.60100 grams of bromine, we first need to calculate the molar mass of bromine, which is 79.904 g/mol. Then, we use the formula: moles = mass / molar mass. Substituting the values, we get moles = 2.60100 g / 79.904 g/mol = 0.03255 moles of bromine.
How many moles of atoms are there in 150 g S?
To find the number of moles of atoms in 150 g of sulfur (S), first, we need the molar mass of sulfur, which is approximately 32.07 g/mol. The number of moles of sulfur in 150 g can be calculated using the formula: moles = mass (g) / molar mass (g/mol). Therefore, 150 g of S corresponds to about 4.68 moles of sulfur. Since each sulfur atom is a single atom, there are also 4.68 moles of atoms in 150 g of sulfur.
How many moles are in 150 grams what compound NaCl?
To calculate the number of moles in 150 grams of NaCl, you need to know the molar mass of NaCl, which is approximately 58.44 g/mol. You can then divide the given mass (150 grams) by the molar mass to get the number of moles. In this case, 150 g / 58.44 g/mol ≈ 2.57 moles of NaCl.
How many moles of atoms are in 150 g sulfur?
To find the number of moles of atoms in 150 g of sulfur, you need to first determine the molar mass of sulfur, which is about 32 g/mol. Then, you can use the formula moles = mass/molar mass. So, 150 g / 32 g/mol ≈ 4.69 moles of sulfur atoms.
How many moles are there in 150 grams of Al(OH)3?
To determine the number of moles in 150 grams of Al(OH)3, we first need to calculate the molar mass of Al(OH)3: Aluminum (Al) has a molar mass of 26.98 g/mol, oxygen (O) has a molar mass of 16.00 g/mol, and hydrogen (H) has a molar mass of 1.01 g/mol. Molar mass of Al(OH)3 = 26.98 + 3(16.00) + 3(1.01) = 78.03 g/mol Now, we can calculate the number of moles: Number of moles = Mass (g) / Molar mass Number of moles = 150 g / 78.03 g/mol ≈ 1.92 moles.
If you have g of beryllium how many moles is this equivalent to?
The formula is: number of moles = g Be/9,012.
What mass of NaCl is dissolved in 150 g of water in a .050 m solution?
To find the mass of NaCl present in the solution, we first need to calculate the number of moles of NaCl in the solution using the formula: moles = molarity x volume. The volume here is 150 g of water, which is approximately 150 mL. Therefore, the moles of NaCl in the solution would be (0.050 mol/L) x (0.150 L) = 0.0075 moles. The molar mass of NaCl is 58.44 g/mol, so the mass of NaCl in the solution is 0.0075 moles x 58.44 g/mol = approximately 0.44 g.
How many grams of H2O are needed to produce 150 g of Mg(OH)2?
To find the amount of water needed, we first calculate the molar mass of Mg(OH)2. Mg has a molar mass of 24.31 g/mol, O has 16.00 g/mol, and H has 1.01 g/mol. So, the molar mass of Mg(OH)2 is 24.31 + 2(16.00) + 2(1.01) = 58.33 g/mol. To produce 150 g of Mg(OH)2, we need 150 g / 58.33 g/mol = 2.57 moles of Mg(OH)2. Since there are 2 moles of H2O per 1 mole of Mg(OH)2, we need 2.57 moles x 2 = 5.14 moles of H2O. Finally, converting moles to grams, we get 5.14 moles x 18.02 g/mol = 92.54 g of H2O required.
How many moles are in 14.84 g Mg?
14,84 g magnesium are equivalent to 0,61 moles.
How many moles are in 97.5 g of oxygen?
97,5 g of oxygen is equal to 5,416 moles.
How many moles are in 978 g Ca?
978 g calcium contain 24,4 moles.
How many moles are in 67.4 g of HCI?
67,4 g HCl is equivalent to 1,85 moles.
How many moles are in 29.0 g of calcium?
29,0 g of calcium is equal to 0,723 moles.
