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How many mol of p are in 96 mol of p4o10?
There are 24 mol of P atoms in 96 mol of P4O10. This is because each P4O10 molecule contains 4 P atoms, so you need to divide the total moles of P4O10 by 4 to find the moles of P atoms.
How many molecules of tetraphosphorus decoxide contain 29.6g of phosphorus atoms?
Since tetraphosphorus decaoxide has the formula P4O10, it contains 4 phosphorus atoms per molecule. The molar mass of P4O10 is 284.09 g/mol. To find the number of moles of phosphorus atoms in 29.6g, divide the mass by the molar mass, then multiply by Avogadro's number (6.022 x 10^23) to get the number of molecules.
How many atoms of phosphorus are in 7.6 moles of copper phosphate?
There are 4 phosphorus atoms in one molecule of copper phosphate (Cu3(PO4)2). Therefore, in 7.6 moles of copper phosphate, there would be 7.6 moles x 4 atoms = 30.4 moles of phosphorus atoms.
How many atoms are there in 7.52 moles of Phosphorus?
There are 4.54 x 10^24 atoms in 7.52 moles of Phosphorus because 1 mole of Phosphorus contains 6.022 x 10^23 atoms. Multiplying this by the number of moles gives the total number of atoms in 7.52 moles.
How many atoms are in 3 moles of phosphorus?
Simple. 3 * 6.022 X 10^23 = 1.81 X 10^24 atoms of P
How many moles of oxygen are in one mole of P4O10?
There are 10 moles of oxygen in one mole of P4O10. This is because each molecule of P4O10 contains 4 phosphorus atoms and 10 oxygen atoms.
How many moles of phosphorus are in a 73.5 mol solution of P4O10?
There are 73.5 moles of P4O10 per kg of solution. Each P4O10 molecule weighs approximately 283.88 g. P makes up 123.88 or about 77.43% of this. 73.5 moles of P4O10 weighs about 20865.18 g. 77.43% of 20865.18g is 16155.91 g. Multiply this by the inverse of the molar mass of P (30.97g /mol) and your answer should be approximately 521.66 moles of P.
How many mol of p are in 96 mol of p4o10?
There are 24 mol of P atoms in 96 mol of P4O10. This is because each P4O10 molecule contains 4 P atoms, so you need to divide the total moles of P4O10 by 4 to find the moles of P atoms.
How many molecules of tetraphosphorus decoxide contain 29.6g of phosphorus atoms?
Since tetraphosphorus decaoxide has the formula P4O10, it contains 4 phosphorus atoms per molecule. The molar mass of P4O10 is 284.09 g/mol. To find the number of moles of phosphorus atoms in 29.6g, divide the mass by the molar mass, then multiply by Avogadro's number (6.022 x 10^23) to get the number of molecules.
How many atoms of phosphorus are present in 3.65 moles of phosphorus triiodide?
There are 2.21 x 10^24 atoms of phosphorus in 3.65 moles of phosphorus triiodide.
How many moles are 1.20x1025 atoms of phosphorus?
To convert atoms to moles, you divide by Avogadro's number, which is approximately 6.022 x 10^23. Therefore, 1.20x10^25 atoms of phosphorus is equal to 20 moles of phosphorus.
How many atoms of phosphorus are in 7.6 moles of copper phosphate?
There are 4 phosphorus atoms in one molecule of copper phosphate (Cu3(PO4)2). Therefore, in 7.6 moles of copper phosphate, there would be 7.6 moles x 4 atoms = 30.4 moles of phosphorus atoms.
How many atoms are there in 7.52 moles of Phosphorus?
There are 4.54 x 10^24 atoms in 7.52 moles of Phosphorus because 1 mole of Phosphorus contains 6.022 x 10^23 atoms. Multiplying this by the number of moles gives the total number of atoms in 7.52 moles.
How many moles of phosphorus atoms are in 100 grams of P4S10?
To find the number of moles of phosphorus atoms in 100 grams of P4S10, we first need to determine the molar mass of P4S10 which is 284.26 g/mol. Next, we calculate the number of moles of P4S10 in 100 grams by dividing 100 g by the molar mass to get 0.352 moles of P4S10. Since there are 4 phosphorus atoms in each P4S10 molecule, there are 0.352 moles x 4 = 1.41 moles of phosphorus atoms in 100 grams of P4S10.
How many atoms are in 3 moles of phosphorus?
Simple. 3 * 6.022 X 10^23 = 1.81 X 10^24 atoms of P
How many atoms of phosphorus are contained in 5.26 moles of ba3(po3)2?
There are 1 atom of phosphorus in each formula unit of Ba3(PO3)2. One formula unit of Ba3(PO3)2 contains 2 moles of phosphorus. Therefore, in 5.26 moles of Ba3(PO3)2, there are 5.26 x 2 = 10.52 moles of phosphorus, which is equivalent to 10.52 x 6.022 x 10^23 atoms.
How many moles of phosphorus atoms are in a 100 g sample of phosphorus?
The gram atomic mass of phosphorus is 30.9738, and by definition, a mole of such atoms contains Avogadro's Number of atoms. Therefore, 100 g of phosphorus contains 100/30.9738 or 3.23 moles, to the justified number of significant digits.
