Molar mass NO2 = 46.0 g/mole
1.18 g NO2 x 1 mol NO2/46.0 g = 0.0257 moles NO2 (to 3 significant figures)
Since 14 (4+10) moles of P4O10 contains 4 moles of Phosphorus, 8 moles of P4O10 will contain :: (8 x 4)/14 = 2.286 moles of Phosphorus
The empirical formula of stannic nitrite is Sn(NO2)4.
The balanced chemical equation for the reaction NH3 + NO2 -> N2O + H2O is: 4 NH3 + 4 NO2 -> 3 N2O + 6 H2O
Since oxygen is diatomic it requires 2 moles of oxygen.
4 moles of oxygen atoms are present in 4 moles of H2O
To determine the grams of oxygen needed to produce 4.50 moles of NO2, use the coefficients in the balanced equation. In this case, 7 moles of O2 are required to produce 4 moles of NO2. Calculate: (4.50 moles of NO2) * (7 moles of O2 / 4 moles of NO2) = 7.88 moles of O2. Finally, convert moles to grams using the molar mass of O2 (32.00 g/mol): 7.88 moles * 32.00 g/mol = 252.16 grams of O2.
To find the number of molecules in 25.0 g of NO2, you can start by converting the mass to moles using the molar mass of NO2. Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
To find the number of moles, you need to first convert 21.4 mg of nitrogen dioxide to grams by dividing by 1000 (since 1 gram = 1000 mg). Then, calculate the moles using the molar mass of nitrogen dioxide (NO2), which is 46.01 g/mol. 21.4 mg is equal to 0.0214 grams. Dividing 0.0214 g by the molar mass of NO2 gives you approximately 0.00047 moles of nitrogen dioxide.
Answer: 8 mol NO First, you start by writing the decomposition of N2O2CL2: N2O2Cl2=> 2NO +Cl2 (in reality, we should expect NO2 or N2 and O2 to be products in place of NO, but we'll assume the problem given expects this decomposition) Then, using stochiometry: 4 mol N2O2Cl2 * 2 mol NO/1 mol N2O2Cl2= 8 mol NO
Roughly 4 moles.
2 moles of Ca and 4 moles of OH
4 moles also 2 moles of oxygen will be consumed
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Since 14 (4+10) moles of P4O10 contains 4 moles of Phosphorus, 8 moles of P4O10 will contain :: (8 x 4)/14 = 2.286 moles of Phosphorus
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When 4 moles of aluminum react with an excess of chlorine gas, 4 moles of aluminum chloride are produced. This is because the balanced chemical equation for the reaction is: 2Al + 3Cl2 -> 2AlCl3 This means that 2 moles of aluminum react with 3 moles of chlorine gas to produce 2 moles of aluminum chloride, so 4 moles of aluminum will produce 4 moles of aluminum chloride.
The mole ratio of N2O5 to H2O depends on the balanced chemical equation for the reaction in which N2O5 decomposes or reacts. For example, in the decomposition of N2O5 into nitrogen dioxide (NO2) and water (H2O), the balanced equation is: 2 N2O5 → 4 NO2 + 2 H2O. In this case, the mole ratio of N2O5 to H2O is 1:1, as 2 moles of N2O5 produce 2 moles of H2O.