450.3915
Calcium Carbonate (CaCO3) has a molar mass of 100.087 g/mol.
4.5 mol * 100.087 g/mol = 450.3915 (because the mol's cancel leaving you with grams)
Grams = Moles * Molar Mass
Moles = 2.50
Molar Mass of Calcium =40.1 (Can be found on Periodic Table = Atomic Mass)
2.50 * 40.1 = 100.25 grams of Calcium
1mol of Ca contains 6.02 x 1023 atoms (avogadro constant).
Therefore 2.5mol of Ca contains 2.5 x 6.02 x 1023 = 1.51 x 1024 atoms.
129 grams calcium (1 mole Ca/40.08 grams calcium)(6.022 X 10^23calcium atoms/1 mole Ca) = 1.94 X 10^24 atoms of calcium
Quite a few! 147 grams calcium (1 mole Ca/40.08 grams)(6.022 X 1023/1 mole Ca) = 2.21 X 1024 atoms of calcium ----------------------------------------
7.92 grams calcium fluoride (1 mole CaF2/78.08 grams)(6.022 X 1023/1 mole CaF2) = 6.11 X 1022 atoms of calcium fluoride --------------------------------------------------
A mole of H2 molecules contains 6.023 x 10^(23) H2 molecules or 2 moles of H atoms (since each molecules has 2 atoms). A mole of CaCO3 (calcium carbonate) has one mole (Avogadro number) of Ca atoms, one mole of C atoms and 3 moles of O atoms.
The formula given shows that each formula unit or mole contains one calcium atom; therefore, 2.5 moles of calcium chloride contains 2.5 moles of calcium atoms.
The number of atoms is 1,50553521.10e23.
129 grams calcium (1 mole Ca/40.08 grams calcium)(6.022 X 10^23calcium atoms/1 mole Ca) = 1.94 X 10^24 atoms of calcium
Quite a few! 147 grams calcium (1 mole Ca/40.08 grams)(6.022 X 1023/1 mole Ca) = 2.21 X 1024 atoms of calcium ----------------------------------------
7.92 grams calcium fluoride (1 mole CaF2/78.08 grams)(6.022 X 1023/1 mole CaF2) = 6.11 X 1022 atoms of calcium fluoride --------------------------------------------------
There are 6.023 x 10^23 atoms in each mole of calcium. I mole of calcium is 40 g, so 1 g contains 6.023 x 10^23/40 atoms = 1.506 x 10^24
Quite a few! 175 grams calcium (1 mole Ca/40.08 grams)(6.022 X 10^23/1 mole Ca) = 2.63 X 10^24 atoms of calcium -------------------------------------------
A mole of H2 molecules contains 6.023 x 10^(23) H2 molecules or 2 moles of H atoms (since each molecules has 2 atoms). A mole of CaCO3 (calcium carbonate) has one mole (Avogadro number) of Ca atoms, one mole of C atoms and 3 moles of O atoms.
The total number of atoms contained in a 1,00 mole sample of helium is 6,022 140 857.10e23.
25.0 moles Ca x 6.02x10^23 atoms/mole = 1.50x10^25 atoms
3.6 moles hydrogen atoms (1 mole water/2 mole H)(6.022 X 1023/1 mole water molecules) = 1.1 X 1024 molecules of water =======================
The formula given shows that each formula unit or mole contains one calcium atom; therefore, 2.5 moles of calcium chloride contains 2.5 moles of calcium atoms.
0.50 moles CaCO3 (1 mole Ca/1 mole CaCO3)(6.022 X 1023/1 mole Ca)= 3.0 X 1023 atoms of calcium===================