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How many moles are in 2.3 grams of phosphorus using avogadro's number?
Wiki User
∙ 13y ago
2.3 grams P (1mole P/30.97 grams)
= 0.07427 moles Phosphorous
0.07427 moles P * 6.022 X 10^23
= 4.5 X 10^22 atoms of P in 2.3 grams P
4.5 X 10^22/6.022 X10^23
= 0.07427 moles of atoms in 2.3 grams of phosphorous
Wiki User
∙ 13y ago
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How many moles of atoms are in 6.0221023 atoms Ne?
1. 6.022 X 1023 is Avogadros number (Avogadros constant) the number of atoms in a mole.
How many moles of phosphorus atoms are in 100 grams of P4S10?
4.00
How many moles in 2.3 grams of phosphorus?
mole = mass/molar mass mass=2.3 grams molar mass=30.97 2.3/30.97=0.0742 moles
How many moles of phosphorus atoms are in a 100 g sample of phosphorus?
The gram atomic mass of phosphorus is 30.9738, and by definition, a mole of such atoms contains Avogadro's Number of atoms. Therefore, 100 g of phosphorus contains 100/30.9738 or 3.23 moles, to the justified number of significant digits.
How many grams of fluorine are needed to react with 6.20 g of phosphorus?
Find number of moles of phosphorusmolar mass of phosphorus is 30.97g/moldivide mass by molar mass to get the moles of phosphorus please that your molar mass mast be multiplied by 4 because you have four phosphorus atoms. 30.97*4= 123.88 g/moln= m/M = 62.0g/123.88g/mol= 0.50 molesTheoretically, there are 6 times the number of moles in fluorine than there are in phosphorus because of the ratio 1:6 but fluorine is diatomic gas so we multiply the number of moles by 12 instead of 6. 6 from the ratio times from fluorine being diatomic gas.So 0.5*12=6 moles of fluorine. we multiply that by the molar mass of fluorine multiplied by 12 because we 12fluorine atoms.So, 6= m/228g/mol so to find mass of fluorine we multiply moles times molar mass it gives us 1368g.
How do you convert grams to moles using avogadros number?
You don't need to use Avogadro's number, you need the mass of the molecule in atomic units. Mass / molecular mass = moles eg for water, 36 grams / 18 atomic units = 2 moles
How do you convert atoms to grams with Avogadro's number?
divide the number of atoms by avogadros number (6.022*10^23), the resulting number is the number of moles you have. Multiply the number of moles of atoms by the molar mass (found on any periodic table) and the answer is how many grams of the substance you have.
How many moles of phosphorus are in 392 grams of phosphorus?
Quite a few! 392 grams phosphorous (1 mole P/30.97 grams) = 12.7 moles phosphorous ===================
How many moles of atoms are in 6.0221023 atoms Ne?
1. 6.022 X 1023 is Avogadros number (Avogadros constant) the number of atoms in a mole.
How many grams of phosphorus trichloride are present in 3.42 moles of this compound?
3,42 moles of phosphorus trichloride have 469,6686 g.
How many moles are in 2.3grams of phosphorus?
n=m/M so, the atomic number for Phosphorus is 30.973... we divide the atomic number by the amount of grams we have so n= 2.3/ 30.973= 0.07425822490556 = 0.14 mol.
How many grams of phosphorus are present in 4.70 moles of tetraphosphorus decaoxide?
4,70 moles of tetraphosphorus decaoxide contain 582,56 g phosphorus.
How many moles of phosphorus atoms are in 100 grams of P4S10?
4.00
How many moles in 2.3 grams of phosphorus?
mole = mass/molar mass mass=2.3 grams molar mass=30.97 2.3/30.97=0.0742 moles
The number of carbon atoms in 2.0 moles is?
The number of atoms in one mole is given by Avogadros number. This is: Avogadro's number = 6.0221415 × 1023 atomsTherefore, two moles of a substance contain 1.2044283 x 1024 atoms
What is moles of carbon?
6.02*10^23atoms (avogadros constant)
What is the number of moles in 32 grams of O2?
There are 1.0001 moles.
