.998 moles
To find the number of moles in 3.75 grams of calcium, divide the mass of calcium by its molar mass. The molar mass of calcium is approximately 40.08 g/mol. Therefore, 3.75 grams of calcium is equal to 0.0936 moles.
The chemical formula for the compound calcium chloride is CaCl2. The atomic mass of CaCl2 is 40.1 + 2(35.5) = 111.1Amount of CaCl2 = mass of pure sample/molar mass = 0.2/111.1 = 0.00180mol There are 0.00180 moles of CaCl2 in a 0.2 gram pure sample.
To find the number of atoms in 159g of calcium, you need to first calculate the number of moles of calcium present using the molar mass of calcium. The molar mass of calcium is approximately 40 g/mol. Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of calcium to atoms. Calculate the number of moles of calcium in 159g using the formula: moles = mass (g) / molar mass (g/mol). Finally, multiply the number of moles by Avogadro's number to determine the number of atoms in 159g of calcium.
In calcium carbonate, the molar mass is 100.1 g/mol. The molar mass of calcium is 40.08 g/mol. Therefore, the percentage of calcium in calcium carbonate is 40.08/100.1 * 100 = 40%. Thus, in 40 grams of calcium carbonate, there are 40% of calcium, which is equivalent to 40/40.08 = 0.997 moles of calcium. Since calcium forms 1+ ions, there are 0.997 * 6.022 * 10^23 = 6.02 * 10^23 ions of calcium present.
To calculate the number of atoms in a sample of calcium, you need to first determine the moles of calcium in 169 g. Then, you can use Avogadro's number (6.022 x 10^23 atoms per mole) to find the number of atoms. The atomic mass of calcium is 40.08 g/mol, so 169 g of calcium is approximately 4.22 moles. Multiplying this by Avogadro's number gives approximately 2.54 x 10^24 atoms in 169 g of calcium.
There are 5 moles of calcium in 200 grams of calcium. This calculation is based on the molar mass of calcium, which is approximately 40 grams per mole.
To find the number of moles in 3.75 grams of calcium, divide the mass of calcium by its molar mass. The molar mass of calcium is approximately 40.08 g/mol. Therefore, 3.75 grams of calcium is equal to 0.0936 moles.
The chemical formula for the compound calcium chloride is CaCl2. The atomic mass of CaCl2 is 40.1 + 2(35.5) = 111.1Amount of CaCl2 = mass of pure sample/molar mass = 0.2/111.1 = 0.00180mol There are 0.00180 moles of CaCl2 in a 0.2 gram pure sample.
To find the number of atoms in 159g of calcium, you need to first calculate the number of moles of calcium present using the molar mass of calcium. The molar mass of calcium is approximately 40 g/mol. Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of calcium to atoms. Calculate the number of moles of calcium in 159g using the formula: moles = mass (g) / molar mass (g/mol). Finally, multiply the number of moles by Avogadro's number to determine the number of atoms in 159g of calcium.
In calcium carbonate, the molar mass is 100.1 g/mol. The molar mass of calcium is 40.08 g/mol. Therefore, the percentage of calcium in calcium carbonate is 40.08/100.1 * 100 = 40%. Thus, in 40 grams of calcium carbonate, there are 40% of calcium, which is equivalent to 40/40.08 = 0.997 moles of calcium. Since calcium forms 1+ ions, there are 0.997 * 6.022 * 10^23 = 6.02 * 10^23 ions of calcium present.
40 g of Ca = 1 mole So 808 g of Ca = 20.2 mole
To calculate the number of atoms in a sample of calcium, you need to first determine the moles of calcium in 169 g. Then, you can use Avogadro's number (6.022 x 10^23 atoms per mole) to find the number of atoms. The atomic mass of calcium is 40.08 g/mol, so 169 g of calcium is approximately 4.22 moles. Multiplying this by Avogadro's number gives approximately 2.54 x 10^24 atoms in 169 g of calcium.
For this you need the atomic mass of Ca. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.40.0 grams Ca / (40.08 grams) = .998 moles Ca
To find the number of moles in 37 grams of calcium hydroxide, you need to divide the given mass by the molar mass of calcium hydroxide. The molar mass of calcium hydroxide (Ca(OH)2) is 74.1 g/mol. Therefore, 37 grams of calcium hydroxide is equal to 0.499 moles.
To find the number of moles in 9.8 grams of Calcium, you first need to calculate the molar mass of Calcium, which is about 40.08 g/mol. Then, divide the given mass by the molar mass: ( \frac{9.8 , \text{g}}{40.08 , \text{g/mol}} \approx 0.245 , \text{moles})
To determine the number of moles in 10.10 g of calcium carbonate, we first need to find the molar mass of CaCO3, which is 40.08 g/mol for calcium, 12.01 g/mol for carbon, and 16.00 g/mol for oxygen. Adding these up gives a molar mass of 100.09 g/mol for CaCO3. Dividing 10.10 g by the molar mass gives 0.101 moles of calcium carbonate.
To determine the number of moles of calcium atoms in 45.8 g of Ca, first find the molar mass of calcium (Ca) from the periodic table (40.08 g/mol). Then, divide the given mass by the molar mass of Ca to get the number of moles. In this case, 45.8 g of Ca is equal to 1.14 moles of Ca atoms.