Use the equation
mol = mass / RFM (or RAM)
mol = 37 / (40 + 16x2 + 1x2)
mol = 37 / 74
mol = 0.5
To neutralize calcium hydroxide, the molar ratio is 2:1 (2 moles of boric acid for every 1 mole of calcium hydroxide). Calculate the molar mass of boric acid (H3BO3) and calcium hydroxide (Ca(OH)2), then use these values to convert the mass of calcium hydroxide to moles and then to grams of boric acid.
The reaction between calcium carbide and water produces acetylene gas (C2H2) and calcium hydroxide (Ca(OH)2. When 1 mole of calcium carbide reacts with 2 moles of water, it produces 1 mole of acetylene and 1 mole of calcium hydroxide. The molar mass of calcium carbide is 64.1 g/mol, so the reaction would produce 26.04 grams of acetylene gas and 74.1 grams of calcium hydroxide from every 64.1 grams of calcium carbide reacted.
To determine the amount of calcium needed, you need to balance the chemical equation for the reaction between calcium and water. The equation is Ca + 2H2O → Ca(OH)2 + H2. Then, convert the mass of water to moles, use the stoichiometry of the balanced equation to find the moles of calcium required, and convert that to grams of calcium.
To determine the number of moles of calcium hydroxide needed to react with the nitric acid, you would need to know the concentration of the nitric acid. With the concentration, you can use the balanced chemical equation of the reaction to calculate the moles of calcium hydroxide required.
2,8 moles of calcium carbonate have 240,208 g.
To neutralize calcium hydroxide, the molar ratio is 2:1 (2 moles of boric acid for every 1 mole of calcium hydroxide). Calculate the molar mass of boric acid (H3BO3) and calcium hydroxide (Ca(OH)2), then use these values to convert the mass of calcium hydroxide to moles and then to grams of boric acid.
42,5 grams calcium is equivalent to 1,06 moles.
120 grams of calcium contain 2,994 moles.
To determine the grams of calcium sulfate formed from 130 grams of calcium hydroxide (Ca(OH)₂), we first need to calculate the moles of Ca(OH)₂. The molar mass of Ca(OH)₂ is approximately 74.09 g/mol, so 130 g corresponds to about 1.76 moles. The balanced chemical equation for the reaction with sulfuric acid (H₂SO₄) produces one mole of calcium sulfate (CaSO₄) for each mole of calcium hydroxide. Therefore, 1.76 moles of Ca(OH)₂ will yield 1.76 moles of CaSO₄, which is approximately 246.5 grams (using the molar mass of CaSO₄, about 136.14 g/mol).
7,68 grams of calcium nitride is equal to 0,052 moles.
There are 5 moles of calcium in 200 grams of calcium. This calculation is based on the molar mass of calcium, which is approximately 40 grams per mole.
3 moles of calcium is equivalent to 120,234 g.
0,27 moles of calcium contain 10,82 g calcium.
To find the number of moles in 5000 grams of calcium, you need to divide the given mass by the molar mass of calcium. The molar mass of calcium is approximately 40.08 g/mol. So, 5000 grams of calcium is equal to 5000/40.08 = 124.69 moles of calcium.
3.8 grams calcium (1 mole Ca/40.08 grams) = 0.09 moles calcium ==============
120 g calcium is equal to 3 moles.
The reaction between calcium carbide and water produces acetylene gas (C2H2) and calcium hydroxide (Ca(OH)2. When 1 mole of calcium carbide reacts with 2 moles of water, it produces 1 mole of acetylene and 1 mole of calcium hydroxide. The molar mass of calcium carbide is 64.1 g/mol, so the reaction would produce 26.04 grams of acetylene gas and 74.1 grams of calcium hydroxide from every 64.1 grams of calcium carbide reacted.