Amount of Fe = (2.71x1024)/(6.02x1023) = 4.50mol
The Atomic Mass of Fe is 55.8
Mass of Fe = 4.50 x 55.8 = 251g
251.33 grams of iron.
251 grams
251.33
Li atomic mass= 6.941g/mol= 4.9 moles of Li1.00 mol = 6.02 x 1023 atoms4.9 mol Li = 2.95 x 1024 atoms= 3.0 x 1024 atoms
Quite a few! 147 grams calcium (1 mole Ca/40.08 grams)(6.022 X 1023/1 mole Ca) = 2.21 X 1024 atoms of calcium ----------------------------------------
Avogadro's Number, 6.022 x 1023 gives the number of atoms in one mole. Calcium has an average atomic weight of 40.08 gmol-1 So one mole weighs 40.08 grams. 115 grams of Calcium will have (6.022 x 1023 / 40.08)*115 = 1.73 x 1024 atoms.
118.7 is close to the 118.96 grams per mole (mass) of tin. So we can call that one mole. 1 mole is equal to 6.022x10^23 (avogadro's number which is the number of atoms per mole of an element).
450.3915Calcium Carbonate (CaCO3) has a molar mass of 100.087 g/mol.4.5 mol * 100.087 g/mol = 450.3915 (because the mol's cancel leaving you with grams)
341 grams scandium (1 mole Sc/44.96 grams)(6.022 X 1023/1 mole Sc) = 4.57 X 1024 atoms of scandium =====================
1 mole C = 6.022 x 1023 atoms 2.408 x 1024 atoms C x 1mol/6.022 x 1023 atoms = 3.999 moles C
2.3 X 1024 atoms / 6.022 X 1023 atoms/mole X 107.87 gm/mole of silver = 412 grams
There are 3.275 moles of calcium in 131 grams as relative atomic mass of calcium is 40. Therefore there are 1.972 x 1024 atoms.
1.88 X 1024 molecules SO3 (1 mole SO3/6.022 X 1023)(80.07 grams/1 mole SO3) = 250 grams sulfur trioxide ===================
Li atomic mass= 6.941g/mol= 4.9 moles of Li1.00 mol = 6.02 x 1023 atoms4.9 mol Li = 2.95 x 1024 atoms= 3.0 x 1024 atoms
31.8 grams carbon (1 mole C/12.01 grams)(6.022 X 1023/1 mole C)= 1.59 X 1024 atoms of carbon===================
Quite a few! 170 grams ammonia (1 mole NH3/17.034 grams)(6.022 X 1023/1 mole NH3) = 6.01 X 1024 atoms of ammonia ========================
The atomic weight of Li is 6.941 g/mol The mass of the sample is 55.2 g This means that: 55.2/6.941=7.95 moles (rounded number) Multiplying this with Avogadro's number (6.022*1023) 7.95*6.022*1023=4.79*1024 atoms. There you have your answer.
Fairly heavy! 1.14 X 1024 atoms of iodine ( 1 mole I/6.022 X 1023)(126.9 grams/1 mole I) = 240 grams of iodine -------------------------------
64 grams sulfur (1 mole S/32.07 grams)(6.022 X 1023/1 mole S) = 1.2 X 1024 atoms of sulfur ====================
4.0 moles Cu (6.022 X 1023/1 mole Cu) = 2.4 X 1024 atoms of copper ====================