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Strictly, elements such as calcium do not have "moles", but the corresponding term, for Avogadro's Number of atoms of an element, is called "gram Atomic Mass". For calcium, this number is about 40.08 grams. Therefore, 9.8 grams of calcium is about 9.8/40.08 or 0.24 gram atoms, to the justified number of significant digits.

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9y ago
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12y ago

if my calculations are correct it should be 9g (mass) divided by 18 (RFM of H2O) = 0.5

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13y ago

You first need to know what element, or the molecular formula of the 9.8 grams consists of.

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11y ago

The molar mass of calcium is 40 g/mol. Therefore, 9.8 g of calcium is equivalent to 0.245 moles.

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14y ago

Molar mass of water:-18g

=> 18g contains 6.022*1023 molecules

=> 9g contains 6.022*1023 /2=3.011 *1023 molecules

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11y ago

18 moles of atomic hydrogen or 9 moles of molecular hydrogen is needed.

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7y ago

9,8 moles of calcium have 392,76 grams.

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15y ago

.391 moles of Na in NaCL

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13y ago

90/18 = 5 moles

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15y ago

1/2 mol

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Q: How many moles are in 9.8 grams of Calcium?
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