There are 4 phosphorus atoms in one molecule of copper phosphate (Cu3(PO4)2). Therefore, in 7.6 moles of copper phosphate, there would be 7.6 moles x 4 atoms = 30.4 moles of phosphorus atoms.
Because copper (II) cations have a charge of +2 and phosphate anions have a charge of -3, the formula of anhydrous* copper (II) phosphate is Cu3(PO4)2. This shows that each formula unit contains 2 atoms of phosphorus. Therefore, the atoms of phosphorus in 4.8 formula units is 4.8 x Avogadro's Number, or about 2.9 X 1024 atoms, to the justified number of significant digits. ____________________________________ The answer to the problem will be the same if hydrated copper (II) phosphate is assumed, because the water of hydration contains no phosphorus and the quantity is specified in moles or formula units, but the formula would be different.
Since 14 (4+10) moles of P4O10 contains 4 moles of Phosphorus, 8 moles of P4O10 will contain :: (8 x 4)/14 = 2.286 moles of Phosphorus
There are 4.54 x 10^24 atoms in 7.52 moles of Phosphorus because 1 mole of Phosphorus contains 6.022 x 10^23 atoms. Multiplying this by the number of moles gives the total number of atoms in 7.52 moles.
One mol of copper is 6.02 x1023 atoms. So 3.44 x 1023 would be 0.571 moles.
There are 1 atom of phosphorus in each formula unit of Ba3(PO3)2. One formula unit of Ba3(PO3)2 contains 2 moles of phosphorus. Therefore, in 5.26 moles of Ba3(PO3)2, there are 5.26 x 2 = 10.52 moles of phosphorus, which is equivalent to 10.52 x 6.022 x 10^23 atoms.
Because copper (II) cations have a charge of +2 and phosphate anions have a charge of -3, the formula of anhydrous* copper (II) phosphate is Cu3(PO4)2. This shows that each formula unit contains 2 atoms of phosphorus. Therefore, the atoms of phosphorus in 4.8 formula units is 4.8 x Avogadro's Number, or about 2.9 X 1024 atoms, to the justified number of significant digits. ____________________________________ The answer to the problem will be the same if hydrated copper (II) phosphate is assumed, because the water of hydration contains no phosphorus and the quantity is specified in moles or formula units, but the formula would be different.
Since 14 (4+10) moles of P4O10 contains 4 moles of Phosphorus, 8 moles of P4O10 will contain :: (8 x 4)/14 = 2.286 moles of Phosphorus
Phosphorus pentachloride is the chemical name for the molecular formula of PCl5. At Standard Temperature and Pressure (STP) one mole corresponds to Avogadro's number of 6.02x10^23 particles. Using molar ratios we know that for every 1 mole of PCl5 we have 1 mole of P. a ratio of 1:1. Answering this question therefore is multiplying our given quantity of 2.97 moles by 6.02x10^23 yielding out answer of 1.79x10^24 atoms.
There are 2.21 x 10^24 atoms of phosphorus in 3.65 moles of phosphorus triiodide.
To find the number of atoms of barium in 68.2 g of barium phosphate, you first need to calculate the moles of barium in 68.2 g of barium phosphate using the molar mass of barium phosphate. Then, you can use Avogadro's number to convert moles of barium to atoms of barium.
There are 7.05 moles of oxygen atoms in 2.35 moles of sodium phosphate, as there are 3 oxygen atoms in each formula unit of sodium phosphate (Na3PO4).
To convert atoms to moles, you divide by Avogadro's number, which is approximately 6.022 x 10^23. Therefore, 1.20x10^25 atoms of phosphorus is equal to 20 moles of phosphorus.
To find the number of moles of copper atoms, divide the number of copper atoms by Avogadro's number (6.022 x 10^23). Therefore, for 1.2 x 10^48 copper atoms, the number of moles is 1.99 x 10^24 moles.
There are 4.54 x 10^24 atoms in 7.52 moles of Phosphorus because 1 mole of Phosphorus contains 6.022 x 10^23 atoms. Multiplying this by the number of moles gives the total number of atoms in 7.52 moles.
To find the number of moles of phosphorus atoms in 100 grams of P4S10, we first need to determine the molar mass of P4S10 which is 284.26 g/mol. Next, we calculate the number of moles of P4S10 in 100 grams by dividing 100 g by the molar mass to get 0.352 moles of P4S10. Since there are 4 phosphorus atoms in each P4S10 molecule, there are 0.352 moles x 4 = 1.41 moles of phosphorus atoms in 100 grams of P4S10.
3CuCl2 (aq)+ 2Na3PO4 (aq)> 6Na+ (aq)+ 6Cl- (aq)+ Cu3(PO4)2 (s) Or, 3 moles of copper (II) chloride and 2 moles of sodium phosphate form 6 moles of sodium ions, 6 moles of chloride ions, and a mole of copper (II) phosphate, which is insoluble, and precipitates out of the solution.
One mol of copper is 6.02 x1023 atoms. So 3.44 x 1023 would be 0.571 moles.