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How many atoms of phosphorus are present in 3.65 moles of phosphorus triiodide?
There are 2.21 x 10^24 atoms of phosphorus in 3.65 moles of phosphorus triiodide.
How many moles of phosphorus atoms are in 100 grams of P4S10?
To find the number of moles of phosphorus atoms in 100 grams of P4S10, we first need to determine the molar mass of P4S10 which is 284.26 g/mol. Next, we calculate the number of moles of P4S10 in 100 grams by dividing 100 g by the molar mass to get 0.352 moles of P4S10. Since there are 4 phosphorus atoms in each P4S10 molecule, there are 0.352 moles x 4 = 1.41 moles of phosphorus atoms in 100 grams of P4S10.
How many moles of phosphorus atoms are in a 100 g sample of phosphorus?
The gram atomic mass of phosphorus is 30.9738, and by definition, a mole of such atoms contains Avogadro's Number of atoms. Therefore, 100 g of phosphorus contains 100/30.9738 or 3.23 moles, to the justified number of significant digits.
How many moles of oxygen are in one mole of P4O10?
There are 10 moles of oxygen in one mole of P4O10. This is because each molecule of P4O10 contains 4 phosphorus atoms and 10 oxygen atoms.
1.50 moles of h3po4 have how many atoms of p?
each mol of h3po4 has 6.022*10^23 molecules you have 1.5 mol, so 1.5 * 6.022*10^23 molecules = 9.033*10^23 molecules each molecule of h3po4 has 1 atom of p, so you have 9.033*10^23 atoms p.
How many atoms of phosphorus are present in 3.65 moles of phosphorus triiodide?
There are 2.21 x 10^24 atoms of phosphorus in 3.65 moles of phosphorus triiodide.
How many moles of phosphorus atoms are there in 8 moles of P4O10?
Since 14 (4+10) moles of P4O10 contains 4 moles of Phosphorus, 8 moles of P4O10 will contain :: (8 x 4)/14 = 2.286 moles of Phosphorus
How many atoms of phosphorus are in 7.6 moles of copper phosphate?
There are 4 phosphorus atoms in one molecule of copper phosphate (Cu3(PO4)2). Therefore, in 7.6 moles of copper phosphate, there would be 7.6 moles x 4 atoms = 30.4 moles of phosphorus atoms.
How many atoms are there in 7.52 moles of Phosphorus?
There are 4.54 x 10^24 atoms in 7.52 moles of Phosphorus because 1 mole of Phosphorus contains 6.022 x 10^23 atoms. Multiplying this by the number of moles gives the total number of atoms in 7.52 moles.
How many moles of phosphorus atoms are in 100 grams of P4S10?
To find the number of moles of phosphorus atoms in 100 grams of P4S10, we first need to determine the molar mass of P4S10 which is 284.26 g/mol. Next, we calculate the number of moles of P4S10 in 100 grams by dividing 100 g by the molar mass to get 0.352 moles of P4S10. Since there are 4 phosphorus atoms in each P4S10 molecule, there are 0.352 moles x 4 = 1.41 moles of phosphorus atoms in 100 grams of P4S10.
How many atoms are in 3 moles of phosphorus?
Simple. 3 * 6.022 X 10^23 = 1.81 X 10^24 atoms of P
How many atoms of phosphorus are contained in 5.26 moles of ba3(po3)2?
There are 1 atom of phosphorus in each formula unit of Ba3(PO3)2. One formula unit of Ba3(PO3)2 contains 2 moles of phosphorus. Therefore, in 5.26 moles of Ba3(PO3)2, there are 5.26 x 2 = 10.52 moles of phosphorus, which is equivalent to 10.52 x 6.022 x 10^23 atoms.
How many moles of phosphorus atoms are in a 100 g sample of phosphorus?
The gram atomic mass of phosphorus is 30.9738, and by definition, a mole of such atoms contains Avogadro's Number of atoms. Therefore, 100 g of phosphorus contains 100/30.9738 or 3.23 moles, to the justified number of significant digits.
How many atoms are in 5.22 g of phosporous?
To find the number of atoms in 5.22 g of phosphorus, you first need to determine the number of moles of phosphorus by dividing the given mass by the molar mass of phosphorus (31.0 g/mol). From there, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
How many moles of oxygen are in one mole of P4O10?
There are 10 moles of oxygen in one mole of P4O10. This is because each molecule of P4O10 contains 4 phosphorus atoms and 10 oxygen atoms.
How many phosphorus atoms are contained in 158 kg of phosphorus?
To calculate the number of phosphorus atoms in 158 kg of phosphorus, we first need to determine the number of moles of phosphorus in 158 kg using the molar mass of phosphorus. Then we can use Avogadro's number (6.022 x 10^23 atoms per mole) to convert moles of phosphorus to atoms. The final calculation will give us the total number of phosphorus atoms in 158 kg.
How many moles are 1.25 and times 10 25 atoms of phosphorous?
Oh honey, let me break it down for you. Avogadro's number tells us that 1 mole is equal to 6.022 x 10^23 atoms. So, to find out how many moles are in 1.25 x 10^25 atoms of phosphorus, you just need to divide the number of atoms by Avogadro's number. That gives you approximately 20.75 moles of phosphorus.
