First calculate the moles of Calcium
Moles(Ca) = 169g/ 40 (Atomic Mass)
moles(Ca) = 4.225 moles.
Remember the Avogdro No. which is the number of ato,ms/molecules in one mole.
Hence 6.022 x 10^*23) = 1 mole.
We have 4.225 moles So multiplying
4.225 X 6.022 x 10^(23) = 2.54 x 10^(24) atoms)
169 g of calcium contain 25,394.10e23 atoms.
149 g of calcium contain 22,39.10e23 atoms.
When calculating calcium you must first see how many moles are there. There are 2.6Ã?10^24 atoms in 173 grams of calcium.
175 g Ca (1 mol / 40.078 g) (6.022x10^23 atoms / 1 mol) = 2.63x10^24 Ca atoms There are 2.63x10^24 c.alcium atoms in 175 grams of calcium.
There are 6.023 x 10^23 atoms in each mole of calcium. I mole of calcium is 40 g, so 1 g contains 6.023 x 10^23/40 atoms = 1.506 x 10^24
(g) -> moles = x(g) * (1 mol/molar mass)Moles -> atoms = x(mol) * (6.022*10^23/1 mol)
149 g of calcium contain 22,39.10e23 atoms.
61,5 g calcium contain 9,241.10e23 atoms.
When calculating calcium you must first see how many moles are there. There are 2.6Ã?10^24 atoms in 173 grams of calcium.
175 g Ca (1 mol / 40.078 g) (6.022x10^23 atoms / 1 mol) = 2.63x10^24 Ca atoms There are 2.63x10^24 c.alcium atoms in 175 grams of calcium.
169 g C x 1 mole C/12.011 g x 6.02x10^23 atoms/mole = 8.47x10^24 atoms
There are 6.023 x 10^23 atoms in each mole of calcium. I mole of calcium is 40 g, so 1 g contains 6.023 x 10^23/40 atoms = 1.506 x 10^24
oxygen
Get off Wiki Answers Mrs. Z's chemistry class
The answer is 0,068 mol (for O not for O2).
Quite a few! 147 grams calcium (1 mole Ca/40.08 grams)(6.022 X 1023/1 mole Ca) = 2.21 X 1024 atoms of calcium ----------------------------------------
(g) -> moles = x(g) * (1 mol/molar mass)Moles -> atoms = x(mol) * (6.022*10^23/1 mol)
The gram atomic mass of calcium is 40.08. Therefore, 127 g of calcium constitutes 127/40.08 or 3.69 gram atomic masses. By definition of Avogadro's Number, each gram atomic mass contains Avogadro's Number of atoms. Therefore, the answer is 3.69 X Avogadro's Number or 1.91 X 1024 atoms, to the justified number of significant digits.