The gram Atomic Mass of phosphorus is 30.9738, and by definition, a mole of such atoms contains Avogadro's Number of atoms. Therefore, 100 g of phosphorus contains 100/30.9738 or 3.23 moles, to the justified number of significant digits.
it is 20456678
there are 0.675moles
4.00
To answer this you must first be given the mass of the sample or at least percentage and molecular formula that phosphorus is in
1
1.12 x 10^22 atoms PFirst determine the number of moles in the 0.577 g sample of phosphorus, determine the number of moles in the sample. Then multiply the moles by 6.022x10^23 atoms/mol.0.577 g P x (1 mol P/30.974 g P) x (6.022x10^23 atoms P/1 mol P) = 1.12 x 10^22 atoms P
it is 20456678
there are 0.675moles
The number of phosphorus atoms is 63,181.10e23.
Since 14 (4+10) moles of P4O10 contains 4 moles of Phosphorus, 8 moles of P4O10 will contain :: (8 x 4)/14 = 2.286 moles of Phosphorus
4.00
To answer this you must first be given the mass of the sample or at least percentage and molecular formula that phosphorus is in
0.5 moles.
10.08 moles (there are six carbon atoms per molecule of C6H6, hence, six times the number of moles of carbon can be produced).
There are 2.49 x 10^-12 moles of lead in that sample.
Simple. 3 * 6.022 X 10^23 = 1.81 X 10^24 atoms of P
A sample of 3,2x10 atoms of nickel is equal to 0,53.10e-23 moles.