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N2O5(g) → 4NO2(g) + O2(g)
Queenie Botsford
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4) How many moles are in 1.18 g of NO2?
Molar mass NO2 = 46.0 g/mole1.18 g NO2 x 1 mol NO2/46.0 g = 0.0257 moles NO2 (to 3 significant figures)
How much would two moles of dinitrogen pentoxide weigh?
The chemical formula of dinitrogen pentoxide is N2O5 . We can calculate its molar mass (mass of one mole) by multiplying the subscript of each element by its molar mass (atomic weight on the periodic table in grams/mole) and adding them together.Molar mass N2O5 =(2 x 14 g/mol N) + (5 x 16 g/mol O) = 108 g/mol N2O5The mass of two moles of N2O5 is (2 x 108 g/mol N2O5 ) = 216 g
How many molecules are present in 1296 g of dinitrogen pentoxide?
Ar of N = 14g/mol Ar of O = 16g/mol Mr of N2O5 = 2(14)+5(16) = 108g/mol Using the formula : number of moles = mass / Mr number of moles = 1296g / 108g/mol = 12mol Each mole of substance contains 6.02 x 10^23 particles, therefore 1296g of N2O5 contains 12 x 6.02 x 10^23 = 7.224 x 10^24 molecules.
How many molecules are present in 1296 g of dinitrogen pentoxide (N2O5)?
1296 g N2O5 x 1 mol N2O5/108 g x 6.02x10^23 molecules/mole = 7.22x10^24 molecules
How many mol of H are in 4.51 mol H2O?
4,51 moles hydrogen exist.
4) How many moles are in 1.18 g of NO2?
Molar mass NO2 = 46.0 g/mole1.18 g NO2 x 1 mol NO2/46.0 g = 0.0257 moles NO2 (to 3 significant figures)
According to the following balanced reaction how many moles of NO are formed from 8.44 moles of NO2 if there is plenty of water present?
Balanced equation. 3NO2 + H2O -> 2HNO3 + NO 8.44 moles NO2 (1 mole NO/3 moles NO2) = 2.81 moles NO formed
How much would two moles of dinitrogen pentoxide weigh?
The chemical formula of dinitrogen pentoxide is N2O5 . We can calculate its molar mass (mass of one mole) by multiplying the subscript of each element by its molar mass (atomic weight on the periodic table in grams/mole) and adding them together.Molar mass N2O5 =(2 x 14 g/mol N) + (5 x 16 g/mol O) = 108 g/mol N2O5The mass of two moles of N2O5 is (2 x 108 g/mol N2O5 ) = 216 g
How many molecules are in 0.400 mol N2O5?
2.41X1023 Molecules
How many molecules are present in 1296 g of dinitrogen pentoxide?
Ar of N = 14g/mol Ar of O = 16g/mol Mr of N2O5 = 2(14)+5(16) = 108g/mol Using the formula : number of moles = mass / Mr number of moles = 1296g / 108g/mol = 12mol Each mole of substance contains 6.02 x 10^23 particles, therefore 1296g of N2O5 contains 12 x 6.02 x 10^23 = 7.224 x 10^24 molecules.
How many moles of no2 are present in 138.08?
Assuming you mean 138.08 grams, you set up a direct proportion between the molar mass of NO2 and your given mass. NO2 comes in at 46g/mol (14+16+16), and your proportion should be 46/1=138.08/x. Solve for x to get approx. 3 moles.
How many moles of N 2 reacted if 0.50 mol of NH 3 is produced?
First make the reaction equation balanced for N-atoms (co-existant in both formula)N2O5 + H2O --> 2 HNO3So 1.02 mole HNO3 is produced from:1.02 x 1 (N per HNO3) / 2 (N per N2O5) = 0.51 mol N2O5
How many moles of nitric oxide NO can be produced from the decomposition of 4 moles of N2O2Cl2?
Answer: 8 mol NO First, you start by writing the decomposition of N2O2CL2: N2O2Cl2=> 2NO +Cl2 (in reality, we should expect NO2 or N2 and O2 to be products in place of NO, but we'll assume the problem given expects this decomposition) Then, using stochiometry: 4 mol N2O2Cl2 * 2 mol NO/1 mol N2O2Cl2= 8 mol NO
How many molecules are present in 1296 g of dinitrogen pentoxide (N2O5)?
1296 g N2O5 x 1 mol N2O5/108 g x 6.02x10^23 molecules/mole = 7.22x10^24 molecules
How many moles of CO2 are produced when 2.1 mol of C2H2 react?
How many moles of CO2 are produced when 2.1 mol of C2H2 react?
How many mol of H are in 4.51 mol H2O?
4,51 moles hydrogen exist.
How many moles of NaCl are in 737 g of NaCl?
mol = mass/Mr mol = 737/ 58.44 moles of NaCl = 12.61
