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Avogadros number (approximately). The atomic weight of iron is 55.845. Avogadros number , the number of atoms in a mole of an element, or the number of molecules in a mole of a compound is 6.023 X 1023

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Q: How many atoms are there in 55.8 grams of Fe?
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How many atoms are present in 400g Iron?

1 mole Fe = 6.022 x 1023 atoms Fe1 mole Fe = 55.845g Fe (atomic weight in grams)Convert grams Fe to moles Fe.400g Fe x (1mol Fe/55.845g Fe) = 7.16mol FeConvert moles Fe to atoms Fe.7.16mol Fe x (6.022 x 1023atoms Fe/1mol Fe) = 4.31 x 1024 atoms Fe


How many atoms are in 13.2 grams of iron?

The conversion string. 13.2g Fe ( 1mol Fe/55.85g Fe ) ( 6.022 X 10^23/ 1mol Fe ) = 1.42 X 10^23 atoms


How many atoms are found in 600 grams of iron?

To find the number of atoms we need to find number of moles of Fe in 312.0 grams. Molar weight of Fe = 56 Number of moles of Fe in 312 grams = 312/56 =5.571 moles. 1 mole of Fe has Avogadro number of atoms. So 5.571 moles of Fe has atoms = 5.571 * Avogadro number. Avogadro number = 6.022 * 10^23 So total atoms = 5.571 * 6.022 * 10^23 = 33.548 * 10^23 * means multiply, ^ means raised to power.


How many atoms are in 10g of Fe?

Molar mass of iron = 55.845g/mol (atomic weight in grams/mol) 1mol Fe atoms = 6.022 x 1023 atoms Fe 10g Fe x 1mol/55.845g x 6.022 x 1023 atoms/mol = 1.078 x 1023 atoms


What number of Fe atoms and what amount of Fe atoms are in 500 g of Fe?

Known/Given:1 mole of Fe = 55.845g Fe (its atomic weight in grams)1 mole of Fe = 6.022 x 1023 atoms Fe (from Avogadro's number)Convert grams Fe to moles Fe.600.0g Fe x 1mol Fe/55.845g Fe = 10.74mol FeConvert moles Fe to atoms Fe.10.74mol Fe x 6.022 x 1023atoms Fe/1mol Fe = 6.468 x 1024atoms Fe


What is the mass of 5.0g of Fe how many atoms are present?

For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023.5.0 grams Fe / (55.9 grams) × (6.02 × 1023 atoms) = 5.38 × 1022 atoms


How many grams is a sample containing 2.71 x 1024 atoms of iron?

Amount of Fe = (2.71x1024)/(6.02x1023) = 4.50mol The atomic mass of Fe is 55.8 Mass of Fe = 4.50 x 55.8 = 251g


How many moles of iron is 5.98x1024 atoms of iron?

1 mole of atoms of any element is 6.022 x 1023 atoms. 1 mole of Fe = 6.022 x 1023 atoms Fe 5.98 x 1024 atoms Fe x (1mol Fe/6.022x1023 atoms Fe) = 9.93 moles Fe


How many atoms in 10 mg of iron?

10 milligrams iron (1 gram/1000 milligrams)(1 mole Fe/55.85 grams)(6.022 X 1023/1 mole Fe) = 1.1 X 1020 atoms of iron ===================


How many atoms are present in 4.80 moles of Fe?

4,80 moles of Fe contain 28,9062761136.10e23 atoms.


How many atoms are present in 4.80 mole of Fe?

4,80 moles of Fe contain 28,9062761136.10e23 atoms.


How many iron atoms are present in a 23.0 g iron block?

1 mole Fe = 55.845g Fe 1 mole Fe = 6.022 x 1023 atoms Fe 23.0g Fe x (1 mole Fe/55.845g Fe) x (6.022 x 1023 atoms Fe/1 mole Fe) = 2.40 x 1023 atoms Fe