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3.00 moles of NO2 have a mass of?
The molar mass of NO2 is 46.01 g/mol. Therefore, 3.00 moles of NO2 have a mass of 138.03 grams (3.00 moles x 46.01 g/mol).
4NH3 7O2 4NO2 6H2O how many grams of oxygen are necessary to produce 4.50 moles of NO2?
To determine the grams of oxygen needed to produce 4.50 moles of NO2, use the coefficients in the balanced equation. In this case, 7 moles of O2 are required to produce 4 moles of NO2. Calculate: (4.50 moles of NO2) * (7 moles of O2 / 4 moles of NO2) = 7.88 moles of O2. Finally, convert moles to grams using the molar mass of O2 (32.00 g/mol): 7.88 moles * 32.00 g/mol = 252.16 grams of O2.
How many moles of molecules are in 25.5g of NO2?
Determine the molar mass of NO2 using the subscripts in the formula and the atomic weights in grams from the periodic table. 1 mole NO2 = (1 x 14.0067g N) + (2 x 15.9994g O) = 46.0055g NO2 Calculate the moles NO2 by dividing the given mass by the molar mass. 25.5g NO2 x (1mol NO2/46.0055g NO2) = 0.554mol NO2
How many molecules are in 25.0 g NO2?
To find the number of molecules in 25.0 g of NO2, you can start by converting the mass to moles using the molar mass of NO2. Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
How many moles are in 21.4 mg of nitrogen dioxide?
To find the number of moles, you need to first convert 21.4 mg of nitrogen dioxide to grams by dividing by 1000 (since 1 gram = 1000 mg). Then, calculate the moles using the molar mass of nitrogen dioxide (NO2), which is 46.01 g/mol. 21.4 mg is equal to 0.0214 grams. Dividing 0.0214 g by the molar mass of NO2 gives you approximately 0.00047 moles of nitrogen dioxide.
4) How many moles are in 1.18 g of NO2?
To find the number of moles in 1.18 g of NO2, you need to divide the given mass by the molar mass of NO2. The molar mass of NO2 is approximately 46 g/mol. So, 1.18 g / 46 g/mol = roughly 0.026 moles of NO2.
How many moles are in 19 g of NO2?
To find the number of moles in 19 g of NO2, we first need to determine the molar mass of NO2, which is 46.01 g/mol. Next, we divide the given mass by the molar mass: 19 g / 46.01 g/mol ≈ 0.413 moles of NO2.
how many moles of NO2 are in 7.4 mol N2O5?
N2O5(g) → 4NO2(g) + O2(g)
3.00 moles of NO2 have a mass of?
The molar mass of NO2 is 46.01 g/mol. Therefore, 3.00 moles of NO2 have a mass of 138.03 grams (3.00 moles x 46.01 g/mol).
How many moles are there in 10.0 of nitrogen dioxide?
To find the number of moles in 10.0 g of nitrogen dioxide (NO2), you first need to find the molar mass of NO2, which is approximately 46.01 g/mol. Then, divide the given mass by the molar mass to get the number of moles. In this case, 10.0 g / 46.01 g/mol ≈ 0.22 moles of nitrogen dioxide.
4NH3 7O2 4NO2 6H2O how many grams of oxygen are necessary to produce 4.50 moles of NO2?
To determine the grams of oxygen needed to produce 4.50 moles of NO2, use the coefficients in the balanced equation. In this case, 7 moles of O2 are required to produce 4 moles of NO2. Calculate: (4.50 moles of NO2) * (7 moles of O2 / 4 moles of NO2) = 7.88 moles of O2. Finally, convert moles to grams using the molar mass of O2 (32.00 g/mol): 7.88 moles * 32.00 g/mol = 252.16 grams of O2.
How many moles of molecules are in 25.5g of NO2?
Determine the molar mass of NO2 using the subscripts in the formula and the atomic weights in grams from the periodic table. 1 mole NO2 = (1 x 14.0067g N) + (2 x 15.9994g O) = 46.0055g NO2 Calculate the moles NO2 by dividing the given mass by the molar mass. 25.5g NO2 x (1mol NO2/46.0055g NO2) = 0.554mol NO2
How many molecules are in 25.0 g NO2?
To find the number of molecules in 25.0 g of NO2, you can start by converting the mass to moles using the molar mass of NO2. Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
How many molecules are in 19.6 g of NO2?
To determine the number of molecules in 19.6 g of NO2, you first need to calculate the number of moles in the sample. Then, you can use Avogadro's number (6.022 x 10^23 molecules per mole) to convert moles to molecules.
How many moles of NO2 can be produced given 1.35 moles of nitrogen monoxide?
The reaction to form nitrogen dioxide using nitric oxide is; 2NO(g) + O2(g) -> 2NO2(g) As the stoichiometry between the substances are 1:1, 1.35 moles of nitrogen monoxide is needed.
How many grams are there in 4.50 moles of barium nitrite?
To convert moles to grams, multiply the number of moles by the molar mass of the compound. The molar mass of barium nitrite (Ba(NO2)2) can be calculated as: 1Ba + 2(NO2) = 137.33 + 2(46.01) = 229.35 g/mol. So, 4.50 moles of barium nitrite would be 4.50 moles x 229.35 g/mol = 1032.08 grams of barium nitrite.
What is the mass of 99.01of NO2 at STP?
To find the mass of 99.01 moles of NO2 at STP (Standard Temperature and Pressure), you can use the ideal gas law. At STP, one mole of any gas occupies 22.4 L, so 99.01 moles of NO2 would occupy 99.01 x 22.4 = 2219.02 L. Using the molar mass of NO2 (46.01 g/mol), you can calculate the mass by multiplying the number of moles by the molar mass. So, 99.01 moles x 46.01 g/mol = 4546.46 grams.
