0
What else can I help you with?
How many moles are in 2.3 grams of phosphorus using avogadro's number?
2.3 grams P (1mole P/30.97 grams) = 0.07427 moles Phosphorous 0.07427 moles P * 6.022 X 10^23 = 4.5 X 10^22 atoms of P in 2.3 grams P 4.5 X 10^22/6.022 X10^23 = 0.07427 moles of atoms in 2.3 grams of phosphorous
How many atoms of phosphorus are present in 3.65 moles of phosphorus triiodide?
There are 2.21 x 10^24 atoms of phosphorus in 3.65 moles of phosphorus triiodide.
How many moles are 1.20x1025 atoms of phosphorus?
To convert atoms to moles, you divide by Avogadro's number, which is approximately 6.022 x 10^23. Therefore, 1.20x10^25 atoms of phosphorus is equal to 20 moles of phosphorus.
How many moles in 2.3 grams of phosphorus?
mole = mass/molar mass mass=2.3 grams molar mass=30.97 2.3/30.97=0.0742 moles
How many moles of phosphorus atoms are in a 100 g sample of phosphorus?
The gram atomic mass of phosphorus is 30.9738, and by definition, a mole of such atoms contains Avogadro's Number of atoms. Therefore, 100 g of phosphorus contains 100/30.9738 or 3.23 moles, to the justified number of significant digits.
How many moles are in 2.3 grams of phosphorus using avogadro's number?
2.3 grams P (1mole P/30.97 grams) = 0.07427 moles Phosphorous 0.07427 moles P * 6.022 X 10^23 = 4.5 X 10^22 atoms of P in 2.3 grams P 4.5 X 10^22/6.022 X10^23 = 0.07427 moles of atoms in 2.3 grams of phosphorous
How many moles of phosphorus atoms are there in 8 moles of P4O10?
Since 14 (4+10) moles of P4O10 contains 4 moles of Phosphorus, 8 moles of P4O10 will contain :: (8 x 4)/14 = 2.286 moles of Phosphorus
How many atoms of phosphorus are present in 3.65 moles of phosphorus triiodide?
There are 2.21 x 10^24 atoms of phosphorus in 3.65 moles of phosphorus triiodide.
How many atoms of phosphorus are in 7.6 moles of copper phosphate?
There are 4 phosphorus atoms in one molecule of copper phosphate (Cu3(PO4)2). Therefore, in 7.6 moles of copper phosphate, there would be 7.6 moles x 4 atoms = 30.4 moles of phosphorus atoms.
How many moles are 1.20x1025 atoms of phosphorus?
To convert atoms to moles, you divide by Avogadro's number, which is approximately 6.022 x 10^23. Therefore, 1.20x10^25 atoms of phosphorus is equal to 20 moles of phosphorus.
How many moles of phosphorus are in 392 grams of phosphorus?
Quite a few! 392 grams phosphorous (1 mole P/30.97 grams) = 12.7 moles phosphorous ===================
How many phosphorus atoms does it take to equal 30.973 grams?
To determine the number of phosphorus atoms in 30.973 grams, you would first convert the mass to moles using the molar mass of phosphorus (30.973 g/mol). Then, you would use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of phosphorus atoms, which would be 30.973 grams / 30.973 g/mol * 6.022 x 10^23 atoms/mol.
How many atoms are there in 5.10 grams of Phosphorus?
There are 5.10 grams of Phosphorus, which has a molar mass of approximately 30.97 g/mol. This would be approximately 0.165 moles of Phosphorus. There are approximately 6.022 x 10^23 atoms in a mole, so 5.10 grams of Phosphorus would contain approximately 9.92 x 10^22 atoms.
How many grams of phosphorus trichloride are present in 3.42 moles of this compound?
3,42 moles of phosphorus trichloride have 469,6686 g.
How to convert grams to atoms?
To convert grams into atoms, you have to convert them into moles first. Get the molar mass and multiply it by the number of moles to get the atoms.
How many moles in 2.3 grams of phosphorus?
mole = mass/molar mass mass=2.3 grams molar mass=30.97 2.3/30.97=0.0742 moles
How many grams of phosphorus are present in 4.70 moles of tetraphosphorus decaoxide?
4,70 moles of tetraphosphorus decaoxide contain 582,56 g phosphorus.
