The weight of 2,5 mol of sulfuric acid is 245,1975 g.
The molar mass of sulfuric acid is 98.08 grams per mole. 4.09 x 98.09 = 401.1881 grams.
Grams NaOH?? Balanced equation. 2NaOH + H2SO4 --> Na2SO4 + 2H2O 4.9 grams H2SO4 (1 mole H2SO4/98.086 grams)(2 mole NaOH/1 mole H2SO4)(39.998 grams/1 mole NaOH) = 4.0 grams NaOH needed =================
To calculate the mass of H2SO4, you first find the moles of H2SO4 using the molarity formula (moles = molarity x volume). Then use the molar mass of H2SO4 (98.08 g/mol) to convert moles to grams. Given that the solution is 5.85 M, you would first calculate moles of H2SO4: 5.85 mol/L x 0.060 L = 0.351 mol. Then convert moles to grams: 0.351 mol x 98.08 g/mol ≈ 34.44 grams of H2SO4.
To determine the number of moles in 1g of H2SO4, you first need to calculate the molar mass of H2SO4. The molar mass of H2SO4 is approximately 98.08 g/mol. Therefore, 1g of H2SO4 is equal to 0.0102 moles (1g / 98.08 g/mol).
To calculate the mass of a substance in grams, you need to multiply the number of moles by the molar mass of the substance. The molar mass of H2SO4 (sulfuric acid) is approximately 98.08 g/mol. Therefore, the mass of 6.25 moles of H2SO4 would be 6.25 moles x 98.08 g/mol = 613 grams.
The molar mass of sulfuric acid is 98.08 grams per mole. 4.09 x 98.09 = 401.1881 grams.
Grams NaOH?? Balanced equation. 2NaOH + H2SO4 --> Na2SO4 + 2H2O 4.9 grams H2SO4 (1 mole H2SO4/98.086 grams)(2 mole NaOH/1 mole H2SO4)(39.998 grams/1 mole NaOH) = 4.0 grams NaOH needed =================
The balanced chemical equation for the reaction is 1 mol of sulfuric acid reacts with 2 mol of ammonium hydroxide. Therefore, for 8 mol of ammonium hydroxide, 4 mol of sulfuric acid are needed. To calculate the grams of sulfuric acid needed, you would multiply the number of moles by the molar mass of sulfuric acid.
To calculate the mass of H2SO4, you first find the moles of H2SO4 using the molarity formula (moles = molarity x volume). Then use the molar mass of H2SO4 (98.08 g/mol) to convert moles to grams. Given that the solution is 5.85 M, you would first calculate moles of H2SO4: 5.85 mol/L x 0.060 L = 0.351 mol. Then convert moles to grams: 0.351 mol x 98.08 g/mol ≈ 34.44 grams of H2SO4.
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4.25 grams. .050 M = .050 mol/1 L 5.0 L x .050 mol/L (cancel out L to get mol as a unit)= .25 mol Atomic mass of Ammonia (NH3)= 17 g/mol .25 mol x 17 g/mol (cancel out mol to get g as a unit)= 4.25 g
To determine the number of moles in 1g of H2SO4, you first need to calculate the molar mass of H2SO4. The molar mass of H2SO4 is approximately 98.08 g/mol. Therefore, 1g of H2SO4 is equal to 0.0102 moles (1g / 98.08 g/mol).
To calculate the mass of a substance in grams, you need to multiply the number of moles by the molar mass of the substance. The molar mass of H2SO4 (sulfuric acid) is approximately 98.08 g/mol. Therefore, the mass of 6.25 moles of H2SO4 would be 6.25 moles x 98.08 g/mol = 613 grams.
To convert moles to grams, you need to use the molar mass of the compound. The molar mass of H2SO4 is 98.08 g/mol. Therefore, 0.736 moles of H2SO4 is equal to 0.736 * 98.08 = 72.16 grams.
To find the mass of 3.60 moles of H2SO4, you first need to calculate the molar mass of H2SO4. The molar mass of H2SO4 is 98.08 g/mol. Multiply the molar mass by the number of moles to get the mass: 3.60 moles * 98.08 g/mol = 353.088 grams. Therefore, the mass of 3.60 moles of H2SO4 is 353.088 grams.
H2SO4 H= 1X2 = 2 S=32X1=32 O=16X4=64 TOTAL: 98 98x3= 294 GRAMS =))
The mass in grams of one mole H2SO4 is: 98.079 g/mol (molar mass)The mass in grams of one molecule H2SO4 is (molecule mass):98.079 (g/mol) / 6.02214*10+23(molecules/mol) = 16.286*10-23 g/molecule