450.3915
Calcium Carbonate (CaCO3) has a molar mass of 100.087 g/mol.
4.5 mol * 100.087 g/mol = 450.3915 (because the mol's cancel leaving you with grams)
1 mole CaCO3 (3 mole O/1 mole CaCO3) = 3 moles oxygen
A mole of H2 molecules contains 6.023 x 10^(23) H2 molecules or 2 moles of H atoms (since each molecules has 2 atoms). A mole of CaCO3 (calcium carbonate) has one mole (Avogadro number) of Ca atoms, one mole of C atoms and 3 moles of O atoms.
To find the number of atoms in 195 grams of calcium, you first need to calculate the number of moles of calcium using its molar mass. Calcium's molar mass is 40.08 g/mol, so there are 195g / 40.08 g/mol = 4.86 moles of calcium. Finally, one mole of calcium contains 6.022 x 10^23 atoms, so 4.86 moles x 6.022 x 10^23 atoms/mole = 2.95 x 10^24 atoms of calcium in 195 grams.
The formula given shows that each formula unit or mole contains one calcium atom; therefore, 2.5 moles of calcium chloride contains 2.5 moles of calcium atoms.
Well, Ca has an atomic mass of 40, so one mole of Ca (6.022x1023 atoms) equals 40g.To get 5kg of Ca, you would times the 40g (one mole) by 125.5kg of Ca has 125x(6.022x1023), or602200000000000000000000 atoms.
The number of atoms is 1,50553521.10e23.
1 mole CaCO3 (3 mole O/1 mole CaCO3) = 3 moles oxygen
One mole of calcium contains Avogadro's number of atoms, which is approximately 6.022 x 10^23 atoms.
There are 6.023 x 10^23 atoms in each mole of calcium. I mole of calcium is 40 g, so 1 g contains 6.023 x 10^23/40 atoms = 1.506 x 10^24
A mole of H2 molecules contains 6.023 x 10^(23) H2 molecules or 2 moles of H atoms (since each molecules has 2 atoms). A mole of CaCO3 (calcium carbonate) has one mole (Avogadro number) of Ca atoms, one mole of C atoms and 3 moles of O atoms.
The total number of atoms contained in a 1,00 mole sample of helium is 6,022 140 857.10e23.
To find the number of atoms in 175 grams of calcium, you first need to calculate the number of moles of calcium using its atomic weight. Then, use Avogadro's number (6.022 x 10^23 atoms per mole) to convert moles to atoms.
There are approximately 1 mole of calcium in 40 g, as the molar mass of calcium is about 40 g/mol.
First you need to find how many moles of calcium that is. Since 1 mole of calcium is 40.078g you need to divide 60.8g by how much is one mole (60.8 / 40.078 = 1.517 moles). Once you know how many moles you have (1.517) you can find how many particles there are. There are 6.02 *10^23 atoms in one mole (Avagadro's number), so your final answer will be, 6.02*10^23 x 1.517 = 9.132 * 10^23
0.50 moles CaCO3 (1 mole Ca/1 mole CaCO3)(6.022 X 1023/1 mole Ca)= 3.0 X 1023 atoms of calcium===================
Neon molecule is mono-atomic. 20.18 g (1 mole) of neon will have 6.023 x 1023 atoms of neon
To find the number of atoms in 195 grams of calcium, you first need to calculate the number of moles of calcium using its molar mass. Calcium's molar mass is 40.08 g/mol, so there are 195g / 40.08 g/mol = 4.86 moles of calcium. Finally, one mole of calcium contains 6.022 x 10^23 atoms, so 4.86 moles x 6.022 x 10^23 atoms/mole = 2.95 x 10^24 atoms of calcium in 195 grams.