The number of phosphorus atoms is 63,181.10e23.
Since 14 (4+10) moles of P4O10 contains 4 moles of Phosphorus, 8 moles of P4O10 will contain :: (8 x 4)/14 = 2.286 moles of Phosphorus
There are 4 phosphorus atoms in one molecule of copper phosphate (Cu3(PO4)2). Therefore, in 7.6 moles of copper phosphate, there would be 7.6 moles x 4 atoms = 30.4 moles of phosphorus atoms.
To calculate the number of phosphorus atoms in 158 kg of phosphorus, we first need to determine the number of moles of phosphorus in 158 kg using the molar mass of phosphorus. Then we can use Avogadro's number (6.022 x 10^23 atoms per mole) to convert moles of phosphorus to atoms. The final calculation will give us the total number of phosphorus atoms in 158 kg.
There are 4.54 x 10^24 atoms in 7.52 moles of Phosphorus because 1 mole of Phosphorus contains 6.022 x 10^23 atoms. Multiplying this by the number of moles gives the total number of atoms in 7.52 moles.
Simple. 3 * 6.022 X 10^23 = 1.81 X 10^24 atoms of P
Since 14 (4+10) moles of P4O10 contains 4 moles of Phosphorus, 8 moles of P4O10 will contain :: (8 x 4)/14 = 2.286 moles of Phosphorus
There are 2.21 x 10^24 atoms of phosphorus in 3.65 moles of phosphorus triiodide.
There are 4 phosphorus atoms in one molecule of copper phosphate (Cu3(PO4)2). Therefore, in 7.6 moles of copper phosphate, there would be 7.6 moles x 4 atoms = 30.4 moles of phosphorus atoms.
To convert atoms to moles, you divide by Avogadro's number, which is approximately 6.022 x 10^23. Therefore, 1.20x10^25 atoms of phosphorus is equal to 20 moles of phosphorus.
To calculate the number of phosphorus atoms in 158 kg of phosphorus, we first need to determine the number of moles of phosphorus in 158 kg using the molar mass of phosphorus. Then we can use Avogadro's number (6.022 x 10^23 atoms per mole) to convert moles of phosphorus to atoms. The final calculation will give us the total number of phosphorus atoms in 158 kg.
5,26 moles of oxygen contain 31,676.10e23 atoms.
Two moles of neon contain 12,044281714.10e23 atoms.
There are 4.54 x 10^24 atoms in 7.52 moles of Phosphorus because 1 mole of Phosphorus contains 6.022 x 10^23 atoms. Multiplying this by the number of moles gives the total number of atoms in 7.52 moles.
To find the number of moles of phosphorus atoms in 100 grams of P4S10, we first need to determine the molar mass of P4S10 which is 284.26 g/mol. Next, we calculate the number of moles of P4S10 in 100 grams by dividing 100 g by the molar mass to get 0.352 moles of P4S10. Since there are 4 phosphorus atoms in each P4S10 molecule, there are 0.352 moles x 4 = 1.41 moles of phosphorus atoms in 100 grams of P4S10.
The gram atomic mass of phosphorus is 30.9738, and by definition, a mole of such atoms contains Avogadro's Number of atoms. Therefore, 100 g of phosphorus contains 100/30.9738 or 3.23 moles, to the justified number of significant digits.
Simple. 3 * 6.022 X 10^23 = 1.81 X 10^24 atoms of P
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