Avogadros number (approximately). The atomic weight of iron is 55.845. Avogadros number , the number of atoms in a mole of an element, or the number of molecules in a mole of a compound is 6.023 X 1023
Amount of Fe = (2.71x1024)/(6.02x1023) = 4.50mol The atomic mass of Fe is 55.8 Mass of Fe = 4.50 x 55.8 = 251g
Fe, or iron, has a molar mass of 55.845 grams per mole. This means that 0.2 moles is equal to 11.2 grams of iron.
The number of particles (atoms or molecules) in a substance is known as Avogadro's constant and is 6.02 x 1023 particles per mole. The mole is the amount of a substance that contains the same number of particles as the number of atoms in 12 grams of carbon-12. If we consider uranium 238 as the largest isotopic component of natural uranium, and as it consists of atoms not molecules, then 1 kilogram contains 1000/238 moles (1000 grams the mass, 238 the relative atomic mass), ie 4.20 moles. so the number of atoms will be 4.20 x 6.02 x 1023, or 2.529 x 1024 atoms.
3.82 × 1024 Fe atoms
Amount of Fe = 55.845/55.845 = 1mol There is 1 mol of Fe in a 55.845g sample. 1 mol of Fe contains 6.02 x 1023 atoms (avogadro constant). Therefore there are 6.02 x 1023 atoms in 55.845g of iron.
1 mole Fe = 6.022 x 1023 atoms Fe1 mole Fe = 55.845g Fe (atomic weight in grams)Convert grams Fe to moles Fe.400g Fe x (1mol Fe/55.845g Fe) = 7.16mol FeConvert moles Fe to atoms Fe.7.16mol Fe x (6.022 x 1023atoms Fe/1mol Fe) = 4.31 x 1024 atoms Fe
The conversion string. 13.2g Fe ( 1mol Fe/55.85g Fe ) ( 6.022 X 10^23/ 1mol Fe ) = 1.42 X 10^23 atoms
To find the number of atoms we need to find number of moles of Fe in 312.0 grams. Molar weight of Fe = 56 Number of moles of Fe in 312 grams = 312/56 =5.571 moles. 1 mole of Fe has Avogadro number of atoms. So 5.571 moles of Fe has atoms = 5.571 * Avogadro number. Avogadro number = 6.022 * 10^23 So total atoms = 5.571 * 6.022 * 10^23 = 33.548 * 10^23 * means multiply, ^ means raised to power.
Molar mass of iron = 55.845g/mol (atomic weight in grams/mol) 1mol Fe atoms = 6.022 x 1023 atoms Fe 10g Fe x 1mol/55.845g x 6.022 x 1023 atoms/mol = 1.078 x 1023 atoms
Known/Given:1 mole of Fe = 55.845g Fe (its atomic weight in grams)1 mole of Fe = 6.022 x 1023 atoms Fe (from Avogadro's number)Convert grams Fe to moles Fe.600.0g Fe x 1mol Fe/55.845g Fe = 10.74mol FeConvert moles Fe to atoms Fe.10.74mol Fe x 6.022 x 1023atoms Fe/1mol Fe = 6.468 x 1024atoms Fe
For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023.5.0 grams Fe / (55.9 grams) × (6.02 × 1023 atoms) = 5.38 × 1022 atoms
Amount of Fe = (2.71x1024)/(6.02x1023) = 4.50mol The atomic mass of Fe is 55.8 Mass of Fe = 4.50 x 55.8 = 251g
1 mole of atoms of any element is 6.022 x 1023 atoms. 1 mole of Fe = 6.022 x 1023 atoms Fe 5.98 x 1024 atoms Fe x (1mol Fe/6.022x1023 atoms Fe) = 9.93 moles Fe
10 milligrams iron (1 gram/1000 milligrams)(1 mole Fe/55.85 grams)(6.022 X 1023/1 mole Fe) = 1.1 X 1020 atoms of iron ===================
4,80 moles of Fe contain 28,9062761136.10e23 atoms.
4,80 moles of Fe contain 28,9062761136.10e23 atoms.
1 mole Fe = 55.845g Fe 1 mole Fe = 6.022 x 1023 atoms Fe 23.0g Fe x (1 mole Fe/55.845g Fe) x (6.022 x 1023 atoms Fe/1 mole Fe) = 2.40 x 1023 atoms Fe